{"id":4143,"date":"2016-05-06T11:49:00","date_gmt":"2016-05-06T11:49:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/"},"modified":"2018-06-07T12:41:14","modified_gmt":"2018-06-07T07:11:14","slug":"ncert-solutions-for-class-9-science-gravitation-part-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/","title":{"rendered":"NCERT Solutions for Class 9 Science Gravitation part 2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#NCERT_Class_9_Science_Chapter_wise_Solutions\" >NCERT Class 9 Science Chapter wise Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#NCERT_Solutions_for_Class_9_Science_Gravitation_part_2\" >NCERT Solutions for Class 9 Science Gravitation part 2<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#1_How_does_the_force_of_gravitation_between_two_objects_change_when_the_distance_between_them_is_reduced_to_half\" >1. How does the force of gravitation between two objects change when the distance between them is reduced to half?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#2_Gravitational_force_acts_on_all_objects_in_proportion_to_their_masses_Why_then_a_heavy_object_does_not_fall_faster_than_a_light_object\" >2. Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#3_What_is_the_magnitude_of_the_gravitational_force_between_the_earth_and_a_1_kg_object_on_its_surface_Mass_of_the_earth_is_and_radius_of_the_earth_is\" >3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is and radius of the earth is.)<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#4_The_earth_and_the_moon_are_attracted_to_each_other_by_gravitational_force_Does_the_earth_attract_the_moon_with_a_force_that_is_greater_or_smaller_or_the_same_as_the_force_with_which_the_moon_attracts_the_earth_Why\" >4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#5_If_the_moon_attracts_the_earth_why_does_the_earth_not_move_towards_the_moon\" >5. If the moon attracts the earth, why does the earth not move towards the moon?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#6_What_happens_to_the_force_between_two_objects_if\" >6. What happens to the force between two objects, if<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#7_What_is_the_importance_of_universal_law_of_gravitation\" >7. What is the importance of universal law of gravitation?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#8_What_is_the_acceleration_of_free_fall\" >8. What is the acceleration of free fall?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#9_What_do_we_call_the_gravitational_force_between_the_earth_and_an_object\" >9. What do we call the gravitational force between the earth and an object?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#10_Amit_buys_few_grams_of_gold_at_the_poles_as_per_the_instruction_of_one_of_his_friends_He_hands_over_the_same_when_he_meets_him_at_the_equator_Will_the_friend_agree_with_the_weight_of_gold_bought_If_not_why_Hint_The_value_of_g_is_greater_at_the_poles_than_at_the_equator\" >10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [Hint: The value of g is greater at the poles than at the equator.]<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#11_Why_will_a_sheet_of_paper_fall_slower_than_one_that_is_crumpled_into_a_ball\" >11. Why will a sheet of paper fall slower than one that is crumpled into a ball?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#12_Gravitational_force_on_the_surface_of_the_moon_is_only_16_as_strong_as_gravitational_force_on_the_earth_What_is_the_weight_in_newtons_of_a_10_kg_object_on_the_moon_and_on_the_earth\" >12. Gravitational force on the surface of the moon is only 1\/6 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#13_A_ball_is_thrown_vertically_upwards_with_a_velocity_of_49_ms_Calculate\" >13. A ball is thrown vertically upwards with a velocity of 49 m\/s. Calculate<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#14_A_stone_is_released_from_the_top_of_a_tower_of_height_196_m_Calculate_its_final_velocity\" >14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#15_A_stone_is_thrown_vertically_upward_with_an_initial_velocity_of_40_ms_Taking_find_the_maximum_height_reached_by_the_stone_What_is_the_net_displacement_and_the_total_distance_covered_by_the_stone\" >15. A stone is thrown vertically upward with an initial velocity of 40 m\/s. Taking, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#16_Calculate_the_force_of_gravitation_between_the_earth_and_the_Sun_given_that_the_mass_of_the_and_of_the_The_average_distance_between_the_two_is\" >16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the and of the. The average distance between the two is.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#17_A_stone_is_allowed_to_fall_from_the_top_of_a_tower_100_m_high_and_at_the_same_time_another_stone_is_projected_vertically_upwards_from_the_ground_with_a_velocity_of_25_ms_Calculate_when_and_where_the_two_stones_will_meet\" >17. A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m\/s. Calculate when and where the two stones will meet.