{"id":4286,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-integers-ex-1-4\/"},"modified":"2018-07-06T15:06:30","modified_gmt":"2018-07-06T09:36:30","slug":"ncert-solutions-for-class-7-maths-1-4","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/","title":{"rendered":"NCERT Solutions for Class 7 Maths 1.4"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#NCERT_Solutions_for_Class_7_Maths_Integers\" >NCERT Solutions for Class 7 Maths\u00a0Integers<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_1Evaluate_each_of_the_following\" >Question 1.Evaluate each of the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_2Verify_that_texa_div_left_b_c_right_ne_left_a_div_b_right_left_a_div_c_righttex_for_each_of_the_following_values_of_texabtex_and_texctex\" >Question 2.Verify that {tex}a \\div \\left( {b + c} \\right) \\ne \\left( {a \\div b} \\right) + \\left( {a \\div c} \\right){\/tex} for each of the following values of {tex}a,b{\/tex} and {tex}c.{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_3Fill_in_the_blanks\" >Question 3.Fill in the blanks:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_4Write_five_pairs_of_integers_texleft_ab_righttex_such_that_texa_div_b_%E2%80%93_3tex_One_such_pair_is_texleft_6_%E2%80%93_2_righttex_because_tex6_div_left_%E2%80%93_2_right_left_%E2%80%93_3_righttex\" >Question 4.Write five pairs of integers {tex}\\left( {a,b} \\right){\/tex} such that {tex}a \\div b = &#8211; 3.{\/tex} One such pair is {tex}\\left( {6, &#8211; 2} \\right){\/tex} because {tex}6 \\div \\left( { &#8211; 2} \\right) = \\left( { &#8211; 3} \\right).{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_5The_temperature_at_noon_was_10oC_above_zero_If_it_decreases_at_the_rate_of_2oC_per_hour_until_mid-night_at_what_time_would_the_temperature_be_8oC_below_zero_What_would_be_the_temperature_at_mid-night\" >Question 5.The temperature at noon was 10oC above zero. If it decreases at the rate of 2oC per hour until mid-night, at what time would the temperature be 8oC below zero? What would be the temperature at mid-night?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_6In_a_class_test_3_marks_are_given_for_every_correct_answer_and_texleft_%E2%80%93_2_righttex_marks_are_given_for_every_incorrect_answer_and_no_marks_for_not_attempting_any_question\" >Question 6.In a class test (+3) marks are given for every correct answer and {tex}\\left( { &#8211; 2} \\right){\/tex} marks are given for every incorrect answer and no marks for not attempting any question.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#Question_7An_elevator_descends_into_a_mine_shaft_at_the_rate_of_6_mmin_If_the_descent_starts_from_10_above_the_ground_level_how_long_will_it_take_to_reach_tex_%E2%80%93_350tex_m\" >Question 7.An elevator descends into a mine shaft at the rate of 6 m\/min. If the descent starts from 10 above the ground level, how long will it take to reach {tex} &#8211; 350{\/tex} m?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#NCERT_Solutions_for_Class_7_Maths_14\" >NCERT Solutions for Class 7 Maths 1.4<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths 1.