{"id":4285,"date":"2016-05-13T11:49:00","date_gmt":"2016-05-13T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-7-maths-integers-ex-1-3\/"},"modified":"2018-07-06T15:06:09","modified_gmt":"2018-07-06T09:36:09","slug":"ncert-solutions-for-class-7-maths-exercise-1-3","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/","title":{"rendered":"NCERT Solutions for Class 7 Maths Exercise 1.3"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#NCERT_Solutions_for_Class_7_Maths_Integers\" >NCERT Solutions for Class 7 Maths\u00a0Integers<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Class_%E2%80%93VII_Mathematics_Ex_13\" >Class \u2013VII Mathematics (Ex. 1.3)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_1Find_the_each_of_the_following_products\" >Question 1.Find the each of the following products:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_2Verify_the_following\" >Question 2.Verify the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_3\" >Question 3.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_4Starting_from_texleft_%E2%80%93_1_right_times_5tex_write_various_products_showing_some_patterns_to_show_texleft_%E2%80%93_1_right_times_left_%E2%80%93_1_right_1tex\" >Question 4.Starting from {tex}\\left( { &#8211; 1} \\right) \\times 5,{\/tex} write various products showing some patterns to show {tex}\\left( { &#8211; 1} \\right) \\times \\left( { &#8211; 1} \\right) = 1.{\/tex}<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_5Find_the_product_using_suitable_properties\" >Question 5.Find the product, using suitable properties:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_6A_certain_freezing_process_requires_that_room_temperature_be_lowered_from_40oC_at_the_rate_of_5oC_every_hour_What_will_be_the_room_temperature_10_hours_after_the_process_begins\" >Question 6.A certain freezing process requires that room temperature be low^ered from 40oC at the rate of 5oC every hour. What will be the room temperature 10 hours after the process begins?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_7In_a_class_test_containing_10_questions_5_marks_are_awarded_for_every_correct_answer_and_texleft_%E2%80%93_2_righttex_marks_are_awarded_for_every_incorrect_answer_and_0_for_questions_not_attempted\" >Question 7.In a class test containing 10 questions, 5 marks are awarded for e^very correct answer and {tex}\\left( { &#8211; 2} \\right){\/tex} marks are awarded for every incorrect answer and 0 for questions not attempted.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_8A_cement_company_earns_a_profit_of_Rs_8_per_bag_of_white_cement_sold_and_a_loss_of_Rs_5_per_bag_of_grey_cement_sold\" >Question 8.A cement company earns a profit of Rs. 8 per bag of white cement sold and a loss of Rs. 5 per bag of grey cement sold.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#Question_9Replace_the_blank_with_an_integer_to_make_it_a_true_statement\" >Question 9.Replace the blank with an integer to make it a true statement:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#NCERT_Solutions_for_Class_7_Maths_Exercise_13\" >NCERT Solutions for Class 7 Maths Exercise 1.3<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 7 Maths Exercise 1.