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#18_A_ball_thrown_up_vertically_returns_to_the_thrower_after_6_s_Find\" >18. A ball thrown up vertically returns to the thrower after 6 s. Find<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#19_In_what_direction_does_the_buoyant_force_on_an_object_immersed_in_a_liquid_act\" >19. In what direction does the buoyant force on an object immersed in a liquid act?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#20_Why_does_a_block_of_plastic_released_under_water_come_up_to_the_surface_of_water\" >20. Why does a block of plastic released under water come up to the surface of water?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-23\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#21_The_volume_of_50_g_of_a_substance_is_20_cm3_If_the_density_of_water_is_1_g_cm%E2%80%933_will_the_substance_float_or_sink\" >21. The volume of 50 g of a substance is 20 cm3. If the density of water is 1 g cm\u20133, will the substance float or sink?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-24\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#22_The_volume_of_a_500_g_sealed_packet_is_Will_the_packet_float_or_sink_in_water_if_the_density_of_water_is_1_g_cm%E2%80%933_What_will_be_the_mass_of_the_water_displaced_by_this_packet\" >22. The volume of a 500 g sealed packet is. Will the packet float or sink in water if the density of water is 1 g cm\u20133? What will be the mass of the water displaced by this packet?<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-25\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#NCERT_Solutions_for_Class_9_Science\" >NCERT Solutions for Class 9 Science<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-26\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/#CBSE_app_for_Class_9\" >CBSE app for Class 9<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 9 Science Gravitation part 2 Class 9 Science book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 9 Science chapter wise NCERT solution for Science Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Science\u00a0Gravitation <a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-09-science\/1218\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/09_Science_Book.jpg\" alt=\"NCERT Solutions for Class 9 Science Gravitation part 2\" width=\"185\" height=\"249\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Class_9_Science_Chapter_wise_Solutions\"><\/span><span class=\"underline-text\">NCERT Class 9 Science Chapter wise Solutions<\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li>01 \u2013 \u00a0Matter in Our Surroundings<\/li>\n<li>02 \u2013 Is Mattter Around us Pure<\/li>\n<li>03 \u2013 Atoms and Molecules<\/li>\n<li>04 \u2013 Structure of the Atom<\/li>\n<li>05 \u2013 The Fundamental Unit of Life<\/li>\n<li>06 \u2013 Tissues<\/li>\n<li>07 \u2013 Diversity in Living Organisms<\/li>\n<li>08 \u2013 Motion<\/li>\n<li>09 \u2013 Force and Laws of Motion<\/li>\n<li>10 \u2013 Gravitation<\/li>\n<li>11 \u2013 Word and Energy<\/li>\n<li>12 \u2013 Sound<\/li>\n<li>13 \u2013 Why Do We Fall Ill<\/li>\n<li>14 \u2013 Natural Resources<\/li>\n<li>15 \u2013 Improvement in Food Resources<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Science_Gravitation_part_2\"><\/span>NCERT Solutions for Class 9 Science Gravitation part 2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6><span class=\"ez-toc-section\" id=\"1_How_does_the_force_of_gravitation_between_two_objects_change_when_the_distance_between_them_is_reduced_to_half\"><\/span><strong>1. How does the force of gravitation between two objects change when the distance between them is reduced to half?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>The force of gravitation between two objects is inversely proportional to the square of the distance between them therefore the gravity will become four times if distance between them is reduced to half.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Gravitational_force_acts_on_all_objects_in_proportion_to_their_masses_Why_then_a_heavy_object_does_not_fall_faster_than_a_light_object\"><\/span><strong>2. Gravitational force acts on all objects in proportion to their masses. Why then, a heavy object does not fall faster than a light object?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In free fall of objects the acceleration in velocity due to gravity is independent of mass of those objects hence a heavy object does not fall faster than a light object.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_What_is_the_magnitude_of_the_gravitational_force_between_the_earth_and_a_1_kg_object_on_its_surface_Mass_of_the_earth_is_and_radius_of_the_earth_is\"><\/span><strong>3. What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is <img decoding=\"async\" style=\"height: 22px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image004.png\" \/>and radius of the earth is<img decoding=\"async\" style=\"height: 19px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image005.png\" \/>.)<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <img decoding=\"async\" style=\"height: 42px; width: 74px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image006.