{"id":4059,"date":"2016-05-06T11:49:00","date_gmt":"2016-05-06T06:19:00","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/"},"modified":"2023-03-22T17:13:07","modified_gmt":"2023-03-22T11:43:07","slug":"ncert-solutions-for-class-10-science-electricity-part-2","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/","title":{"rendered":"NCERT Solutions for Class 10 Science Electricity Part 2"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_76 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title\" style=\"cursor:inherit\">Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#NCERT_Class_10_Science_Chapter_wise_Solutions\" >NCERT Class 10 Science Chapter wise Solutions<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#NCERT_Solutions_for_Class_10_Science_Electricity_Part_2\" >NCERT Solutions for Class 10 Science Electricity Part 2<\/a><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><ul class='ez-toc-list-level-6' ><li class='ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#1_A_piece_of_wire_of_resistance_R_is_cut_into_five_equal_parts_These_parts_are_then_connected_in_parallel_If_the_equivalent_resistance_of_this_combination_is_R_then_the_ratio_RR_is\" >1. A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R\u2019, then the ratio R\/R\u2019 is:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#2_Which_of_the_following_terms_does_not_represent_electrical_power_in_a_circuit\" >2. Which of the following terms does not represent electrical power in a circuit?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#3_An_electric_bulb_is_rated_220_V_and_100_W_When_it_is_operated_on_110_V_the_power_consumed_will_be\" >3. An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#4_Two_conducting_wires_of_the_same_material_and_of_equal_lengths_and_equal_diameters_are_first_connected_in_series_and_then_parallel_in_a_circuit_across_the_same_potential_difference_The_ratio_of_heat_produced_in_series_and_parallel_combination_would_be\" >4. Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combination would be:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-7\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#5_How_is_a_voltmeter_connected_in_the_circuit_to_measure_the_potential_difference_between_two_points\" >5. How is a voltmeter connected in the circuit to measure the potential difference between two points?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-8\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#6_A_copper_wire_has_diameter_05_mm_and_resistivity_of_16_x_10-8_m_what_will_be_the_length_of_this_wire_to_make_its_resistance_10_How_much_does_the_resistance_change_if_the_diameter_is_doubled\" >6. A copper wire has diameter 0.5 mm and resistivity of 1.6 x 10-8 m. what will be the length of this wire to make its resistance 10? How much does the resistance change if the diameter is doubled?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-9\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#7_The_value_of_current_I_flowing_in_a_given_resistor_for_the_corresponding_values_of_potential_difference_V_across_the_resistor_are_given_below\" >7. The value of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-10\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#Plot_a_graph_between_V_and_I_and_calculate_the_resistance_of_that_resistor\" >Plot a graph between V and I and calculate the resistance of that resistor.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-11\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#8_When_a_12_v_battery_is_connected_across_an_unknown_resistor_there_is_a_current_of_25_mA_in_the_circuit_Find_the_value_of_the_resistance_of_the_resistor\" >8. When a 12 v battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-12\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#9_A_battery_of_9_V_is_connected_in_series_with_resistance_of_02_%CE%A9_03_%CE%A9_04_%CE%A9_05_%CE%A9_and_12_%CE%A9_respectively_How_much_current_would_flow_through_the_12_resistor\" >9. A battery of 9 V is connected in series with resistance of 0.2 \u03a9, 0.3 \u03a9, 0.4 \u03a9, 0.5 \u03a9 and 12 \u03a9 respectively. How much current would flow through the 12 resistor?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-13\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#10_How_many_176_%CE%A9_resistors_in_parallel_are_required_to_carry_5_A_on_a_220_V_line\" >10. How many 176 \u03a9 resistors (in parallel) are required to carry 5 A on a 220 V line?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-14\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#11_Show_how_you_would_connect_three_resistors_each_of_resistance_6_%CE%A9_so_that_the_combination_has_resistance_of_i_9_%CE%A9_ii_4_%CE%A9\" >11. Show how you would connect three resistors, each of resistance 6 \u03a9 so that the combination has resistance of (i) 9 \u03a9 (ii) 4 \u03a9.