{"id":31887,"date":"2026-09-21T15:44:55","date_gmt":"2026-09-21T10:14:55","guid":{"rendered":"https:\/\/mycbseguide.com\/blog\/?p=31887"},"modified":"2026-09-21T16:08:10","modified_gmt":"2026-09-21T10:38:10","slug":"finding-the-unknown-ncert-solutions-class-7-maths-ganita-prakash","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/finding-the-unknown-ncert-solutions-class-7-maths-ganita-prakash\/","title":{"rendered":"Finding the Unknown – NCERT Solutions Class 7 Maths (Ganita Prakash)"},"content":{"rendered":"\n

Finding the Unknown<\/strong><\/strong> – NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash).<\/p>\n\n\n\n

NCERT Solutions Class 7<\/h2>\n\n\nEnglish Poorvi<\/a>\n\n\nHindi Malhar<\/a>\n\n\nMaths Ganita Prakash<\/a>\n\n\nScience Curiosity<\/a>\n\n\nSocial Exploring Society<\/a>\n\n\n\n

Finding the Unknown<\/strong><\/strong> \u2013 NCERT Solutions<\/h2>\n\n\n\n
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Q.1: Solve the equation and check the solution: {tex}3 x-10=35{\/tex}<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Step 1: Add 10 to both sides:
{tex} 3 x-10+10=35+10 \\Longrightarrow 3 x=45 {\/tex}
Step 2: Divide both sides by 3:
{tex} x=\\frac{45}{3}=15 {\/tex}
Check: {tex}3 \\times 15-10=45-10=35{\/tex}<\/p>\n\n\n\n

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Q.2: Solve the equation and check the solution: {tex}5 s=3 s{\/tex}<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Step 1: Subtract {tex}3 s{\/tex} from both sides:
{tex} 5 s-3 s=3 s-3 s \\Longrightarrow 2 s=0 {\/tex}
Step 2: Divide both sides by 2:
{tex} s=0 {\/tex}
Check: {tex}5 \\times 0=3 \\times 0{\/tex}, both sides are 0.<\/p>\n\n\n\n

\n\n\n\n

Q.3: Solve the equation and check the solution: {tex}3 u-7=2 u+3{\/tex}<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Step 1: Subtract {tex}2 u{\/tex} from both sides:
{tex} 3 u-2 u-7=2 u-2 u+3 \\Longrightarrow u-7=3 {\/tex}
Step 2: Add 7 to both sides:
{tex} u-7+7=3+7 \\Longrightarrow u=10 {\/tex}
Check: {tex}3 \\times 10-7=30-7=23,{\/tex} {tex}2 \\times 10+3=20+3=23{\/tex}<\/p>\n\n\n\n

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Q.4: Solve the equation and check the solution: {tex}4(m+6)-8=2 m-4{\/tex}<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Expand left:
{tex} 4 m+24-8=2 m-4 \\Longrightarrow 4 m+16=2 m-4 {\/tex}
Step 1: Subtract {tex}2 m{\/tex} from both sides:
{tex} 4 m-2 m+16=2 m-2 m-4{\/tex} {tex} \\Longrightarrow 2 m+16=-4 {\/tex}
Step 2: Subtract 16 from both sides:
{tex} 2 m+16-16=-4-16 \\Longrightarrow 2 m=-20 {\/tex}
Step 3: Divide by 2:
{tex} m=-10 {\/tex}
Check: {tex}4(-10+6)-8=4(-4)-8=-16-8{\/tex} {tex}=-24,2 \\times-10-4=-20-4=-24{\/tex}<\/p>\n\n\n\n

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Q.5: Solve the equation and check the solution: {tex}\\frac{u}{15}=6{\/tex}<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Multiply both sides by 15:
{tex} u=6 \\times 15=90 {\/tex}
Check: {tex}\\frac{90}{15}=6{\/tex}<\/p>\n\n\n\n

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Q.6: Write 5 equations whose solution is x = -2.<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

    \n
  1. {tex}x+2=0{\/tex}
    {tex}x=-2{\/tex}<\/li>\n\n\n\n
  2. {tex}3 x+6=0{\/tex}
    {tex}3 x=-6 \\Longrightarrow x=\\frac{-6}{3}=-2{\/tex}<\/li>\n\n\n\n
  3. {tex}2 x=-4{\/tex}
    {tex}x=\\frac{-4}{2}=-2{\/tex}<\/li>\n\n\n\n
  4. {tex}5 x+10=0{\/tex}
    {tex}5 x=-10 \\Longrightarrow x=\\frac{-10}{5}=-2{\/tex}<\/li>\n\n\n\n
  5. {tex}\\frac{x}{2}=-1{\/tex}
    {tex}x=-1 \\times 2=-2{\/tex}
    In each equation, substituting {tex}x=-2{\/tex} satisfies the equality.<\/li>\n<\/ol>\n\n\n\n
    \n\n\n\n

    Q.7: Find the value: {tex}2 y=60{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Divide both sides by 2:
    {tex} y=\\frac{60}{2}=30 {\/tex}
    {tex}2 \\times 30=60{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.8: Find the value: {tex}-8=5 x-3{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Add 3 to both sides:
    {tex} -8+3=5 x \\Longrightarrow-5=5 x {\/tex}
    Divide by 5 :
    {tex} x=\\frac{-5}{5}=-1 {\/tex}
    {tex}5 \\times-1-3=-5-3=-8{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.9: Find the value: {tex}-53 w=-15{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Divide both sides by -53:
    {tex} w=\\frac{-15}{-53}=\\frac{15}{53} {\/tex}
    {tex}-53 \\times \\frac{15}{53}=-15{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.10: Find the value: {tex} 13-z=8 {\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Subtract 13 from both sides:
    {tex} -z=8-13=-5 {\/tex}
    Multiply both sides by -1:
    {tex} z=5 {\/tex}
     {tex}13-5=8{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.11: Find the value: {tex}k+8=12-k{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Add {tex}k{\/tex} to both sides:
    {tex} k+k+8=12 \\Longrightarrow 2 k+8=12 {\/tex}
    Subtract 8 from both sides:
    {tex} 2 k=4 {\/tex}
    Divide by 2:
    {tex} k=2 {\/tex}
    {tex}2+8=10 ; 12-2=10 {\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.12: Find the value: {tex}7 m=m-3{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Subtract {tex}m{\/tex} from both sides:
    {tex} 7 m-m=-3 \\Longrightarrow 6 m=-3 {\/tex}
    Divide by 6:
    {tex} m=-\\frac{3}{6}=-\\frac{1}{2} {\/tex}
    {tex}7 \\times-\\frac{1}{2}=-\\frac{7}{2} ;-\\frac{1}{2}-3{\/tex} {tex}=-\\frac{1}{2}-\\frac{6}{2}=-\\frac{7}{2}{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.13: Find the value: {tex}3 n=10+n{\/tex}<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    Subtract {tex}n{\/tex} from both sides:
    {tex} 3 n-n=10 \\Longrightarrow 2 n=10 {\/tex}
    Divide by 2:
    {tex} n=5 {\/tex}
    {tex}3 \\times 5=15 ; 10+5=15 \\checkmark{\/tex}<\/p>\n\n\n\n

    \n\n\n\n

    Q.14: I am a 3-digit number. My hundred\u2019s digit is 3 less than my ten\u2019s digit. My ten\u2019s digit is 3 less than my unit\u2019s digit. The sum of all the three digits is 15. Who am I?<\/p>\n\n\n\n

    Solution:<\/p>\n\n\n\n

    The required 3-digit number is 258.<\/p>\n\n\n\n