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 56px; width: 159px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image007.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 47px; width: 87px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image008.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 9.81 N<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_The_earth_and_the_moon_are_attracted_to_each_other_by_gravitational_force_Does_the_earth_attract_the_moon_with_a_force_that_is_greater_or_smaller_or_the_same_as_the_force_with_which_the_moon_attracts_the_earth_Why\"><\/span><strong>4. The earth and the moon are attracted to each other by gravitational force. Does the earth attract the moon with a force that is greater or smaller or the same as the force with which the moon attracts the earth? Why?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>The earth and the moon are attracted to each other by same gravitational force because for both of them formula to calculate force of attraction is the same<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 108px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image009.png\" \/><\/p>\n<p style=\"text-align: justify;\">d is also same for both.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_If_the_moon_attracts_the_earth_why_does_the_earth_not_move_towards_the_moon\"><\/span><strong>5. If the moon attracts the earth, why does the earth not move towards the moon?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Earth does not move towards moon because mass of moon is very small as compared to that of earth.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_What_happens_to_the_force_between_two_objects_if\"><\/span><strong>6. What happens to the force between two objects, if<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) the mass of one object is doubled?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) the distance between the objects is doubled and tripled?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(iii) the masses of both objects are doubled?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> the force between two objects will be doubled.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> the force between two objects will become 1\/4<sup>th<\/sup> and 1\/9<sup>th<\/sup> of the present force.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii)<\/strong> the force between two objects will become four times the present force.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_What_is_the_importance_of_universal_law_of_gravitation\"><\/span><strong>7. What is the importance of universal law of gravitation?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>The universal law of gravitation is important due to the following:<\/p>\n<p style=\"text-align: justify;\"><strong>i)<\/strong> this law explains well the force that binds us to earth.<\/p>\n<p style=\"text-align: justify;\"><strong>ii)<\/strong> this law describes the motion of planets around the sun.<\/p>\n<p style=\"text-align: justify;\"><strong>iii)<\/strong> this law justifies the tide formation on earth due to moon and sun.<\/p>\n<p style=\"text-align: justify;\"><strong>iv)<\/strong> this law gives reason for movement of moon around earth.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"8_What_is_the_acceleration_of_free_fall\"><\/span><strong>8. What is the acceleration of free fall?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>The acceleration of free fall is <img decoding=\"async\" style=\"height: 24px; width: 100px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image010.png\" \/>(on earth)<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"9_What_do_we_call_the_gravitational_force_between_the_earth_and_an_object\"><\/span><strong>9. What do we call the gravitational force between the earth and an object?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Weight<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"10_Amit_buys_few_grams_of_gold_at_the_poles_as_per_the_instruction_of_one_of_his_friends_He_hands_over_the_same_when_he_meets_him_at_the_equator_Will_the_friend_agree_with_the_weight_of_gold_bought_If_not_why_Hint_The_value_of_g_is_greater_at_the_poles_than_at_the_equator\"><\/span><strong>10. Amit buys few grams of gold at the poles as per the instruction of one of his friends. He hands over the same when he meets him at the equator. Will the friend agree with the weight of gold bought? If not, why? [<em>Hint<\/em>: The value of <em>g <\/em>is greater at the poles than at the equator.]<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Since <img decoding=\"async\" style=\"height: 22px; width: 79px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image003.png\" \/>and given in the question that value of g is greater at the poles than at the equator, hence weight of same amount of gold will be lesser at equator than it was on the poles. Therefore, the friend will not agree with the weight of gold bought.