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-15\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#12_Several_electric_bulbs_designed_to_be_used_on_a_220_V_electric_supply_line_are_rated_10_W_How_many_lamps_can_be_connected_in_parallel_with_each_other_across_the_two_wires_of_220_V_line_if_the_maximum_allowable_current_is_5_A\" >12. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-16\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#13_A_hot_plate_of_an_electric_oven_connected_to_a_220_V_line_has_two_resistance_coils_A_and_B_Each_of_24_%CE%A9_resistances_which_may_be_used_separately_in_series_or_in_parallel_What_are_the_currents_in_the_three_cases\" >13. A hot plate of an electric oven connected to a 220 V line has two resistance coils A and B. Each of 24 \u03a9 resistances, which may be used separately, in series or in parallel. What are the currents in the three cases?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-17\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#14_Compare_the_power_used_in_the_2_%CE%A9_resistor_in_each_of_the_following_circuits\" >14. Compare the power used in the 2 \u03a9 resistor in each of the following circuits:<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-18\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#15_Two_lamps_one_rated_100_W_at_220_V_and_the_other_60_W_at_220_V_are_connected_in_parallel_to_electric_mains_supply_What_current_is_drawn_from_the_line_if_the_supply_voltage_is_220_V\" >15. Two lamps, one rated 100 W at 220 V, and the other 60 W at 220 V are connected in parallel to electric mains supply. What current is drawn from the line if the supply voltage is 220 V?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-19\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#16_Which_uses_more_energy_a_250_W_TV_set_in_1_hour_or_a_1200_W_toaster_in_10_minutes\" >16. Which uses more energy, a 250 W TV set in 1 hour, or a 1200 W toaster in 10 minutes?<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-20\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#17_An_electric_heater_of_resistance_8_draws_15_A_from_the_service_mains_for_2_hours_Calculate_the_rate_at_which_heat_is_developed_in_the_heater\" >17. An electric heater of resistance 8 draws 15 A from the service mains for 2 hours. Calculate the rate at which heat is developed in the heater.<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-6'><a class=\"ez-toc-link ez-toc-heading-21\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#18_Explain_the_following\" >18. Explain the following:<\/a><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-22\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#NCERT_Solutions_for_Class_10_Science\" >NCERT Solutions for Class 10 Science<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-23\" href=\"https:\/\/mycbseguide.com\/blog\/ncert-solutions-for-class-10-science-electricity-part-2\/#CBSE_app_for_Students\" >CBSE app for Students<\/a><\/li><\/ul><\/nav><\/div>\n<p>NCERT Solutions for Class 10 Science Electricity Part 2 Class 10 Science Class book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE Board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Science chapter wise NCERT solution for Science Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.<\/p>\n<p style=\"text-align: center;\"><strong>NCERT solutions for Class 10 Science\u00a0Electricity <a class=\"button\" href=\"https:\/\/mycbseguide.com\/downloads\/cbse-class-10-science\/1176\/ncert-solutions\/5\/\">Download as PDF<\/a><\/strong><\/p>\n<p><img loading=\"lazy\" decoding=\"async\" class=\"aligncenter\" src=\"https:\/\/media-mycbseguide.s3.ap-south-1.amazonaws.com\/images\/blog\/10%20Science%20Book.jpg\" alt=\"NCERT Solutions for Class 10 Science Electricity Part 2\" width=\"168\" height=\"207\" \/><\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Class_10_Science_Chapter_wise_Solutions\"><\/span><span class=\"underline-text\">NCERT Class 10 Science Chapter wise Solutions<\/span><span class=\"ez-toc-section-end\"><\/span><\/h2>\n<ul>\n<li>1 \u2013 Chemical Reactions and Equations<\/li>\n<li>2 \u2013 Acids, Bases and Salts<\/li>\n<li>3 \u2013 Metals and Non-metals<\/li>\n<li>4 \u2013 Carbon and Its Compounds<\/li>\n<li>5 \u2013 Periodic Classification of Elements<\/li>\n<li>6 \u2013 Life Processes<\/li>\n<li>7 \u2013 Control and Coordination<\/li>\n<li>8 \u2013 How do Organisms Reproduce?