{"id":4228,"date":"2016-05-06T11:49:00","date_gmt":"2016-05-06T11:49:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-16\/"},"modified":"2018-07-21T11:35:46","modified_gmt":"2018-07-21T06:05:46","slug":"ncert-solutions-class-6-maths-exercise-7-6","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/","title":{"rendered":"NCERT Solutions for Class 6 Maths Exercise 7.6"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#NCERT_Solutions_for_Class_6_Maths_Fractions\" >NCERT Solutions for Class 6 Maths\u00a0Fractions<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Class_%E2%80%93VI_Mathematics\" >Class \u2013VI Mathematics<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Ex_76\" >(Ex. 7.6)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_1Solve\" >Question 1.Solve:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_2Sarika_bought_texfrac25tex_meter_of_ribbon_and_Lalita_texfrac34tex_meter_of_ribbon_What_is_the_total_length_of_the_ribbon_they_bought\" >Question 2.Sarika bought {tex}\\frac{2}{5}{\/tex} meter of ribbon and Lalita {tex}\\frac{3}{4}{\/tex} meter of ribbon. What is the total length of the ribbon they bought?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_3Naina_was_given_tex1frac12tex_piece_of_cake_and_Najma_was_given_tex1frac13tex_piece_of_cake_Find_the_total_amount_of_cake_given_to_both_of_them\" >Question 3.Naina was given {tex}1\\frac{1}{2}{\/tex} piece of cake and Najma was given {tex}1\\frac{1}{3}{\/tex} piece of cake. Find the total amount of cake given to both of them.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_4Fill_in_the_boxes\" >Question 4.Fill in the boxes:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_5Complete_the_addition_%E2%80%93_subtraction_box\" >Question 5.Complete the addition \u2013 subtraction box:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_6A_piece_of_wire_texfrac78tex_meter_long_broke_into_two_pieces_One_piece_was_texfrac14tex_meter_long_How_long_is_the_other_piece\" >Question 6.A piece of wire {tex}\\frac{7}{8}{\/tex} meter long broke into two pieces. One piece was {tex}\\frac{1}{4}{\/tex} meter long. How long is the other piece?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_7Nandini_house_is_texfrac910tex_km_from_her_school_She_walked_some_distance_and_then_took_a_bus_for_texfrac12tex_km_to_reach_the_school_How_far_did_she_walk\" >Question 7.Nandini house is {tex}\\frac{9}{{10}}{\/tex} km from her school. She walked some distance and then took a bus for {tex}\\frac{1}{2}{\/tex} km to reach the school. How far did she walk?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_8Ahsa_and_Samuel_have_bookshelves_of_the_same_size_partly_filled_with_books_Ashas_shelf_is_texfrac56thtex_full_and_Samuels_shelf_is_texfrac25thtex_full_Whose_bookshelf_is_more_full_By_what_fraction\" >Question 8.Ahsa and Samuel have bookshelves of the same size partly filled with books. Asha\u2019s shelf is {tex}\\frac{5}{6}th{\/tex} full and Samuel\u2019s shelf is {tex}\\frac{2}{5}th{\/tex} full. Whose bookshelf is more full? By what fraction?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#Question_9Jaidev_takes_tex2frac15tex_minutes_to_walk_across_the_school_ground_Rahul_takes_texfrac74tex_minutes_to_do_same_Who_takes_less_time_and_by_what_fraction\" >Question 9.Jaidev takes {tex}2\\frac{1}{5}{\/tex} minutes to walk across the school ground. Rahul takes {tex}\\frac{7}{4}{\/tex} minutes to do same. Who takes less time and by what fraction?