{"id":4247,"date":"2016-05-06T11:49:00","date_gmt":"2016-05-06T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-ratio-and-proportion-ex-12-1\/"},"modified":"2018-07-23T10:17:33","modified_gmt":"2018-07-23T04:47:33","slug":"ncert-solutions-class-6-maths-exercise-12-1","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Exercise 12.1"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#NCERT_Solutions_for_Class_6_Maths_Ratio_and_proportion\" >NCERT Solutions for Class 6 Maths Ratio and proportion<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Class_%E2%80%93VI_Mathematics\" >Class \u2013VI Mathematics<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Ex_121\" >(Ex. 12.1)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_1_There_are_20_girls_and_15_boys_in_a_class\" >Question 1. There are 20 girls and 15 boys in a class.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_2_Out_of_30_students_in_a_class_like_football_12_like_cricket_and_remaining_like_tennis_Find_the_ratio_of\" >Question 2. Out of 30 students in a class, like football, 12 like cricket and remaining like tennis. Find the ratio of:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_3_See_the_figure_and_find_the_ratio_of\" >Question 3. See the figure and find the ratio of:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_4_Distances_travelled_by_Hamid_and_Akhtar_in_an_hour_are_9_km_and_12_km_Find_the_ratio_of_speed_of_Hamid_to_the_speed_of_Akhtar\" >Question 4. Distances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_5_Fill_in_the_following_blanks\" >Question 5. Fill in the following blanks:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_6_Find_the_ratio_of_the_following\" >Question 6. Find the ratio of the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_7_Find_the_ratio_of_the_following\" >Question 7. Find the ratio of the following:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_8_In_a_year_Seema_earns_Rs_150000_and_saves_Rs_50000_Find_the_ratio_of\" >Question 8. In a year, Seema earns Rs. 1,50,000 and saves Rs. 50,000. Find the ratio of:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_9_There_are_102_teachers_in_a_school_of_33oo_students_Find_the_ratio_of_the_number_of_teachers_to_the_number_of_students\" >Question 9. There are 102 teachers in a school of 33oo students. Find the ratio of the number of teachers to the number of students.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_11_Out_of_1800_students_in_a_school_750_opted_basketball_800_opted_cricket_and_remaining_opted_table_tennis_If_a_student_can_opt_only_one_game_find_the_ratio_of\" >Question 11. Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_12_Cost_of_a_dozen_pens_is_Rs_180_and_cost_of_8_ball_pens_is_Rs_56_Find_the_ratio_of_the_cost_of_a_pen_to_the_cost_of_a_ball_pen\" >Question 12. Cost of a dozen pens is Rs. 180 and cost of 8 ball pens is Rs. 56. Find the ratio of the cost of a pen to the cost of a ball pen.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_13_Consider_the_statement_Ratio_of_breadth_and_length_of_a_ball_is_2_5_Complete_the_following_table_that_shows_some_possible_breadths_and_lengths_of_the_hall\" >Question 13. Consider the statement: Ratio of breadth and length of a ball is 2 : 5. Complete the following table that shows some possible breadths and lengths of the hall.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_14_Divide_20_pens_between_Sheela_and_Sangeeta_in_the_ratio_3_2\" >Question 14. Divide 20 pens between Sheela and Sangeeta in the ratio 3 : 2.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_15_Mother_wants_to_divide_Rs_36_between_her_daughters_Shreya_and_Bhoomika_in_the_ratio_of_their_ages_If_the_age_of_Shreya_is_15_years_and_age_of_Bhoomika_is_12_years_find_how_much_Shreya_and_Bhoomika_will_get\" >Question 15. Mother wants to divide Rs. 