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"11_Why_will_a_sheet_of_paper_fall_slower_than_one_that_is_crumpled_into_a_ball\"><\/span><strong>11. Why will a sheet of paper fall slower than one that is crumpled into a ball?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>A greater surface area offers greater resistance and buoyancy same is true in the case of a sheet of paper that has larger surface area as compared to paper crumpled into a ball. So sheet of paper falls slower.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"12_Gravitational_force_on_the_surface_of_the_moon_is_only_16_as_strong_as_gravitational_force_on_the_earth_What_is_the_weight_in_newtons_of_a_10_kg_object_on_the_moon_and_on_the_earth\"><\/span><strong>12. Gravitational force on the surface of the moon is only 1\/6 as strong as gravitational force on the earth. What is the weight in newtons of a 10 kg object on the moon and on the earth?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>value of gravity on earth <img decoding=\"async\" style=\"height: 22px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image011.png\" \/><\/p>\n<p style=\"text-align: justify;\">value of gravity on moon = 1\/6<sup>th<\/sup> of earth = 9.8\/6 <img decoding=\"async\" style=\"height: 22px; width: 88px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image012.png\" \/><\/p>\n<p style=\"text-align: justify;\">weight of object on moon <img decoding=\"async\" style=\"height: 19px; width: 150px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image013.png\" \/>= 16.3 N<\/p>\n<p style=\"text-align: justify;\">weight of object on earth <img decoding=\"async\" style=\"height: 19px; width: 138px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image014.png\" \/>= 98 N<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"13_A_ball_is_thrown_vertically_upwards_with_a_velocity_of_49_ms_Calculate\"><\/span><strong>13. A ball is thrown vertically upwards with a velocity of 49 m\/s. Calculate<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) the maximum height to which it rises,<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) the total time it takes to return to the surface of the earth.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> v = u + gt<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 26px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image015.png\" \/><\/p>\n<p style=\"text-align: justify;\">9.8t = 49<\/p>\n<p style=\"text-align: justify;\">t = 49\/9.8 = 5 s<\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" style=\"height: 42px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image016.png\" \/><img decoding=\"async\" style=\"height: 42px; width: 143px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image017.png\" \/><\/strong>= 245 &#8211; 122.5 = 122.5<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> total time taken to return = 5 + 5 = 10 s<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"14_A_stone_is_released_from_the_top_of_a_tower_of_height_196_m_Calculate_its_final_velocity\"><\/span><strong>14. A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <img decoding=\"async\" style=\"height: 42px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image016.png\" \/><\/strong><\/p>\n<p style=\"text-align: justify;\">19.6 <img decoding=\"async\" style=\"height: 42px; width: 125px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image018.png\" \/><\/p>\n<p style=\"text-align: justify;\">4.9 <img decoding=\"async\" style=\"height: 22px; width: 64px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image019.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image020.png\" \/>= 4<\/p>\n<p style=\"text-align: justify;\">t = 2<\/p>\n<p style=\"text-align: justify;\">since v= u + at <img decoding=\"async\" style=\"height: 19px; width: 95px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image021.png\" \/>= 19.6 m\/s<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"15_A_stone_is_thrown_vertically_upward_with_an_initial_velocity_of_40_ms_Taking_find_the_maximum_height_reached_by_the_stone_What_is_the_net_displacement_and_the_total_distance_covered_by_the_stone\"><\/span><strong>15. A stone is thrown vertically upward with an initial velocity of 40 m\/s. Taking<img decoding=\"async\" style=\"height: 24px; width: 91px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image022.png\" \/>, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Initial velocity of stone (u) = 40 m\/s<\/p>\n<p style=\"text-align: justify;\">at maximum height stone will be at rest so v= 0<\/p>\n<p style=\"text-align: justify;\">v = u + gt<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 26px; width: 113px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image023.png\" \/><\/p>\n<p style=\"text-align: justify;\">10t = 40<\/p>\n<p style=\"text-align: justify;\">t = 40\/10 = 4 s<\/p>\n<p style=\"text-align: justify;\">distance covered \/maximum height<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image016.