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#NCERT_Solutions_for_Class_6_Maths_Exercise_76\" >NCERT Solutions for Class 6 Maths Exercise 7.6<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#NCERT_Solutions_for_Mathematics_Class_3rd_to_12th\" >NCERT Solutions for Mathematics Class 3rd to 12th<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 6 Maths Exercise 7.6 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Maths\u00a0Fractions\u00a0<a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-06-mathematics-fractions\/1619\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_6_Maths_Fractions\"><\/span>NCERT Solutions for Class 6 Maths\u00a0Fractions<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Class_%E2%80%93VI_Mathematics\"><\/span><strong>Class \u2013VI Mathematics <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6 style=\"text-align: center;\"><span class=\"ez-toc-section\" id=\"Ex_76\"><\/span><strong>(Ex. 7.6)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<h6><span class=\"ez-toc-section\" id=\"Question_1Solve\"><\/span><strong>Question 1.<\/strong>Solve:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}\\frac{2}{3} + \\frac{1}{7}{\/tex}<\/p>\n<p>(b) {tex}\\frac{3}{{10}} + \\frac{7}{{15}}{\/tex}<\/p>\n<p>(c) {tex}\\frac{4}{9} + \\frac{2}{7}{\/tex}<\/p>\n<p>(d) {tex}\\frac{5}{7} + \\frac{1}{3}{\/tex}<\/p>\n<p>(e) {tex}\\frac{2}{5} + \\frac{1}{6}{\/tex}<\/p>\n<p>(f) {tex}\\frac{4}{5} + \\frac{2}{3}{\/tex}<\/p>\n<p>(g) {tex}\\frac{3}{4} &#8211; \\frac{1}{3}{\/tex}<\/p>\n<p>(h) {tex}\\frac{5}{6} &#8211; \\frac{1}{3}{\/tex}<\/p>\n<p>(i) {tex}\\frac{2}{3} + \\frac{3}{4} + \\frac{1}{2}{\/tex}<\/p>\n<p>(j) {tex}\\frac{1}{2} + \\frac{1}{3} + \\frac{1}{6}{\/tex}<\/p>\n<p>(k) {tex}1\\frac{1}{3} + 3\\frac{2}{3}{\/tex}<\/p>\n<p>(l) {tex}4\\frac{2}{3} + 3\\frac{1}{4}{\/tex}<\/p>\n<p>(m) {tex}\\frac{{16}}{5} &#8211; \\frac{7}{5}{\/tex}<\/p>\n<p>(n) {tex}\\frac{4}{3} &#8211; \\frac{1}{2}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) L.C.M. of 3 and 7 is 21<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{2}{3} + \\frac{1}{7} = \\frac{{2 \\times 7 + 1 \\times 3}}{{21}} = \\frac{{14 + 3}}{{21}} = \\frac{{17}}{{21}}{\/tex}<\/p>\n<p>(b) L.C.M. of 10 and 15 is 30<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{3}{{10}} + \\frac{7}{{15}} = \\frac{{3 \\times 3 + 7 \\times 2}}{{30}} = \\frac{{9 + 14}}{{30}} = \\frac{{23}}{{30}}{\/tex}<\/p>\n<p>(c) L.C.M. of 9 and 7 is 63<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{4}{9} + \\frac{2}{7} = \\frac{{4 \\times 7 + 2 \\times 9}}{{63}} = \\frac{{28 + 18}}{{63}} = \\frac{{46}}{{63}}{\/tex}<\/p>\n<p>(d)L.C.M. of 7 and 3 is 21<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{5}{7} + \\frac{1}{3} = \\frac{{5 \\times 3 + 7 \\times 1}}{{21}} = \\frac{{15 + 7}}{{21}} = \\frac{{22}}{{21}} = 1\\frac{1}{{21}}{\/tex}<\/p>\n<p>(e)L.C.M. of 5 and 6 is 30<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{2}{5} + \\frac{1}{6} = \\frac{{2 \\times 6 + 5 \\times 1}}{{30}} = \\frac{{12 + 5}}{{30}} = \\frac{{17}}{{30}}{\/tex}<\/p>\n<p>(f)L.C.M. of 5 and 3 is 15<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{4}{5} + \\frac{2}{3}{\/tex} = {tex}\\frac{{4 \\times 3 + 2 \\times 5}}{{15}} = \\frac{{12 + 10}}{{15}} = \\frac{{22}}{{15}} = 1\\frac{7}{{15}}{\/tex}<\/p>\n<p>(g)L.C.M. of 4 and 3 is 12<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{3}{4} &#8211; \\frac{1}{3} = \\frac{{3 \\times 3 &#8211; 4 \\times 1}}{{12}} = \\frac{{9 &#8211; 4}}{{12}} = \\frac{5}{{12}}{\/tex}<\/p>\n<p>(h)L.C.M. of 6 and 3 is 6<\/p>\n<p>{tex}\\therefore {\/tex}<\/p>\n<p>{tex}\\frac{5}{6}-\\frac{1}{3}=\\frac{5\\times 1-2\\times 1}{6}=\\frac{5-2}{6}=\\frac{3}{6}=\\frac{1}{2}{\/tex}<\/p>\n<p>(i)L.C.M. of 3, 4 and 2 is 