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 7\u00a0Integers\u00a0Maths<\/strong><strong>\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics-integers\/1510\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths 1.4\" width=\"168\" height=\"213\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Integers\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Integers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p style=\"text-align: center;\"><strong>Class \u2013VII Mathematics (Ex. 1.4)<\/strong><\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Evaluate_each_of_the_following\"><\/span><strong>Question<\/strong> 1.Evaluate each of the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}\\left( { &#8211; 30} \\right) \\div 10{\/tex}<\/p>\n<p>(b) {tex}50 \\div \\left( { &#8211; 5} \\right){\/tex}<\/p>\n<p>(c) {tex}\\left( { &#8211; 36} \\right) \\div \\left( { &#8211; 9} \\right){\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 49} \\right) \\div 49{\/tex}<\/p>\n<p>(e) {tex}13 \\div \\left[ {\\left( { &#8211; 2} \\right) + 1} \\right]{\/tex}<\/p>\n<p>(f) {tex}0 \\div \\left( { &#8211; 12} \\right){\/tex}<\/p>\n<p>(g) {tex}\\left( { &#8211; 31} \\right) \\div \\left[ {\\left( { &#8211; 30} \\right) \\div \\left( { &#8211; 1} \\right)} \\right]{\/tex}<\/p>\n<p>(h) {tex}\\left[ {\\left( { &#8211; 36} \\right) \\div 12} \\right] \\div 3{\/tex}{tex}\\left( { &#8211; 206} \\right) \\div \\_\\_\\_\\_\\_\\_\\_ = 1{\/tex}<\/p>\n<p>(i) {tex}\\left[ {\\left( { &#8211; 6} \\right) + 5} \\right] \\div \\left[ {\\left( { &#8211; 2} \\right) + 1} \\right]{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}\\left( { &#8211; 30} \\right) \\div 10{\/tex} = {tex}\\left( { &#8211; 30} \\right) \\times \\frac{1}{{10}} = \\frac{{ &#8211; 30 \\times 1}}{{10}} = &#8211; 3{\/tex}<\/p>\n<p>(b) {tex}50 \\div \\left( { &#8211; 5} \\right){\/tex} = {tex}50 \\times \\left( {\\frac{{ &#8211; 1}}{5}} \\right) = \\frac{{50 \\times \\left( { &#8211; 1} \\right)}}{5} = &#8211; 10{\/tex}<\/p>\n<p>(c) {tex}\\left( { &#8211; 36} \\right) \\div \\left( { &#8211; 9} \\right){\/tex} = {tex}\\left( { &#8211; 36} \\right) \\times \\left( {\\frac{{ &#8211; 1}}{9}} \\right) = \\frac{{\\left( { &#8211; 36} \\right) \\times \\left( { &#8211; 1} \\right)}}{9} = \\frac{{36}}{9} = 4{\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 49} \\right) \\div 49{\/tex} = {tex}\\left( { &#8211; 49} \\right) \\times \\frac{1}{{49}} = \\frac{{ &#8211; 49}}{{49}} = &#8211; 1{\/tex}<\/p>\n<p>(e) {tex}13 \\div \\left[ {\\left( { &#8211; 2} \\right) + 1} \\right]{\/tex} = {tex}13 \\div \\left( { &#8211; 1} \\right) = 13 \\times \\left( {\\frac{{ &#8211; 1}}{1}} \\right) = &#8211; 13{\/tex}<\/p>\n<p>(f) {tex}0 \\div \\left( { &#8211; 12} \\right){\/tex} = {tex}0 \\times \\left( {\\frac{{ &#8211; 1}}{{12}}} \\right) = \\frac{0}{{12}} = 0{\/tex}<\/p>\n<p>(g) {tex}\\left( { &#8211; 31} \\right) \\div \\left[ {\\left( { &#8211; 30} \\right) \\div \\left( { &#8211; 1} \\right)} \\right]{\/tex} = {tex}\\left( { &#8211; 31} \\right) \\div \\left( { &#8211; 30 &#8211; 1} \\right) = \\left( { &#8211; 31} \\right) \\div \\left( { &#8211; 31} \\right) = \\left( { &#8211; 31} \\right) \\times \\left( {\\frac{{ &#8211; 1}}{{31}}} \\right) = \\frac{{31}}{{31}} = 1{\/tex}<\/p>\n<p>(h) {tex}\\left[ {\\left( { &#8211; 36} \\right) \\div 12} \\right] \\div 3{\/tex} = {tex}\\left[ {\\left( { &#8211; 36} \\right) \\times \\frac{1}{{12}}} \\right] \\times \\frac{1}{3} = \\left( {\\frac{{ &#8211; 36}}{{12}}} \\right) \\times \\frac{1}{3} = \\left( { &#8211; 3} \\right) \\times \\frac{1}{3} = \\frac{{ &#8211; 3}}{3} = &#8211; 1{\/tex}<\/p>\n<p>(i) {tex}\\left[ {\\left( { &#8211; 6} \\right) + 5} \\right] \\div \\left[ {\\left( { &#8211; 2} \\right) + 1} \\right]{\/tex} = {tex}\\left( { &#8211; 6 + 5} \\right) \\div \\left( { &#8211; 2 + 1} \\right) = \\left( { &#8211; 1} \\right) \\div \\left( { &#8211; 1} \\right) = \\left( { &#8211; 1} \\right) \\times \\frac{{\\left( { &#8211; 1} \\right)}}{1} = 1{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Verify_that_texa_div_left_b_c_right_ne_left_a_div_b_right_left_a_div_c_righttex_for_each_of_the_following_values_of_texabtex_and_texctex\"><\/span><strong>Question<\/strong> 2.Verify that {tex}a \\div \\left( {b + c} \\right) \\ne \\left( {a \\div b} \\right) + \\left( {a \\div c} \\right){\/tex} for each of the following values of {tex}a,b{\/tex} and {tex}c.{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}a = 12,b = &#8211; 4,c = 2{\/tex}<\/p>\n<p>(b) {tex}a = \\left( { &#8211; 10} \\right),b = 1,c = 1{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Given: {tex}a \\div \\left( {b + c} \\right) \\ne \\left( {a \\div b} \\right) + \\left( {a \\div c} \\right){\/tex}<\/p>\n<p>{tex}a = 12,b = &#8211; 4,c = 2{\/tex}<\/p>\n<p>Putting the given values in L.H.S. = {tex}12 \\div \\left( { &#8211; 4 + 2} \\right){\/tex}<\/p>\n<p>= {tex}12 \\div \\left( { &#8211; 2} \\right) = 12 \\div \\left( {\\frac{{ &#8211; 1}}{2}} \\right) = \\frac{{ &#8211; 12}}{2} = &#8211; 6{\/tex}<\/p>\n<p>Putting the given values in R.H.S. = {tex}\\left[ {12 \\div \\left( { &#8211; 4} \\right)} \\right] + \\left( {12 \\div 2} \\right){\/tex}<\/p>\n<p>= {tex}\\left( {12 \\times \\frac{{ &#8211; 1}}{4}} \\right) + 6 = &#8211; 3 + 6 = 3{\/tex}<\/p>\n<p>Since, L.H.S. {tex} \\ne {\/tex} R.H.S.<\/p>\n<p>Hence verified.<\/p>\n<p>(b) Given: {tex}a \\div \\left( {b + c} \\right) \\ne \\left( {a \\div b} \\right) + \\left( {a \\div c} \\right){\/tex}<\/p>\n<p>{tex}a = &#8211; 10,b = 1,c = 1{\/tex}<\/p>\n<p>Putting the given values in L.H.S. = {tex} &#8211; 10 \\div \\left( {1 + 1} \\right){\/tex}<\/p>\n<p>= {tex} &#8211; 10 \\div \\left( 2 \\right) = &#8211; 5{\/tex}<\/p>\n<p>Putting the given values in R.H.S. = {tex}\\left[ { &#8211; 10 \\div 1} \\right] + \\left( { &#8211; 10 \\div 1} \\right){\/tex}<\/p>\n<p>= {tex} &#8211; 10 &#8211; 10 = &#8211; 20{\/tex}<\/p>\n<p>Since, L.H.S. {tex} \\ne {\/tex} R.H.S.<\/p>\n<p>Hence verified.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Fill_in_the_blanks\"><\/span><strong>Question<\/strong> 3.Fill in the blanks:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}369 \\div \\_\\_\\_\\_\\_\\_\\_ = 369{\/tex}<\/p>\n<p>(b) {tex}\\left( { &#8211; 75} \\right) \\div \\_\\_\\_\\_\\_\\_\\_ = \\left( { &#8211; 1} \\right){\/tex}<\/p>\n<p>(c) {tex}\\left( -206 \\right)\\div \\_\\_\\_\\_\\_\\_\\_=1{\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 87} \\right) \\div \\_\\_\\_\\_\\_\\_\\_ = 87{\/tex}<\/p>\n<p>(e) {tex}\\_\\_\\_\\_\\_\\_\\_ \\div 1 = &#8211; 87{\/tex}<\/p>\n<p>(f) {tex}\\_\\_\\_\\_\\_\\_\\_ \\div 48 = &#8211; 1{\/tex}<\/p>\n<p>(g) {tex}20 \\div \\_\\_\\_\\_\\_\\_\\_ = &#8211; 