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If the age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#Question_16_Present_age_of_father_is_42_years_and_that_of_his_son_is_14_years_Find_the_ratio_of\" >Question 16. Present age of father is 42 years and that of his son is 14 years. Find the ratio of:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#NCERT_Solutions_for_Class_6_Maths_Exercise_121\" >NCERT Solutions for Class 6 Maths Exercise 12.1<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#NCERT_Solutions_for_Mathematics_Class_3rd_to_12th\" >NCERT Solutions for Mathematics Class 3rd to 12th<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 6 Maths Exercise 12.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Ratio and proportion <a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-06-mathematics-ratio-and-proportion\/1624\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/06_Maths_Book.jpg\" alt=\"NCERT Solutions for Class 6 Maths Exercise 12.1\" width=\"154\" height=\"180\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_6_Maths_Ratio_and_proportion\"><\/span>NCERT Solutions for Class 6 Maths Ratio and proportion<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VI_Mathematics\"><\/span><strong>Class \u2013VI Mathematics <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Ex_121\"><\/span><strong>(Ex. 12.1)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1_There_are_20_girls_and_15_boys_in_a_class\"><\/span><strong>Question 1. <\/strong>There are 20 girls and 15 boys in a class.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a)What is the ratio of number of girls to the number of boys?<\/p>\n<p>(b)What is the ratio of girls to the total number of students in the class?<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) The ratio of girls to that of boys = {tex}\\frac{{20}}{{15}} = \\frac{4}{3}{\/tex} = 4 : 3<\/p>\n<p>(b) The ratio of girls to total students = {tex}\\frac{{20}}{{20 + 15}} = \\frac{{20}}{{35}} = \\frac{4}{7}{\/tex} = 4 : 7<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_2_Out_of_30_students_in_a_class_like_football_12_like_cricket_and_remaining_like_tennis_Find_the_ratio_of\"><\/span><strong>Question 2. <\/strong>Out of 30 students in a class, like football, 12 like cricket and remaining like tennis. Find the ratio of:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a)Number of students liking football to number of students liking tennis.<\/p>\n<p>(b)Number of students liking cricket to total number of students.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Total number of students = 30<\/p>\n<p>Number of students like football = 6<\/p>\n<p>Number of students like cricket = 12<\/p>\n<p>Thus number of students like tennis = 30 \u2013 6 \u2013 12 = 12<\/p>\n<p>(a) The ratio of students like football that of tennis = {tex}\\frac{6}{{12}} = \\frac{1}{2}{\/tex} = 1 : 2<\/p>\n<p>(b) The ratio of students like cricket to that of total students = {tex}\\frac{{12}}{{30}} = \\frac{2}{5}{\/tex} = 2 : 5<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3_See_the_figure_and_find_the_ratio_of\"><\/span><strong>Question 3. <\/strong>See the figure and find the ratio of:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/06\/mathematics\/06_math_ncert_ch12_01.jpg\" \/><\/p>\n<p>(a)Number of triangles to the number of circles inside the rectangle.<\/p>\n<p>(b)Number of squares to all the figures inside the rectangle.<\/p>\n<p>(c)Number of circles to all the figures inside the rectangle.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Ratio of number of triangle to that of circles = {tex}\\frac{3}{2}{\/tex} = 3 : 2<\/p>\n<p>(b) Ratio of number of squares to all figures = {tex}\\frac{2}{7}{\/tex} = 2 : 7<\/p>\n<p>(c) Ratio of number of circles to all figures = {tex}\\frac{2}{7}{\/tex} = 2 : 7<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_4_Distances_travelled_by_Hamid_and_Akhtar_in_an_hour_are_9_km_and_12_km_Find_the_ratio_of_speed_of_Hamid_to_the_speed_of_Akhtar\"><\/span><strong>Question 4. <\/strong>Distances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>We know that, Speed = {tex}\\frac{{{\\text{Distance}}}}{{{\\text{Time}}}}{\/tex}<\/p>\n<p>Speed of Hamid = {tex}\\frac{{{\\text{9 m}}}}{{{\\text{1 h}}}}{\/tex} = 9 km\/h and Speed of Akhtar = {tex}\\frac{{{\\text{12 m}}}}{{{\\text{1 h}}}}{\/tex} = 12 km\/h<\/p>\n<p>Ratio of speed of Hamid to that of speed of Akhtar = {tex}\\frac{9}{{12}} = \\frac{3}{4}{\/tex} = 3 : 4<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5_Fill_in_the_following_blanks\"><\/span><strong>Question 5. <\/strong>Fill in the following blanks:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>{tex}\\frac{{15}}{{18}} = \\frac{{\\boxed{{\\text{ }}}}}{6} = \\frac{{10}}{{\\boxed{{\\text{ }}}}} = \\frac{{\\boxed{{\\text{ }}}}}{{30}}{\/tex} [Are these equivalent ratios?]