12<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{2}{3} + \\frac{3}{4} + \\frac{1}{2} = \\frac{{2 \\times 4 + 3 \\times 3 + 1 \\times 6}}{{12}} = \\frac{{6 + 9 + 6}}{{12}} = \\frac{{23}}{{12}} = 1\\frac{{11}}{{12}}{\/tex}<\/p>\n<p>(j)L.C.M. of 2, 3, and 6 is 6<\/p>\n<p>{tex}\\therefore {\/tex}<\/p>\n<p>{tex}\\frac{1}{2}+\\frac{1}{3}+\\frac{1}{6}=\\frac{1\\times 3+1\\times 2+1\\times 1}{6}=\\frac{3+2+1}{6}=\\frac{6}{6}=1{\/tex}<\/p>\n<p>(k)L.C.M. of 3 and 3 is 3<\/p>\n<p>{tex}\\therefore {\/tex}<\/p>\n<p>{tex}\\frac{4}{3}+\\frac{11}{3}=\\frac{4+11}{3}=\\frac{15}{3}=5{\/tex}<\/p>\n<p>(l)L.C.M. of 3 and 4 is 12<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{14}}{3} + \\frac{{13}}{4} = \\frac{{14 \\times 4 + 13 \\times 3}}{{12}} = \\frac{{56 + 39}}{{12}} = \\frac{{95}}{{12}} = 7\\frac{{11}}{{12}}{\/tex}<\/p>\n<p>(m)L.C.M. of 5 and 5 is 5<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{{16}}{5} &#8211; \\frac{7}{5} = \\frac{{16 &#8211; 7}}{5} = \\frac{9}{5} = 1\\frac{4}{5}{\/tex}<\/p>\n<p>(n)L.C.M. of 3 and 2 is 6<\/p>\n<p>{tex}\\therefore {\/tex} {tex}\\frac{4}{3} &#8211; \\frac{1}{2} = \\frac{{4 \\times 2 &#8211; 1 \\times 3}}{6} = \\frac{{8 &#8211; 3}}{6} = \\frac{5}{6}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 7.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_2Sarika_bought_texfrac25tex_meter_of_ribbon_and_Lalita_texfrac34tex_meter_of_ribbon_What_is_the_total_length_of_the_ribbon_they_bought\"><\/span><strong>Question 2.<\/strong>Sarika bought {tex}\\frac{2}{5}{\/tex} meter of ribbon and Lalita {tex}\\frac{3}{4}{\/tex} meter of ribbon. What is the total length of the ribbon they bought?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Ribbon bought by Sarita = {tex}\\frac{2}{5}{\/tex} m and Ribbon bought by Lalita = {tex}\\frac{3}{4}{\/tex} m<\/p>\n<p>Total length of ribbon = {tex}\\frac{2}{5} + \\frac{3}{4}{\/tex} = {tex}\\frac{{2 \\times 4 + 5 \\times 3}}{{20}}{\/tex} [{tex}\\because {\/tex} L.C.M. of 5 and 4 is 20]\n<p>= {tex}\\frac{{8 + 15}}{{20}} = \\frac{{23}}{{20}} = 1\\frac{3}{{20}}{\/tex} m<\/p>\n<p>Therefore, they bought {tex}1\\frac{3}{{20}}{\/tex} m of ribbon.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 7.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_3Naina_was_given_tex1frac12tex_piece_of_cake_and_Najma_was_given_tex1frac13tex_piece_of_cake_Find_the_total_amount_of_cake_given_to_both_of_them\"><\/span><strong>Question 3.<\/strong>Naina was given {tex}1\\frac{1}{2}{\/tex} piece of cake and Najma was given {tex}1\\frac{1}{3}{\/tex} piece of cake. Find the total amount of cake given to both of them.<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Cake taken by Naina = {tex}1\\frac{1}{2}{\/tex} piece and Cake taken by Najma = {tex}1\\frac{1}{3}{\/tex} piece<\/p>\n<p>Total cake taken = {tex}1\\frac{1}{2}{\/tex} + {tex}1\\frac{1}{3}{\/tex} = {tex}\\frac{3}{2} + \\frac{4}{3}{\/tex} = {tex}\\frac{{3 \\times 3 + 4 \\times 2}}{6}{\/tex} [{tex}\\because {\/tex} L.C.M. of 2 and 3 is 6]\n<p>= {tex}\\frac{{9 + 8}}{6} = \\frac{{17}}{6} = 2\\frac{5}{6}{\/tex}<\/p>\n<p>Therefore total consumption of cake is {tex}2\\frac{5}{6}{\/tex}.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_4Fill_in_the_boxes\"><\/span><strong>Question 4.<\/strong>Fill in the boxes:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p>(a) {tex}\\boxed{{\\text{ }}} &#8211; \\frac{5}{8} = \\frac{1}{4}{\/tex}<\/p>\n<p>(b) {tex}\\boxed{{\\text{ }}} &#8211; \\frac{1}{5} = \\frac{1}{2}{\/tex}<\/p>\n<p>(c) {tex}\\frac{1}{2} &#8211; \\boxed{{\\text{ }}} = \\frac{1}{6}{\/tex}<\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>(a) {tex}\\frac{1}{4} + \\frac{5}{8} = \\frac{{2 + 5}}{8} = \\frac{7}{8}{\/tex}<\/p>\n<p>(b) {tex}\\frac{1}{2} + \\frac{1}{5} = \\frac{{5 + 2}}{{10}} = \\frac{7}{{10}}{\/tex}<\/p>\n<p>(c) {tex}\\frac{1}{2} &#8211; \\frac{1}{6} = \\frac{{3 &#8211; 1}}{6} = \\frac{2}{6}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 7.