<\/li>\n<li>9 \u2013 Heredity and Evolution<\/li>\n<li>10 \u2013 Light Reflection and Refraction<\/li>\n<li>11 \u2013 Human Eye and Colourful World<\/li>\n<li>12 \u2013 Electricity<\/li>\n<li>13 \u2013 Magnetic Effects of Electric Current<\/li>\n<li>14 \u2013 Sources of Energy<\/li>\n<li>15 \u2013 Our Environment<\/li>\n<li>16 \u2013 Management of Natural Resources<\/li>\n<\/ul>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Science_Electricity_Part_2\"><\/span>NCERT Solutions for Class 10 Science Electricity Part 2<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<h6><span class=\"ez-toc-section\" id=\"1_A_piece_of_wire_of_resistance_R_is_cut_into_five_equal_parts_These_parts_are_then_connected_in_parallel_If_the_equivalent_resistance_of_this_combination_is_R_then_the_ratio_RR_is\"><\/span><strong>1. A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If the equivalent resistance of this combination is R\u2019, then the ratio R\/R\u2019 is:<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) 1\/25<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) 1\/5<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) 5<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(d) 25<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (d) <\/strong>25<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"2_Which_of_the_following_terms_does_not_represent_electrical_power_in_a_circuit\"><\/span><strong>2. Which of the following terms does not represent electrical power in a circuit?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) I<sup>2<\/sup>R<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) IR<sup>2<\/sup><\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) VI<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(d) V<sup>2<\/sup>\/R <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (b)<\/strong> IR<sup>2<\/sup><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"3_An_electric_bulb_is_rated_220_V_and_100_W_When_it_is_operated_on_110_V_the_power_consumed_will_be\"><\/span><strong>3. An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) 100 W<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) 75 W<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) 50 W<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(d) 25 W<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (d)<\/strong> 25 W<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"4_Two_conducting_wires_of_the_same_material_and_of_equal_lengths_and_equal_diameters_are_first_connected_in_series_and_then_parallel_in_a_circuit_across_the_same_potential_difference_The_ratio_of_heat_produced_in_series_and_parallel_combination_would_be\"><\/span><strong>4. Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combination would be: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) 1:2<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) 2:1<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) 1:4<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(d) 4:1<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (c)<\/strong> 1:4<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"5_How_is_a_voltmeter_connected_in_the_circuit_to_measure_the_potential_difference_between_two_points\"><\/span><strong>5. How is a voltmeter connected in the circuit to measure the potential difference between two points?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>A voltmeter is always connected in parallel to resistance across the point between which the potential difference is to be measured.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"6_A_copper_wire_has_diameter_05_mm_and_resistivity_of_16_x_10-8_m_what_will_be_the_length_of_this_wire_to_make_its_resistance_10_How_much_does_the_resistance_change_if_the_diameter_is_doubled\"><\/span><strong>6. A copper wire has diameter 0.5 mm and resistivity of 1.6 x 10-8 m. what will be the length of this wire to make its resistance 10? How much does the resistance change if the diameter is doubled? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Diameter of wire (d) = 0.5 mm, resistivity (\u03c1) 1.6 x 10<sup>-8<\/sup> \u03a9m, resistance (R) = 10 \u03a9.<\/p>\n<p style=\"text-align: justify;\">R = \u03c1L\/A<\/p>\n<p style=\"text-align: justify;\">L= \u03c0D<sup>2<\/sup>R\/4\u03c1<\/p>\n<p style=\"text-align: justify;\">= 22 x (5 x 10<sup>-4<\/sup>)<sup>2<\/sup>\/ 7 x 4 x 1.6 x 10<sup>-8<\/sup> = 122.5 m<\/p>\n<p style=\"text-align: justify;\">If the diameter is doubled for given length of given material resistance is inversely proportional to the cross-section area of wire.