\n<p><strong>Answer:<\/strong><\/p>\n<p>{tex}\\frac{{15}}{{18}} = \\frac{{\\boxed5}}{6} = \\frac{{10}}{{\\boxed{12}}} = \\frac{{\\boxed{25}}}{{30}}{\/tex}<\/p>\n<p>Yes, these are equivalent ratios.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_6_Find_the_ratio_of_the_following\"><\/span><strong>Question 6. <\/strong>Find the ratio of the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) 81 to 108<\/p>\n<p>(b) 98 to 63<\/p>\n<p>(c) 33 km to 121 km<\/p>\n<p>(d) 30 minutes to 45 minutes<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Ratio of 81 to 108 = = 3 : 4<\/p>\n<p>(b) Ratio of 98 to 63 = = 14 : 9<\/p>\n<p>(c) Ratio of 33 km to 121 km = = 3 : 11<\/p>\n<p>(d) Ratio of 30 minutes to 45 minutes = = 2 : 3<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_7_Find_the_ratio_of_the_following\"><\/span><strong>Question 7. <\/strong>Find the ratio of the following:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) 30 minutes to 1 hour<\/p>\n<p>(b) 40 cm to 1.5 m<\/p>\n<p>(c) 55 paise to Re. 1<\/p>\n<p>(d) 500 ml to 2 liters<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) 30 minutes to 1.5 hour<\/p>\n<p>1.5 hours = 1.5 x 60 = 90 minutes [{tex}\\because {\/tex} 1 hour = 60 minutes]\n<p>Now, ratio of 30 minutes to 1.5 hour = 30 minutes : 1.5 hour<\/p>\n<p>{tex} \\Rightarrow {\/tex} 30 minutes : 90 minutes = = 1 : 3<\/p>\n<p>(b) 40 cm to 1.5 m<\/p>\n<p>1.5 m = 1.5 x 100 cm = 150 cm [{tex}\\because {\/tex} 1 m = 100 cm]\n<p>Now, ratio of 40 cm to 1.5 m = 40 cm : 1.5 m<\/p>\n<p>{tex} \\Rightarrow {\/tex} 40 cm : 150 cm = = 4 : 15<\/p>\n<p>(c) 55 paise to Re. 1<\/p>\n<p>Re. 1 = 100 paise<\/p>\n<p>Now, ratio of 55 paise to Re. 1 = 55 paise : 100 paise<\/p>\n<p>{tex} \\Rightarrow {\/tex} = 11 : 20<\/p>\n<p>(d) 500 ml to 2 liters<\/p>\n<p>2 liters = 2 x 1000 ml = 2000 ml [{tex}\\because {\/tex} 1 litre = 1000 ml]\n<p>Now, ratio of 500 ml to 2 liters = 500 ml : 2 liters<\/p>\n<p>{tex} \\Rightarrow {\/tex} 500 ml : 2000 ml = = 1 : 4<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_8_In_a_year_Seema_earns_Rs_150000_and_saves_Rs_50000_Find_the_ratio_of\"><\/span><strong>Question 8. <\/strong>In a year, Seema earns Rs. 1,50,000 and saves Rs. 50,000. Find the ratio of:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) Money that Seema earns to the money she saves.<\/p>\n<p>(b) Money that she saves to the money she spends.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Total earning = Rs. 1,50,000 and Saving = Rs. 50,000<\/p>\n<p>{tex}\\therefore {\/tex} Money spent = Rs. 1,50,000 &#8211; Rs. 50,000 = Rs. 1,00,000<\/p>\n<p>(a) Ratio of money earned to money saved = = 3 : 1<\/p>\n<p>(b) Ratio of money saved to money spend = = 1 : 2<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_9_There_are_102_teachers_in_a_school_of_33oo_students_Find_the_ratio_of_the_number_of_teachers_to_the_number_of_students\"><\/span><strong>Question 9. <\/strong>There are 102 teachers in a school of 33oo students. Find the ratio of the number of teachers to the number of students.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong> Ratio of number of teachers to that of students = = 17 : 550<\/p>\n<p><strong>Question 10. <\/strong>In a college out of 4320 students, 2300 are girls. Find the ratio of:<\/p>\n<p>(a) Number of girls to the total number of students.<\/p>\n<p>(b) Number of boys to the number of girls.<\/p>\n<p>(c) Number of boys to the total number of students.