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 42px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image024.png\" \/>= 160 &#8211; 80 = 80 m<\/p>\n<p style=\"text-align: justify;\">net displacement of stone = 0(thrown upwards then falls back to same place)<\/p>\n<p style=\"text-align: justify;\">total distance covered by the stone = 80 + 80 = 160 m<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"16_Calculate_the_force_of_gravitation_between_the_earth_and_the_Sun_given_that_the_mass_of_the_and_of_the_The_average_distance_between_the_two_is\"><\/span><strong>16. Calculate the force of gravitation between the earth and the Sun, given that the mass of the <img decoding=\"async\" style=\"height: 22px; width: 150px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image025.png\" \/>and of the<img decoding=\"async\" style=\"height: 22px; width: 141px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image026.png\" \/>. The average distance between the two is<img decoding=\"async\" style=\"height: 19px; width: 96px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image027.png\" \/>.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>F = G <img decoding=\"async\" style=\"height: 27px; width: 21px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image028.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 56px; width: 215px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image029.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" style=\"height: 22px; width: 110px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image030.png\" \/><\/strong><\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"17_A_stone_is_allowed_to_fall_from_the_top_of_a_tower_100_m_high_and_at_the_same_time_another_stone_is_projected_vertically_upwards_from_the_ground_with_a_velocity_of_25_ms_Calculate_when_and_where_the_two_stones_will_meet\"><\/span><strong>17. A stone is allowed to fall from the top of a tower 100 m high and at the same time another stone is projected vertically upwards from the ground with a velocity of 25 m\/s. Calculate when and where the two stones will meet.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Suppose both the stones will meet after t seconds.<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 24px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\"><sup><img decoding=\"async\" style=\"height: 22px; width: 119px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image032.png\" \/><\/sup><\/p>\n<p style=\"text-align: justify;\">= 5t<sup>2<\/sup><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 24px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 26px; width: 155px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image033.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 82px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image034.png\" \/><\/p>\n<p style=\"text-align: justify;\">h + h\u2019 = 100 m<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 101px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image035.png\" \/>= 100<\/p>\n<p style=\"text-align: justify;\">25t = 100<\/p>\n<p style=\"text-align: justify;\">t = 4 s<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image036.png\" \/>= 80 m<\/p>\n<p style=\"text-align: justify;\">Therefore, the two stones will meet after 4 seconds when the falling stone would have covered a height of 80 m.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"18_A_ball_thrown_up_vertically_returns_to_the_thrower_after_6_s_Find\"><\/span><strong>18. A ball thrown up vertically returns to the thrower after 6 s. Find<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) the velocity with which it was thrown up,<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) the maximum height it reaches, and<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) its position after 4 s.<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (a)<\/strong>time taken by ball to reach maximum height(t) = 6\/2 = 3 s<\/p>\n<p style=\"text-align: justify;\">v = u + gt<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 26px; width: 121px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image037.png\" \/><\/p>\n<p style=\"text-align: justify;\">u = 29.4 m\/s (the velocity with which it was thrown up)<\/p>\n<p style=\"text-align: justify;\"><strong>(b)<\/strong> the maximum height it reaches: therefore <img decoding=\"async\" style=\"height: 24px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 26px; width: 169px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image038.png\" \/><\/p>\n<p style=\"text-align: justify;\">= 88.2 &#8211; 44.1<\/p>\n<p style=\"text-align: justify;\">= 44.1 m<\/p>\n<p style=\"text-align: justify;\"><strong>(c)<\/strong> its position after 4 s will be:<\/p>\n<p style=\"text-align: justify;\">Since in first 3 s it will reach the maximum height and in next 1 s it will start a free fall so, u = 0, t =1<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 24px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image031.png\" \/><\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 19px; width: 122px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image039.png\" \/>= 4.9 m<\/p>\n<p style=\"text-align: justify;\">therefore, after 4s the position of ball = 44.1 &#8211; 4.9 = 39.2 m<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"19_In_what_direction_does_the_buoyant_force_on_an_object_immersed_in_a_liquid_act\"><\/span><strong>19. In what direction does the buoyant force on an object immersed in a liquid act?