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_5Complete_the_addition_%E2%80%93_subtraction_box\"><\/span><strong>Question 5.<\/strong>Complete the addition \u2013 subtraction box:<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/06\/mathematics\/06_math_ncert_ch07_18.jpg\" \/><\/p>\n<p><strong>Answer:<\/strong><\/p>\n<p>Sol.<\/p>\n<p><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/06\/mathematics\/06_math_ncert_ch07_22.jpg\" \/><\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_6A_piece_of_wire_texfrac78tex_meter_long_broke_into_two_pieces_One_piece_was_texfrac14tex_meter_long_How_long_is_the_other_piece\"><\/span><strong>Question 6.<\/strong>A piece of wire {tex}\\frac{7}{8}{\/tex} meter long broke into two pieces. One piece was {tex}\\frac{1}{4}{\/tex} meter long. How long is the other piece?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Total length of wire = {tex}\\frac{7}{8}{\/tex} meter<\/p>\n<p>Length of first part = {tex}\\frac{1}{4}{\/tex} meter<\/p>\n<p>Remaining part = {tex}\\frac{7}{8} &#8211; \\frac{1}{4} = \\frac{{7 \\times 1 &#8211; 2 \\times 1}}{8}{\/tex} [{tex}\\because {\/tex} L.C.M. of 8 and 4 is 8]\n<p>= {tex}\\frac{{7 &#8211; 2}}{8} = \\frac{5}{8}{\/tex} meter<\/p>\n<p>Therefore, the length of remaining part is {tex}\\frac{5}{8}{\/tex} meter.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 7.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_7Nandini_house_is_texfrac910tex_km_from_her_school_She_walked_some_distance_and_then_took_a_bus_for_texfrac12tex_km_to_reach_the_school_How_far_did_she_walk\"><\/span><strong>Question 7.<\/strong>Nandini house is {tex}\\frac{9}{{10}}{\/tex} km from her school. She walked some distance and then took a bus for {tex}\\frac{1}{2}{\/tex} km to reach the school. How far did she walk?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer: <\/strong><\/p>\n<p>Total distance between school and house = {tex}\\frac{9}{{10}}{\/tex} km<\/p>\n<p>Distance covered by bus = {tex}\\frac{1}{2}{\/tex} km<\/p>\n<p>Remaining distance = {tex}\\frac{9}{{10}} &#8211; \\frac{1}{2} = \\frac{{9 \\times 1 &#8211; 1 \\times 5}}{{10}}{\/tex} [{tex}\\because {\/tex} L.C.M. of 10 and 2 is 10]\n<p>= {tex}\\frac{9-5}{10}=\\frac{4}{10}=\\frac{2}{5}{\/tex} km<\/p>\n<p>Therefore, distance covered by walking us {tex}\\frac{2}{5}{\/tex} km.<\/p>\n<hr \/>\n<h6><span class=\"ez-toc-section\" id=\"Question_8Ahsa_and_Samuel_have_bookshelves_of_the_same_size_partly_filled_with_books_Ashas_shelf_is_texfrac56thtex_full_and_Samuels_shelf_is_texfrac25thtex_full_Whose_bookshelf_is_more_full_By_what_fraction\"><\/span><strong>Question 8.<\/strong>Ahsa and Samuel have bookshelves of the same size partly filled with books. Asha\u2019s shelf is {tex}\\frac{5}{6}th{\/tex} full and Samuel\u2019s shelf is {tex}\\frac{2}{5}th{\/tex} full. Whose bookshelf is more full? By what fraction?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>{tex}\\frac{5}{6}{\/tex} and {tex}\\frac{2}{5}{\/tex}<\/p>\n<p>{tex} \\Rightarrow {\/tex} {tex}\\frac{5}{6} \\times \\frac{5}{5} = \\frac{{25}}{{30}}{\/tex} and {tex}\\frac{2}{5} \\times \\frac{6}{6} = \\frac{{12}}{{30}}{\/tex} [{tex}\\because {\/tex} L.C.M. of 6 and 5 is 30]\n<p>{tex}\\because {\/tex} {tex}\\frac{{25}}{{30}} &gt; \\frac{{12}}{{30}}{\/tex} {tex} \\Rightarrow {\/tex} {tex}\\frac{5}{6} &gt; \\frac{2}{5}{\/tex}<\/p>\n<p>{tex}\\therefore {\/tex} Asha\u2019s bookshelf is more covered than Samueal.