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Total number of students in school = 4320<\/p>\n<p>Number of girls = 2300<\/p>\n<p>Therefore, number of boys = 4320 \u2013 2300 = 2020<\/p>\n<p>(a) Ratio of girls to total number of students = = 115 : 216<\/p>\n<p>(b) Ratio of boys to that of girls = = 101 : 115<\/p>\n<p>(c) Ratio of boys to total number of students = = 101 : 216<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_11_Out_of_1800_students_in_a_school_750_opted_basketball_800_opted_cricket_and_remaining_opted_table_tennis_If_a_student_can_opt_only_one_game_find_the_ratio_of\"><\/span><strong>Question 11. <\/strong>Out of 1800 students in a school, 750 opted basketball, 800 opted cricket and remaining opted table tennis. If a student can opt only one game, find the ratio of:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) Number of students who opted basketball to the number of students who opted table tennis.<\/p>\n<p>(b) Number of students who opted cricket to the number of students opting basketball.<\/p>\n<p>(c) Number of students who opted basketball to the total number of students.<\/p>\n<p><strong>Answer:<\/strong> Total number of students = 1800<\/p>\n<p>Number of students opted basketball = 750<\/p>\n<p>Number of students opted cricket = 800<\/p>\n<p>Therefore, number of students opted tennis = 1800 \u2013 (750 + 800) = 250<\/p>\n<p>(a) Ratio of students opted basketball to that of opted table tennis = = 3 : 1<\/p>\n<p>(b) Ratio of students opted cricket to students opted basketball = = 16 : 15<\/p>\n<p>(c) Ratio of students opted basketball to total no. of students = = 5 : 12<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_12_Cost_of_a_dozen_pens_is_Rs_180_and_cost_of_8_ball_pens_is_Rs_56_Find_the_ratio_of_the_cost_of_a_pen_to_the_cost_of_a_ball_pen\"><\/span><strong>Question 12. <\/strong>Cost of a dozen pens is Rs. 180 and cost of 8 ball pens is Rs. 56. Find the ratio of the cost of a pen to the cost of a ball pen.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong> Cost of a dozen pens (12 pens) = Rs. 180<\/p>\n<p>{tex}\\therefore {\/tex} Cost of 1 pen = {tex}\\frac{{180}}{{12}}{\/tex} = Rs. 15<\/p>\n<p>Cost of 8 ball pens = Rs. 56<\/p>\n<p>{tex}\\therefore {\/tex} Cost of 1 ball en = {tex}\\frac{{56}}{8}{\/tex} = Rs. 7<\/p>\n<p>Ratio of cost of one pen to that of one ball pen = {tex}\\frac{{15}}{7}{\/tex} = 15 : 7<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_13_Consider_the_statement_Ratio_of_breadth_and_length_of_a_ball_is_2_5_Complete_the_following_table_that_shows_some_possible_breadths_and_lengths_of_the_hall\"><\/span><strong>Question 13. <\/strong>Consider the statement: Ratio of breadth and length of a ball is 2 : 5. Complete the following table that shows some possible breadths and lengths of the hall.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<table style=\"width: 100%;\" border=\"1\" cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td><strong>Breadth of the hall (in meters)<\/strong><\/td>\n<td>10<\/td>\n<td>{tex}\\boxed{{\\text{}}}{\/tex}<\/td>\n<td>40<\/td>\n<\/tr>\n<tr>\n<td><strong>Length of the hall (in meters)<\/strong><\/td>\n<td>25<\/td>\n<td>50<\/td>\n<td>{tex}\\boxed{{\\text{}}}{\/tex}<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><strong>Answer:<\/strong><\/p>\n<p>Ratio of breadth to length = 2 : 5 = {tex}\\frac{2}{5}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} Other equivalent ratios are = {tex}\\frac{2}{5} \\times \\frac{{10}}{{10}} = \\frac{{20}}{{50}}{\/tex}, {tex}\\frac{2}{5} \\times \\frac{{20}}{{20}} = \\frac{{40}}{{100}}{\/tex}<\/p>\n<p>Thus,<\/p>\n<table style=\"width: 100%;\" border=\"1\" cellspacing=\"0\" cellpadding=\"0\">\n<tbody>\n<tr>\n<td><strong>Breadth of the hall (in meters)<\/strong><\/td>\n<td>10<\/td>\n<td>20<\/td>\n<td>40<\/td>\n<\/tr>\n<tr>\n<td><strong>Length of the hall (in meters)<\/strong><\/td>\n<td>25<\/td>\n<td>50<\/td>\n<td>100<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h6><span class=\"ez-toc-section\" id=\"Question_14_Divide_20_pens_between_Sheela_and_Sangeeta_in_the_ratio_3_2\"><\/span><strong>Question 14. <\/strong>Divide 20 pens between Sheela and Sangeeta in the ratio 3 : 2.