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 7\u00a0Integers\u00a0Maths<\/strong><strong>\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-07-mathematics\/1509\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/07_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 7 Maths Exercise 1.3\" width=\"176\" height=\"223\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Integers\"><\/span>NCERT Solutions for Class 7 Maths\u00a0Integers<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VII_Mathematics_Ex_13\"><\/span><strong>Class \u2013VII Mathematics (Ex. 1.3)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Find_the_each_of_the_following_products\"><\/span><strong>Question<\/strong> 1.Find the each of the following products:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) 3 x (\u20131)<\/p>\n<p>(b) (\u20131) x 225<\/p>\n<p>(c) (\u201321) x (\u201330)<\/p>\n<p>(d) (\u2013316) x (\u20131)<\/p>\n<p>(e) (\u201315) x 0 x (\u201318)<\/p>\n<p>(f) (\u201312) x (\u201311) x (10)<\/p>\n<p>(g) 9 x (\u20133) x (\u20136)<\/p>\n<p>(h) (\u201318) x (\u20135) x (\u20134)<\/p>\n<p>(i) (\u20131) x (\u20132) x (\u20133) x 4<\/p>\n<p>(j) (\u20133) x (\u20136) x (2) x (\u20131)<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) 3 x (\u20131) = \u20133<\/p>\n<p>(b) (\u20131) x 225 = \u2013225<\/p>\n<p>(c) (\u201321) x (\u201330) = 630<\/p>\n<p>(d) (\u2013316) x (\u20131) = 316<\/p>\n<p>(e) (\u201315) x 0 x (\u201318) = 0<\/p>\n<p>(f) (\u201312) x (\u201311) x (10) = 132 x 10 = 1320<\/p>\n<p>(g) 9 x (\u20133) x (\u20136) = 9 x 18 = 162<\/p>\n<p>(h) (\u201318) x (\u20135) x (\u20134) = 90 x (\u20134) = \u2013360<\/p>\n<p>(i) (\u20131) x (\u20132) x (\u20133) x 4 = (\u20136 x 4) = \u201324<\/p>\n<p>(j) (\u20133) x (\u20136) x (2) x (\u20131) = (\u201318) x (\u20132) = 36<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Verify_the_following\"><\/span><strong>Question<\/strong> 2.Verify the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) 18 x [7 + (\u20133)] = [18 x 7] + [18 x (\u20133)]\n<p>(b) (\u201321) x [(\u20134) + (\u20136)] = [(\u201321) x (-4)] + [(\u201321) x (\u20136)]\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) 18 x [7 + (\u20133)] = [18 x 7] + [18 x (\u20133)]\n<p>{tex} \\Rightarrow {\/tex} 18 x 4 = 126 + (\u201354)<\/p>\n<p>{tex} \\Rightarrow {\/tex} 72 = 72<\/p>\n<p>{tex} \\Rightarrow {\/tex} L.H.S. = R.H.S. Hence verified.<\/p>\n<p>(b) (\u201321) x [(\u20134) + (\u20136)] = [(\u201321) x (\u20134)] + [(\u201321) x (\u20136)]\n<p>{tex} \\Rightarrow {\/tex} (\u201321) x (\u201310) = 84 + 126<\/p>\n<p>{tex} \\Rightarrow {\/tex} 210 = 210<\/p>\n<p>{tex} \\Rightarrow {\/tex} L.H.S. = R.H.S. Hence verified.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3\"><\/span><strong>Question<\/strong> 3.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i)For any integer {tex}a,{\/tex} what is {tex}\\left( { &#8211; 1} \\right) \\times a{\/tex} equal to?<\/p>\n<p>(ii)Determine the integer whose product with {tex}\\left( { &#8211; 1} \\right){\/tex} is:<\/p>\n<p>(a) \u201322<\/p>\n<p>(b) 37<\/p>\n<p>(c) 0<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) {tex}\\left( { &#8211; 1} \\right) \\times a = &#8211; a,{\/tex} where {tex}a{\/tex} is an integer.<\/p>\n<p>(ii) (a) {tex}\\left( { &#8211; 1} \\right) \\times \\left( { &#8211; 22} \\right) = 22{\/tex}<\/p>\n<p>(b) {tex}\\left( { &#8211; 1} \\right) \\times 37 = &#8211; 37{\/tex}<\/p>\n<p>(c) {tex}\\left( { &#8211; 1} \\right) \\times 0 = 0{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Starting_from_texleft_%E2%80%93_1_right_times_5tex_write_various_products_showing_some_patterns_to_show_texleft_%E2%80%93_1_right_times_left_%E2%80%93_1_right_1tex\"><\/span><strong>Question<\/strong> 4.Starting from {tex}\\left( { &#8211; 1} \\right) \\times 5,{\/tex} write various products showing some patterns to show {tex}\\left( { &#8211; 1} \\right) \\times \\left( { &#8211; 1} \\right) = 1.