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"7_The_value_of_current_I_flowing_in_a_given_resistor_for_the_corresponding_values_of_potential_difference_V_across_the_resistor_are_given_below\"><\/span><strong>7. The value of current I flowing in a given resistor for the corresponding values of potential difference V across the resistor are given below: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong><img decoding=\"async\" id=\"Picture 25\" style=\"height: 69px; width: 538px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/science\/ch12\/image005.png\" \/><\/strong><\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"Plot_a_graph_between_V_and_I_and_calculate_the_resistance_of_that_resistor\"><\/span><strong>Plot a graph between V and I and calculate the resistance of that resistor.<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>From the given data the I-V graph is a straight line as shown below:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 26\" style=\"height: 205px; width: 205px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/science\/ch12\/image006.png\" \/><\/p>\n<p style=\"text-align: justify;\">Resistance of resistor (R) = V<sub>A<\/sub>-V<sub>B<\/sub>\/1<sub>A<\/sub>-1<sub>B<\/sub> = 12 V \u2013 6 V\/ 3.6 A \u2013 1.8 A<\/p>\n<p style=\"text-align: justify;\">= 6V\/ 1.8 A = 3.3 \u03a9<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"8_When_a_12_v_battery_is_connected_across_an_unknown_resistor_there_is_a_current_of_25_mA_in_the_circuit_Find_the_value_of_the_resistance_of_the_resistor\"><\/span><strong>8. When a 12 v battery is connected across an unknown resistor, there is a current of 2.5 mA in the circuit. Find the value of the resistance of the resistor. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Voltage of battery = V = 12 V, Current (I) = 2.5 mA = 2.5 x 10<sup>-3<\/sup> A<\/p>\n<p style=\"text-align: justify;\">Resistance (R) = V\/I = 12V\/ 2.5 x 10<sup>-3<\/sup> A = 4800 \u03a9.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"9_A_battery_of_9_V_is_connected_in_series_with_resistance_of_02_%CE%A9_03_%CE%A9_04_%CE%A9_05_%CE%A9_and_12_%CE%A9_respectively_How_much_current_would_flow_through_the_12_resistor\"><\/span><strong>9. A battery of 9 V is connected in series with resistance of 0.2 \u03a9, 0.3 \u03a9, 0.4 \u03a9, 0.5 \u03a9 and 12 \u03a9 respectively. How much current would flow through the 12 resistor? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Potential difference (V) = 9 V.<\/p>\n<p style=\"text-align: justify;\">Total resistance (R) = R<sub>1<\/sub>+ R<sub>2<\/sub>+ R<sub>3<\/sub>+R<sub>4<\/sub> +R<sub>5<\/sub><\/p>\n<p style=\"text-align: justify;\">= 0.2 +0.3 + 0.5 + 0.5 + 12 = 13.4 \u03a9<\/p>\n<p style=\"text-align: justify;\">Current in the circuit (I) = V\/R = 9 V \/ 13. 4 \u03a9 = 0.67 A.<\/p>\n<p style=\"text-align: justify;\">In series circuit same current flows through all the resistance, hence current of 0.67 A will flow through 12 \u03a9 resistor.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"10_How_many_176_%CE%A9_resistors_in_parallel_are_required_to_carry_5_A_on_a_220_V_line\"><\/span><strong>10. How many 176 \u03a9 resistors (in parallel) are required to carry 5 A on a 220 V line? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Let a resistor of 176 \u03a9 are joined in parallel. Then their combined resistance (R)<\/p>\n<p style=\"text-align: justify;\">1\/R = 1\/176 + 1\/176 \u2026\u2026 times = n\/176 or R = 176\/n \u03a9<\/p>\n<p style=\"text-align: justify;\">It is given that V= 220 V and I = 5 A<\/p>\n<p style=\"text-align: justify;\">R = V\/I or 176\/n = 220\/5 = 44 \u03a9<\/p>\n<p style=\"text-align: justify;\">n = 176\/44 = 4, 4 resistors should be joined in parallel.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"11_Show_how_you_would_connect_three_resistors_each_of_resistance_6_%CE%A9_so_that_the_combination_has_resistance_of_i_9_%CE%A9_ii_4_%CE%A9\"><\/span><strong>11. Show how you would connect three resistors, each of resistance 6 \u03a9 so that the combination has resistance of (i) 9 \u03a9 (ii) 4 \u03a9. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>It is given here that R<sub>1<\/sub> = R<sub>2<\/sub> = 6 \u03a9.