2{\/tex}<\/p>\n<p>(h) {tex}\\_\\_\\_\\_\\_\\_\\_ \\div \\left( 4 \\right) = &#8211; 3{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}369 \\div \\underline 1 = 369{\/tex}<\/p>\n<p>(b) {tex}\\left( { &#8211; 75} \\right) \\div \\underline {75} = \\left( { &#8211; 1} \\right){\/tex}<\/p>\n<p>(c) {tex}\\left( { &#8211; 206} \\right) \\div \\underline {\\left( { &#8211; 206} \\right)} = 1{\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 87} \\right) \\div \\underline {\\left( { &#8211; 1} \\right)} = 87{\/tex}<\/p>\n<p>(e) {tex}\\underline {\\left( { &#8211; 87} \\right)} \\div 1 = &#8211; 87{\/tex}<\/p>\n<p>(f) {tex}\\underline {\\left( { &#8211; 48} \\right)} \\div 48 = &#8211; 1{\/tex}<\/p>\n<p>(g) {tex}20 \\div \\underline {\\left( { &#8211; 10} \\right)} = &#8211; 2{\/tex}<\/p>\n<p>(h) {tex}\\underline {\\left( { &#8211; 12} \\right)} \\div \\left( 4 \\right) = &#8211; 3{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Write_five_pairs_of_integers_texleft_ab_righttex_such_that_texa_div_b_%E2%80%93_3tex_One_such_pair_is_texleft_6_%E2%80%93_2_righttex_because_tex6_div_left_%E2%80%93_2_right_left_%E2%80%93_3_righttex\"><\/span><strong>Question<\/strong> 4.Write five pairs of integers {tex}\\left( {a,b} \\right){\/tex} such that {tex}a \\div b = &#8211; 3.{\/tex} One such pair is {tex}\\left( {6, &#8211; 2} \\right){\/tex} because {tex}6 \\div \\left( { &#8211; 2} \\right) = \\left( { &#8211; 3} \\right).{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\left( { &#8211; 6} \\right) \\div 2 = &#8211; 3{\/tex}<\/p>\n<p>(ii) {tex}9 \\div \\left( { &#8211; 3} \\right) = &#8211; 3{\/tex}<\/p>\n<p>(iii) {tex}12 \\div \\left( { &#8211; 4} \\right) = &#8211; 3{\/tex}<\/p>\n<p>(iv) {tex}\\left( { &#8211; 9} \\right) \\div 3 = &#8211; 3{\/tex}<\/p>\n<p>(v) {tex}\\left( { &#8211; 15} \\right) \\div 5 = &#8211; 3{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5The_temperature_at_noon_was_10oC_above_zero_If_it_decreases_at_the_rate_of_2oC_per_hour_until_mid-night_at_what_time_would_the_temperature_be_8oC_below_zero_What_would_be_the_temperature_at_mid-night\"><\/span><strong>Question<\/strong> 5.The temperature at noon was 10oC above zero. If it decreases at the rate of 2oC per hour until mid-night, at what time would the temperature be 8oC below zero? What would be the temperature at mid-night?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Following number line is representing the temperature:<\/p>\n<p>The temperature decreases 2oC = 1 hour<\/p>\n<p>The temperature decreases 1oC = {tex}\\frac{1}{2}{\/tex} hour<\/p>\n<p>The temperature decreases 18oC = {tex}\\frac{1}{2} \\times 18{\/tex} = 9 hours<\/p>\n<p>Total time = 12 noon + 9 hours = 21 hours = 9 pm<\/p>\n<p>Thus, at 9 pm the temperature would be 8oC below 0oC.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_6In_a_class_test_3_marks_are_given_for_every_correct_answer_and_texleft_%E2%80%93_2_righttex_marks_are_given_for_every_incorrect_answer_and_no_marks_for_not_attempting_any_question\"><\/span><strong>Question<\/strong> 6.In a class test (+3) marks are given for every correct answer and {tex}\\left( { &#8211; 2} \\right){\/tex} marks are given for every incorrect answer and no marks for not attempting any question.