<\/p>\n<p>Difference = {tex}\\frac{{25}}{{30}} &#8211; \\frac{{12}}{{30}} = \\frac{{13}}{{30}}{\/tex}<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 6 Maths Exercise 7.6<\/p>\n<h6><span class=\"ez-toc-section\" id=\"Question_9Jaidev_takes_tex2frac15tex_minutes_to_walk_across_the_school_ground_Rahul_takes_texfrac74tex_minutes_to_do_same_Who_takes_less_time_and_by_what_fraction\"><\/span><strong>Question 9.<\/strong>Jaidev takes {tex}2\\frac{1}{5}{\/tex} minutes to walk across the school ground. Rahul takes {tex}\\frac{7}{4}{\/tex} minutes to do same. Who takes less time and by what fraction?<span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p><strong>Answer:<\/strong><\/p>\n<p>Time taken by jaidev = {tex}2\\frac{1}{5}{\/tex} minutes = {tex}\\frac{{11}}{5}{\/tex} minutes<\/p>\n<p>Time taken by Rahul = {tex}\\frac{7}{4}{\/tex} minutes<\/p>\n<p>Difference = {tex}\\frac{{11}}{5} &#8211; \\frac{7}{4}{\/tex} = {tex}\\frac{{11 \\times 4 &#8211; 7 \\times 5}}{{20}}{\/tex} [{tex}\\because {\/tex} L.C.M. of 5 and 4 is 20]\n<p>= {tex}\\frac{{44 &#8211; 35}}{{20}} = \\frac{9}{{20}}{\/tex} minutes<\/p>\n<p>Thus, Rahul takes less time, which is {tex}\\frac{9}{{20}}{\/tex} minutes.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_6_Maths_Exercise_76\"><\/span>NCERT Solutions for Class 6 Maths Exercise 7.6<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Mathematics_Class_3rd_to_12th\"><\/span>NCERT Solutions for Mathematics Class 3rd to 12th<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-12-mathematics\/\">NCERT Solutions for Class 12 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-11-mathematics\/\">NCERT Solutions for Class 11 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-maths\/\">NCERT Solutions for Class 10 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-maths\/\">NCERT Solutions for Class 9 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-8-mathematics\/\">NCERT Solutions for Class 8 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-7-mathematics\/\">NCERT Solutions for Class 7 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths\/\">NCERT Solutions for Class 6 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-5-mathematics\/\">NCERT Solutions for Class 5 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-4-mathematics\/\">NCERT Solutions for Class 4 Mathematics<\/a><\/li>\n<li><a href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-3-mathematics\/\">NCERT Solutions for Class 3 Mathematics<\/a><\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download NCERT Solutions for Class 6 Maths, Social Science Computer Science, Home Science, Hindi English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 6 Maths Exercise 7.6 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise &#8230; <a title=\"NCERT Solutions for Class 6 Maths Exercise 7.6\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-class-6-maths-exercise-7-6\/\" aria-label=\"More on NCERT Solutions for Class 6 Maths Exercise 7.6\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1395,281],"tags":[283,196,321,1485,216],"class_list":["post-4228","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-mathematics-cbse-class-06","category-ncert-solutions","tag-cbse-study-material","tag-class-6","tag-mathematics","tag-maths","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 6 Maths Exercise 7.6 | myCBSEguide<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 6 Maths Exercise 7.6 in PDF format for free download. 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