{\/tex}<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>{tex}\\left( { &#8211; 1} \\right) \\times 5 = &#8211; 5{\/tex} {tex}\\left( { &#8211; 1} \\right) \\times 4 = &#8211; 4{\/tex}<\/p>\n<p>{tex}\\left( { &#8211; 1} \\right) \\times 3 = &#8211; 3{\/tex} {tex}\\left( { &#8211; 1} \\right) \\times 2 = &#8211; 2{\/tex}<\/p>\n<p>{tex}\\left( { &#8211; 1} \\right) \\times 1 = &#8211; 1{\/tex} {tex}\\left( { &#8211; 1} \\right) \\times 0 = 0{\/tex}<\/p>\n<p>{tex}\\left( { &#8211; 1} \\right) \\times \\left( { &#8211; 1} \\right) = 1{\/tex}<\/p>\n<p>Thus, we can conclude that this pattern shows the product of one negative integer and one positive integer is negative integer whereas the product of two negative integers is a positive integer.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5Find_the_product_using_suitable_properties\"><\/span><strong>Question<\/strong> 5.Find the product, using suitable properties:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}26 \\times \\left( { &#8211; 48} \\right) + \\left( { &#8211; 48} \\right) \\times \\left( { &#8211; 36} \\right){\/tex}<\/p>\n<p>(b) {tex}8 \\times 53 \\times \\left( { &#8211; 125} \\right){\/tex}<\/p>\n<p>(c) {tex}15 \\times \\left( { &#8211; 25} \\right) \\times \\left( { &#8211; 4} \\right) \\times \\left( { &#8211; 10} \\right){\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 41} \\right) \\times \\left( {102} \\right){\/tex}<\/p>\n<p>(e) {tex}625 \\times \\left( { &#8211; 35} \\right) + \\left( { &#8211; 625} \\right) \\times 65{\/tex}<\/p>\n<p>(f) {tex}7 \\times \\left( {50 &#8211; 2} \\right){\/tex}<\/p>\n<p>(g) {tex}\\left( { &#8211; 17} \\right) \\times \\left( { &#8211; 29} \\right){\/tex}<\/p>\n<p>(h) {tex}\\left( { &#8211; 57} \\right) \\times \\left( { &#8211; 19} \\right) + 57{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}26 \\times \\left( { &#8211; 48} \\right) + \\left( { &#8211; 48} \\right) \\times \\left( { &#8211; 36} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\left( { &#8211; 48} \\right) \\times \\left[ {26 + \\left( { &#8211; 36} \\right)} \\right]{\/tex} [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} {tex}\\left( { &#8211; 48} \\right) \\times \\left( { &#8211; 10} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} 480<\/p>\n<p>(b) {tex}8 \\times 53 \\times \\left( { &#8211; 125} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}53 \\times \\left[ {8 \\times \\left( { &#8211; 125} \\right)} \\right]{\/tex} [Commutative property]\n<p>{tex} \\Rightarrow {\/tex} {tex}53 \\times \\left( { &#8211; 1000} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 53000{\/tex}<\/p>\n<p>(c) {tex}15 \\times \\left( { &#8211; 25} \\right) \\times \\left( { &#8211; 4} \\right) \\times \\left( { &#8211; 10} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}15 \\times \\left[ {\\left( { &#8211; 25} \\right) \\times \\left( { &#8211; 4} \\right) \\times \\left( { &#8211; 10} \\right)} \\right]{\/tex} [Commutative property]\n<p>{tex} \\Rightarrow {\/tex} {tex}15 \\times \\left( { &#8211; 1000} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 15000{\/tex}<\/p>\n<p>(d) {tex}\\left( { &#8211; 41} \\right) \\times \\left( {102} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 41 \\times \\left[ {100 + 2} \\right]{\/tex} [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} {tex}\\left[ {\\left( { &#8211; 41} \\right) \\times 100} \\right] + \\left[ {\\left( { &#8211; 41} \\right) \\times 2} \\right]{\/tex} {tex} \\Rightarrow {\/tex} {tex} &#8211; 4100 + \\left( { &#8211; 82} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 4182{\/tex}<\/p>\n<p>(e) {tex}625 \\times \\left( { &#8211; 35} \\right) + \\left( { &#8211; 625} \\right) \\times 65{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}625 \\times \\left[ {\\left( { &#8211; 35} \\right) + \\left( { &#8211; 65} \\right)} \\right]{\/tex} [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} {tex}625 \\times \\left( { &#8211; 100} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex} &#8211; 62500{\/tex}<\/p>\n<p>(f) {tex}7 \\times \\left( {50 &#8211; 2} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}7 \\times 50 &#8211; 7 \\times 2{\/tex} [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} {tex}350 &#8211; 14 = 336{\/tex}<\/p>\n<p>(g){tex}\\left( { &#8211; 17} \\right) \\times \\left( { &#8211; 29} \\right){\/tex}{tex} \\Rightarrow {\/tex}<\/p>\n<p>{tex}\\left( { &#8211; 17} \\right) \\times \\left[ {\\left( { &#8211; 30} \\right) + 1} \\right]{\/tex} [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} {tex}\\left( { &#8211; 17} \\right) \\times \\left( {30} \\right) + \\left( { &#8211; 17} \\right) \\times 1{\/tex} {tex} \\Rightarrow {\/tex} {tex}510 + \\left( { &#8211; 17} \\right){\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} 493<\/p>\n<p>(h){tex}\\left( { &#8211; 57} \\right) \\times \\left( { &#8211; 19} \\right) + 57{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\left( { &#8211; 57} \\right) \\times \\left( { &#8211; 19} \\right) + 57 \\times 1{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} 57 x 19 + 57 x 1<\/p>\n<p>{tex} \\Rightarrow {\/tex} 57 x (19 + 1) [Distributive property]\n<p>{tex} \\Rightarrow {\/tex} 57 x 20 = 1140<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_6A_certain_freezing_process_requires_that_room_temperature_be_lowered_from_40oC_at_the_rate_of_5oC_every_hour_What_will_be_the_room_temperature_10_hours_after_the_process_begins\"><\/span><strong>Question<\/strong> 6.A certain freezing process requires that room temperature be low^ered from 40oC at the rate of 5oC every hour. What will be the room temperature 10 hours after the process begins?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Given: Present room temperature = 40oC<\/p>\n<p>Decreasing the temperature every hour = 5oC<\/p>\n<p>Room temperature after 10 hours = 40oC + 10 x (\u20135oC )<\/p>\n<p>= 40oC \u2013 50oC<\/p>\n<p>= \u2013 10oC<\/p>\n<p>Thus, the room temperature after 10 hours is \u2013 10oC after the process begins.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_7In_a_class_test_containing_10_questions_5_marks_are_awarded_for_every_correct_answer_and_texleft_%E2%80%93_2_righttex_marks_are_awarded_for_every_incorrect_answer_and_0_for_questions_not_attempted\"><\/span><strong>Question<\/strong> 7.In a class test containing 10 questions, 5 marks are awarded for e^very correct answer and {tex}\\left( { &#8211; 2} \\right){\/tex} marks are awarded for every incorrect answer and 0 for questions not attempted.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(i)Mohan gets four correct and six incorrect answers. What is his score?<\/p>\n<p>(ii)Reshma gets five correct answers and five incorrect answers, what is her score?<\/p>\n<p>(iii)Heena gets two correct and five incorrect answers out of seven questions she attempts. What is her score?<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(i) Mohan gets marks for four correct questions = 4 x 5 = 20<\/p>\n<p>He gets marks for six incorrect questions = 6 x (\u20132) = \u201312<\/p>\n<p>Therefore, total scores of Mohan = (4 x 5) + [6 x (\u20132)]\n<p>= 20 \u2013 12 = 8<\/p>\n<p>Thus, Mohan gets 8 marks in a class test.<\/p>\n<p>(ii) Reshma gets marks for five correct questions = 5 x 5 = 25<\/p>\n<p>She gets marks for five incorrect questions = 5 x (\u20132) = \u201310<\/p>\n<p>Therefore, total score of Resham = 25 + (\u201310) = 15<\/p>\n<p>Thus, Reshma gets 15 marks in a class test.<\/p>\n<p>(iii) Heena gets marks for two correct questions = 2 x 5 = 10<\/p>\n<p>She gets marks for five incorrect questions = 5 x (\u20132) = \u201310<\/p>\n<p>Therefore, total score of Resham = 10 + (\u201310) = 0<\/p>\n<p>Thus, Reshma gets 0 marks in a class test.