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Ratio between Sheela and Sangeeta = 3 : 2<\/p>\n<p>Total these terms = 3 + 2 = 5<\/p>\n<p>Therefore, part of Sheela = {tex}\\frac{3}{5}{\/tex} of the total pens<\/p>\n<p>And part of Sangeeta = {tex}\\frac{2}{5}{\/tex} of total pens<\/p>\n<p>Thus, Sheela gets = = 12 pens<\/p>\n<p>And Sangeeta gets = = 8 pens<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_15_Mother_wants_to_divide_Rs_36_between_her_daughters_Shreya_and_Bhoomika_in_the_ratio_of_their_ages_If_the_age_of_Shreya_is_15_years_and_age_of_Bhoomika_is_12_years_find_how_much_Shreya_and_Bhoomika_will_get\"><\/span><strong>Question 15. <\/strong>Mother wants to divide Rs. 36 between her daughters Shreya and Bhoomika in the ratio of their ages. If the age of Shreya is 15 years and age of Bhoomika is 12 years, find how much Shreya and Bhoomika will get.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Ratio of the age of Shreya to that of Bhoomika = = 5 : 4<\/p>\n<p>Thus, Rs. 36 divide between Shreya and Bhoomika in the ratio of 5 : 4.<\/p>\n<p>Shreya gets = {tex}\\frac{5}{9}{\/tex} of Rs. 36 = = Rs. 20<\/p>\n<p>Bhoomika gets = {tex}\\frac{4}{9}{\/tex} of Rs. 36 = = Rs. 16<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 12.1<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_16_Present_age_of_father_is_42_years_and_that_of_his_son_is_14_years_Find_the_ratio_of\"><\/span><strong>Question 16. <\/strong>Present age of father is 42 years and that of his son is 14 years. Find the ratio of:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) Present age of father to the present age of son.<\/p>\n<p>(b) Age of the father to the age of the son, when son was 12 years old.<\/p>\n<p>(c) Age of father after 10 years to the age of son after 10 years.<\/p>\n<p>(d) Age of father to the age of son when father was 30 years old.<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) Ratio of father\u2019s present age to that of son = = 3 : 1<\/p>\n<p>(b) When son was 12 years, i.e., 2 years ago, then father was (42 \u2013 2) = 40 years<\/p>\n<p>Therefore, the ratio of their ages = = 10 : 3<\/p>\n<p>(c) Age of father after 10 years = 42 + 10 = 52 years<\/p>\n<p>Age of son after 10 years = 14 + 10 = 24 years<\/p>\n<p>Therefore, ratio of their ages = = 13 : 6<\/p>\n<p>(d) When father was 30 years old, i.e., 12 years ago, then son was (14 \u2013 12) = 2 years old<\/p>\n<p>Therefore, the ratio of their ages = = 15 : 1<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_6_Maths_Exercise_121\"><\/span>NCERT Solutions for Class 6 Maths Exercise 12.1<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Mathematics_Class_3rd_to_12th\"><\/span>NCERT Solutions for Mathematics Class 3rd to 12th<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-12-mathematics\/\">NCERT Solutions for Class 12 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-11-mathematics\/\">NCERT Solutions for Class 11 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths\/\">NCERT Solutions for Class 10 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths\/\">NCERT Solutions for Class 9 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-mathematics\/\">NCERT Solutions for Class 8 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-mathematics\/\">NCERT Solutions for Class 7 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths\/\">NCERT Solutions for Class 6 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-5-mathematics\/\">NCERT Solutions for Class 5 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-4-mathematics\/\">NCERT Solutions for Class 4 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-3-mathematics\/\">NCERT Solutions for Class 3 Mathematics<\/a><\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 6 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 6 Maths Exercise 12.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 6 Maths Exercise 12.1\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-12-1\/\" aria-label=\"More on NCERT Solutions for Class 6 Maths Exercise 12.1\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1395,281],"tags":[283,196,321,1485,216],"class_list":["post-4247","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-06","category-ncert-solutions","tag-cbse-study-material","tag-class-6","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 6 Maths Exercise 12.1 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 6 Maths Exercise 12.1 in PDF format for free download. 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