<\/p>\n<p style=\"text-align: justify;\"><strong>(i)<\/strong> To get net resistance of 9 \u03a9 we should join three resistors as below:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 29\" style=\"height: 90px; width: 282px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/science\/ch12\/image007.png\" \/><\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> To get 4 \u03a9 net resistance we should join three resistors as below:<\/p>\n<p style=\"text-align: justify;\"><img decoding=\"async\" id=\"Picture 28\" style=\"height: 102px; width: 258px;\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/static\/ncert\/10\/science\/ch12\/image008.jpg\" \/><\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"12_Several_electric_bulbs_designed_to_be_used_on_a_220_V_electric_supply_line_are_rated_10_W_How_many_lamps_can_be_connected_in_parallel_with_each_other_across_the_two_wires_of_220_V_line_if_the_maximum_allowable_current_is_5_A\"><\/span><strong>12. Several electric bulbs designed to be used on a 220 V electric supply line, are rated 10 W. How many lamps can be connected in parallel with each other across the two wires of 220 V line if the maximum allowable current is 5 A? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Each bulb is rated as 10 W, 220 V, It draws a current (I) = P\/V = 10 W\/220 V<\/p>\n<p style=\"text-align: justify;\">= 1\/22 A.<\/p>\n<p style=\"text-align: justify;\">As the maximum allowable current is 5 A and all lamps are connected in parallel, hence maximum number of bulbs joined in parallel with each other = 5 x 22 = 110.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"13_A_hot_plate_of_an_electric_oven_connected_to_a_220_V_line_has_two_resistance_coils_A_and_B_Each_of_24_%CE%A9_resistances_which_may_be_used_separately_in_series_or_in_parallel_What_are_the_currents_in_the_three_cases\"><\/span><strong>13. A hot plate of an electric oven connected to a 220 V line has two resistance coils A and B. Each of 24 \u03a9 resistances, which may be used separately, in series or in parallel. What are the currents in the three cases? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>It is given that potential difference (V) = 220 V.<\/p>\n<p style=\"text-align: justify;\">Resistance of coil (A) = Resistance of coil (B) = 24 \u03a9<\/p>\n<p style=\"text-align: justify;\"><strong>(i) <\/strong>When either coil is used separately, the circuit (I) = V\/R = 220 V\/ 24 \u03a9<\/p>\n<p style=\"text-align: justify;\">= 9.2 A.<\/p>\n<p style=\"text-align: justify;\"><strong>(ii) <\/strong>When two coils are used in series total resistance (R)<\/p>\n<p style=\"text-align: justify;\">= R<sub>1<\/sub> + R<sub>2<\/sub> = 24 +24 = 48 \u03a9<\/p>\n<p style=\"text-align: justify;\">Current flowing (I) = V\/ R = 220 V\/ 48 \u03a9 = 4.6 A.<\/p>\n<p style=\"text-align: justify;\"><strong>(iii) <\/strong>When two coils are joined in parallel. Total resistance (R) = 1\/24 + 1\/24<\/p>\n<p style=\"text-align: justify;\">= 2\/24, R = 12 \u03a9.<\/p>\n<p style=\"text-align: justify;\">Current (I) = V\/R = 220 V \/ 12 \u03a9 = 18.3 A.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"14_Compare_the_power_used_in_the_2_%CE%A9_resistor_in_each_of_the_following_circuits\"><\/span><strong>14. Compare the power used in the 2 \u03a9 resistor in each of the following circuits: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(i) a 6-volt battery in series with 1 \u03a9 and 2 \u03a9 resistors and,<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(ii) a 4 V battery in parallel with 12 \u03a9 and \u03a9 resistors. <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans. (i)<\/strong> When a 2 \u03a9 resistor is joined t a 6 V battery in series with 1 \u03a9 and 2 \u03a9 resistors. Total resistance (R) = 2 + 1 + 2 = 5 \u03a9.<\/p>\n<p style=\"text-align: justify;\">Current (I) = 6 V\/5 \u03a9 = 1.2 A<\/p>\n<p style=\"text-align: justify;\">Power used in 2 A resistor = I<sup>2<\/sup>R = 2.88 W<\/p>\n<p style=\"text-align: justify;\"><strong>(ii)<\/strong> When 2 \u03a9 resistor is joined to a 4 V battery in parallel with 12 \u03a9 resistor and 2 \u03a9 resistors, the current flowing in 2 \u03a9 = 4 V\/ 2 \u03a9 = 2 A\/.<\/p>\n<p style=\"text-align: justify;\">Power used in 2 \u03a9 resistor = I<sup>2<\/sup>R = 8 W<\/p>\n<p style=\"text-align: justify;\">Ratio = 2.88\/8 = 0.36: 1.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"15_Two_lamps_one_rated_100_W_at_220_V_and_the_other_60_W_at_220_V_are_connected_in_parallel_to_electric_mains_supply_What_current_is_drawn_from_the_line_if_the_supply_voltage_is_220_V\"><\/span><strong>15. Two lamps, one rated 100 W at 220 V, and the other 60 W at 220 V are connected in parallel to electric mains supply. What current is drawn from the line if the supply voltage is 220 V?<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Current drawn by 1<sup>st<\/sup> lamp rated 100 W at 220 V = P\/V = 100\/ 220 = 5\/11 A.<\/p>\n<p style=\"text-align: justify;\">Current drawn by 2<sup>nd<\/sup> lamp rated 60 W at 220 V = 60\/220 = 3\/11 A.<\/p>\n<p style=\"text-align: justify;\">In parallel arrangement the total current = I1 +I2 = 3\/11+ 5\/11 = 8\/11 = 0.73 A.