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>In the upward direction only.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"20_Why_does_a_block_of_plastic_released_under_water_come_up_to_the_surface_of_water\"><\/span><strong>20. Why does a block of plastic released under water come up to the surface of water?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Since of plastic has density very less as compared to water i.e. weight of plastic is less than the buoyant force experienced by it therefore a block of plastic released under water come up to the surface of water\/floats.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 9 Science Gravitation part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"21_The_volume_of_50_g_of_a_substance_is_20_cm3_If_the_density_of_water_is_1_g_cm%E2%80%933_will_the_substance_float_or_sink\"><\/span><strong>21. The volume of 50 g of a substance is 20 cm3. If the density of water is 1 g cm<sup>\u20133<\/sup>, will the substance float or sink?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Density of that substance (d) = mass\/volume = 50\/20 = <img decoding=\"async\" style=\"height: 24px; width: 77px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image040.png\" \/><\/p>\n<p style=\"text-align: justify;\">since the density of substance (2.5) is greater than the density of water (1) therefore it will sink.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"22_The_volume_of_a_500_g_sealed_packet_is_Will_the_packet_float_or_sink_in_water_if_the_density_of_water_is_1_g_cm%E2%80%933_What_will_be_the_mass_of_the_water_displaced_by_this_packet\"><\/span><strong>22. The volume of a 500 g sealed packet is<img decoding=\"async\" style=\"height: 19px; width: 62px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image041.png\" \/>. Will the packet float or sink in water if the density of water is 1 g cm<sup>\u20133<\/sup>? What will be the mass of the water displaced by this packet?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Density of the packet = mass\/volume = 500\/350 <img decoding=\"async\" style=\"height: 24px; width: 104px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image042.png\" \/><\/p>\n<p style=\"text-align: justify;\">Since the density of packet is more than density of water so it will sink. And packet will displace water equal to its volume :<\/p>\n<p style=\"text-align: justify;\">volume of water displaced by packet <img decoding=\"async\" style=\"height: 22px; width: 70px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image043.png\" \/>(volume of packet)<\/p>\n<p style=\"text-align: justify;\">mass of water displaced = volume of water displaced <img decoding=\"async\" style=\"height: 14px; width: 12px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image044.png\" \/> density of water<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" style=\"height: 22px; width: 128px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/09\/science\/ch10\/image045.png\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_9_Science\"><\/span>NCERT Solutions for Class 9 Science<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 9 Science PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Science includes text book solutions .NCERT Solutions for CBSE Class 9 Science have total 15 chapters. 9 Science NCERT Solutions in PDF for free Download on our website. Ncert Science class 9 solutions PDF and Science ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Class_9\"><\/span>CBSE app for Class 9<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 9 Science, Computer Science, Home Science,Hindi ,English, Maths Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 9 Science Gravitation part 2 Class 9 Science book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class &#8230; <a title=\"NCERT Solutions for Class 9 Science Gravitation part 2\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-9-science-gravitation-part-2\/\" aria-label=\"More on NCERT Solutions for Class 9 Science Gravitation part 2\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":-1,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[281,1377],"tags":[283,1344,216,349],"class_list":["post-4143","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-ncert-solutions","category-science-cbse-class-09","tag-cbse-study-material","tag-class-9","tag-ncert-solutions","tag-science"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 9 Science Gravitation part 2<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 9 Science Gravitation part 2 in PDF format for free download. 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