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_8A_cement_company_earns_a_profit_of_Rs_8_per_bag_of_white_cement_sold_and_a_loss_of_Rs_5_per_bag_of_grey_cement_sold\"><\/span><strong>Question<\/strong> 8.A cement company earns a profit of Rs. 8 per bag of white cement sold and a loss of Rs. 5 per bag of grey cement sold.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a)The company sells 3,000 bags of white cement and 5,000 bags of grey cement in a month. What is its profit or loss?<\/p>\n<p>(b)What is the number of white cement bags it must sell to have neither profit nor loss. If the number of grey bags sold is 6,400 bags.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Given: Profit of 1 bag of white cement = Rs. 8<\/p>\n<p>And Loss of 1 bag of grey cement = Rs. 5<\/p>\n<p>(a) Profit on selling 3000 bags of white cement = 3000 x 8 = Rs. 24,000<\/p>\n<p>Loss of selling 5000 bags of grey cement = 5000 x Rs. 5 = Rs. 25,000<\/p>\n<p>Since Profit &lt; Loss<\/p>\n<p>Therefore, his total loss on selling the grey cement bags = Loss \u2013 Profit<\/p>\n<p>= 25,000 \u2013 24,000<\/p>\n<p>= Rs. 1,000<\/p>\n<p>Thus, he has lost of Rs. 1,000 on selling the grey cement bags.<\/p>\n<p>(b)Let the number of bags of white cement be {tex}x.{\/tex}<\/p>\n<p>According to question, Loss = Profit<\/p>\n<p>{tex}\\therefore {\/tex} 5 x 6,400 = {tex}x{\/tex} x 8<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}x = \\frac{{5 \\times 6400}}{8}{\/tex} = 5000 bags<\/p>\n<p>Thus, he must sell 4000 white cement bags to have neither profit nor loss.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 7 Maths Exercise 1.3<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_9Replace_the_blank_with_an_integer_to_make_it_a_true_statement\"><\/span><strong>Question 9.<\/strong>Replace the blank with an integer to make it a true statement:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a){tex}\\left( { &#8211; 3} \\right) \\times \\_\\_\\_\\_\\_\\_\\_ = 27{\/tex}<\/p>\n<p>(b) {tex}5 \\times \\_\\_\\_\\_\\_\\_\\_ = &#8211; 35{\/tex}<\/p>\n<p>(c) {tex}\\_\\_\\_\\_\\_\\_\\_ \\times \\left( { &#8211; 8} \\right) = &#8211; 56{\/tex}<\/p>\n<p>(d) {tex}\\_\\_\\_\\_\\_\\_\\_ \\times \\left( { &#8211; 12} \\right) = 132{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}\\left( { &#8211; 3} \\right) \\times \\underline {\\left( { &#8211; 9} \\right)} = 27{\/tex}<\/p>\n<p>(b) {tex}5 \\times \\underline {\\left( { &#8211; 7} \\right)} = &#8211; 35{\/tex}<\/p>\n<p>(c) {tex}\\underline 7 \\times \\left( { &#8211; 8} \\right) = &#8211; 56{\/tex}<\/p>\n<p>(d) {tex}\\underline {\\left( { &#8211; 11} \\right)} \\times \\left( { &#8211; 12} \\right) = 132{\/tex}<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_7_Maths_Exercise_13\"><\/span>NCERT Solutions for Class 7 Maths Exercise 1.3<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 7 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 7 Maths Exercise 1.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 7 Maths Exercise 1.3\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-maths-exercise-1-3\/\" aria-label=\"More on NCERT Solutions for Class 7 Maths Exercise 1.3\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1388,281],"tags":[283,1535,321,1485,216],"class_list":["post-4285","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-07","category-ncert-solutions","tag-cbse-study-material","tag-class-7","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 7 Maths Exercise 1.3 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 7 Maths Exercise 1.3 in PDF format for free download. 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