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"16_Which_uses_more_energy_a_250_W_TV_set_in_1_hour_or_a_1200_W_toaster_in_10_minutes\"><\/span><strong>16. Which uses more energy, a 250 W TV set in 1 hour, or a 1200 W toaster in 10 minutes? <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Energy used by a TV set of power 250 W in 1 hour = P x t = 250 Wh.<\/p>\n<p style=\"text-align: justify;\">Energy used by toaster of power 1200 W in 10 minute (10\/60 h)<\/p>\n<p style=\"text-align: justify;\">= P x t = 1200 W x 10\/60 h = 200 Wh.<\/p>\n<hr \/>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"17_An_electric_heater_of_resistance_8_draws_15_A_from_the_service_mains_for_2_hours_Calculate_the_rate_at_which_heat_is_developed_in_the_heater\"><\/span><strong>17. An electric heater of resistance 8 draws 15 A from the service mains for 2 hours. Calculate the rate at which heat is developed in the heater. <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>Ans. <\/strong>Resistance of electric heater (R) = 8 \u03a9, current (I) = 15 A.<\/p>\n<p style=\"text-align: justify;\">Rate at which heat developed in the heater = I<sup>2<\/sup>Rt\/t = 15 x 15 x 8 = 1800 W.<\/p>\n<hr \/>\n<p style=\"text-align: center;\">NCERT Solutions for Class 10 Science Electricity Part 2<\/p>\n<h6 style=\"text-align: justify;\"><span class=\"ez-toc-section\" id=\"18_Explain_the_following\"><\/span><strong>18. Explain the following: <\/strong><span class=\"ez-toc-section-end\"><\/span><\/h6>\n<p style=\"text-align: justify;\"><strong>(a) Why is the tungsten used almost exclusively for filament of electric lamps?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(b) Why are the conductors of electric heating devices, such as bread-toasters and electric irons, made of an alloy rather than a pure metal? <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(c) Why is the series arrangement not used for domestic circuits?<\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(d) How does the resistance of wire vary with its area of cross-section? <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>(e) Why are copper and aluminium wires usually employed for electric transmission? <\/strong><\/p>\n<p style=\"text-align: justify;\"><strong>Ans.<\/strong> <strong>(a) <\/strong>For filament of electric lamp we require a strong metal with high melting point. Tungsten is used exclusively for filament of electric lamps because its melting point is extremely high.<\/p>\n<p style=\"text-align: justify;\"><strong>(b) <\/strong>Conductors of electric heating devices are made of an alloy rather than a pure metal due to high resistivity than pure metal and high melting point to avoid getting oxidized at high temperature.<\/p>\n<p style=\"text-align: justify;\"><strong>(c) <\/strong>Series arrangement is not used for domestic circuits as current to all appliances remain same in spite of different resistance and every appliance cannot be switched on\/ off independently.<\/p>\n<p style=\"text-align: justify;\"><strong>(d) <\/strong>Resistance of a wire is inversely proportional to its cross-section area.<\/p>\n<p style=\"text-align: justify;\"><strong>(e) <\/strong>Copper and aluminium wires are usually employed for electricity transmission because they are good conductor with low resistivity. They are ductile also to be drawn into thin wires.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"NCERT_Solutions_for_Class_10_Science\"><\/span>NCERT Solutions for Class 10 Science<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>NCERT Solutions Class 10 Science PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Science includes text book solutions from Book. NCERT Solutions for CBSE Class 10 Science have total 16 chapters. 10 Science NCERT Solutions in PDF for free Download on our website. Ncert Science class 10 solutions PDF and Science ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.<\/p>\n<h2><span class=\"ez-toc-section\" id=\"CBSE_app_for_Students\"><\/span>CBSE app for Students<span class=\"ez-toc-section-end\"><\/span><\/h2>\n<p>To download\u00a0NCERT Solutions for class 10 Social Science, Computer Science, Home Science,Hindi ,English, Maths Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through\u00a0<a href=\"https:\/\/play.google.com\/store\/apps\/details?id=in.techchefs.MyCBSEGuide&amp;referrer=utm_source%3Dmycbse_bottom%26utm_medium%3Dtext%26utm_campaign%3Dmycbseads\"><strong>the best app for CBSE students<\/strong><\/a>\u00a0and myCBSEguide website.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Science Electricity Part 2 Class 10 Science Class book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE Board exam. 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