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i)Radhika scored 20 marks. If she has got 12 correct answers, how many questions has she attempted incorrectly?<\/p>\n<p>(ii)Mohini scores {tex}\\left( { &#8211; 5} \\right){\/tex} marks in this test, though she has got 7 correct answers. How many questions has she attempted incorrectlt?<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) Marks given for one correct answer = 3<\/p>\n<p>Marks given for 12 correct answers = 3 x 12 = 36<\/p>\n<p>Radhika scored 20 marks.<\/p>\n<p>Therefore, Marks obtained for incorrect answers = 20 \u2013 36 = \u201316<\/p>\n<p>Now, marks given for one incorrect answer = \u20132<\/p>\n<p>Therefore, number of incorrect answers = {tex}\\left( { &#8211; 16} \\right) \\div \\left( { &#8211; 2} \\right) = 8{\/tex}<\/p>\n<p>Thus, Radhika has attempted 8 incorrect questions.<\/p>\n<p>(ii) Marks given for seven correct answers = 3 x 7 = 21<\/p>\n<p>Mohini scores = \u20135<\/p>\n<p>Marks obtained for incorrect answers = = \u20135 \u2013 21 = \u201326<\/p>\n<p>Now, marks given for one incorrect answer = \u20132<\/p>\n<p>Therefore, number of incorrect answers = {tex}\\left( { &#8211; 26} \\right) \\div \\left( { &#8211; 2} \\right) = 13{\/tex}<\/p>\n<p>Thus, Mohini has attempted 13 incorrect questions.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths 1.4<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_7An_elevator_descends_into_a_mine_shaft_at_the_rate_of_6_mmin_If_the_descent_starts_from_10_above_the_ground_level_how_long_will_it_take_to_reach_tex_%E2%80%93_350tex_m\"><\/span><strong>Question 7.<\/strong>An elevator descends into a mine shaft at the rate of 6 m\/min. If the descent starts from 10 above the ground level, how long will it take to reach {tex} &#8211; 350{\/tex} m?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Starting position of mine shaft is 10 m above the ground but it moves in opposite direction so it travels the distance (\u2013350) m below the ground.<\/p>\n<p>So total distance covered by mine shaft = 10 m \u2013 (\u2013350) m = 10 + 350 = 360 m<\/p>\n<p>Now, time taken to cover a distance of 6 m by it = 1 minute<\/p>\n<p>So, time taken to cover a distance of 1 m by it = {tex}\\frac{1}{6}{\/tex} minute<\/p>\n<p>Therefore, time taken to cover a distance of 360 m = {tex}\\frac{1}{6} \\times 360{\/tex} = 60 minutes = 1 hour<\/p>\n<p>(Since 60 minutes = 1 hour)<\/p>\n<p>Thus, in one hour the mine shaft reaches \u2013350 below the ground.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_14\"><\/span>NCERT Solutions for Class 7 Maths 1.4<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths 1.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT &#8230; <a title=\"NCERT Solutions for Class 7 Maths 1.4\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-1-4\/\" aria-label=\"More on NCERT Solutions for Class 7 Maths 1.4\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1388,281],"tags":[283,1535,321,1485,216],"class_list":["post-4286","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-07","category-ncert-solutions","tag-cbse-study-material","tag-class-7","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 7 Maths 1.4 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 7 Maths 1.4 in PDF format for free download. 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