{"id":31881,"date":"2026-09-17T17:30:38","date_gmt":"2026-09-17T12:00:38","guid":{"rendered":"https:\/\/mycbseguide.com\/blog\/?p=31881"},"modified":"2026-09-17T17:31:09","modified_gmt":"2026-09-17T12:01:09","slug":"another-peek-beyond-the-point-ncert-solutions-class-7-maths-ganita-prakash","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/another-peek-beyond-the-point-ncert-solutions-class-7-maths-ganita-prakash\/","title":{"rendered":"Another Peek Beyond the Point – NCERT Solutions Class 7 Maths (Ganita Prakash)"},"content":{"rendered":"\n

Another Peek Beyond the Point<\/strong><\/strong> – NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash).<\/p>\n\n\n\n

NCERT Solutions Class 7<\/h2>\n\n\nEnglish Poorvi<\/a>\n\n\nHindi Malhar<\/a>\n\n\nMaths Ganita Prakash<\/a>\n\n\nScience Curiosity<\/a>\n\n\nSocial Exploring Society<\/a>\n\n\n\n

Another Peek Beyond the Point<\/strong><\/strong> \u2013 NCERT Solutions<\/h2>\n\n\n\n
\n\n\n\n

Q.1: Recall that a tenth is 0.1, a hundredth is 0.01, and so on. Find the following products in tenths, hundredths and so on:<\/p>\n\n\n\n

    \n
  1. {tex} 6 \\times 4 \\text { tenths }=24 \\text { tenths } {\/tex}<\/li>\n\n\n\n
  2. {tex} 7 \\times 0.3 {\/tex}<\/li>\n\n\n\n
  3. {tex} 9 \\times 5 \\text { hundredths } {\/tex}<\/li>\n<\/ol>\n\n\n\n

    Solution:<\/p>\n\n\n\n

      \n
    1. Already given:
      {tex} 6 \\times 4 \\text { tenths }=24 \\text { tenths } {\/tex}
      Since 1 tenth {tex}=0.1{\/tex},
      {tex} 24 \\text { tenths }=24 \\times 0.1=2.4 {\/tex}\u00a0
      24 tenths {tex}=2.4{\/tex}<\/li>\n\n\n\n
    2. {tex} 7 \\times 0.3=7 \\times 3 \\text { tenths }=21 \\text { tenths } {\/tex}
      {tex} 21 \\text { tenths }=21 \\times 0.1=2.1 {\/tex}
      {tex}21 \\text { tenths = } 2.1 {\/tex}<\/li>\n\n\n\n
    3. {tex} 9 \\times 5 \\text { hundredths }=45 \\text { hundredths } {\/tex}
      {tex} 45 \\text { hundredths }=45 \\times 0.01=0.45 {\/tex}
      {tex}45 \\text { hundredths = } 0.45 {\/tex}<\/li>\n<\/ol>\n\n\n\n
      \n\n\n\n

      Q.2: Find the product:\u00a0{tex}27.34 \\times 6{\/tex}<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      {tex} 27.34 \\times 6=(27 \\times 6)+(0.34 \\times 6) {\/tex}
      {tex} =162+2.04=164.04 {\/tex}
      {tex} 27.34 \\times 6=164.04 {\/tex}<\/p>\n\n\n\n

      \n\n\n\n

      Q.3: Find the product:\u00a0 {tex} 4.23 \\times 3.7 {\/tex}<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Ignore decimals first: {tex}423 \\times 37=423 \\times(30+7){\/tex}
      {tex} 423 \\times 30=12690, 423 \\times 7=2961 {\/tex}
      {tex} 12690+2961=15651 {\/tex}
      Now count decimal places {tex}\\rightarrow(2{\/tex} in {tex}4.23+1{\/tex} in 3.7{tex})=3{\/tex} decimal places
      {tex} 15651 \\div 1000=15.651 {\/tex}
      {tex}4.23 \\times 3.7=15.651{\/tex}<\/p>\n\n\n\n

      \n\n\n\n

      Q.4: Find the product:\u00a0{tex}0.432 \\times 0.23{\/tex}<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Ignore decimals first: {tex}432 \\times 23=432 \\times(20+3){\/tex}
      {tex} 432 \\times 20=8640, 432 \\times 3=1296 {\/tex}
      {tex} 8640+1296=9936 {\/tex}
      Total decimal places {tex}\\rightarrow(3{\/tex} in {tex}0.432+2{\/tex} in 0.23{tex})=5{\/tex} decimal places
      {tex} 9936 \\div 100000=0.09936 {\/tex}
      Answer: {tex}0.432 \\times 0.23=0.09936{\/tex}<\/p>\n\n\n\n

      \n\n\n\n

      Q.5: Thejus needs 1.65 m of cloth for a shirt. How many metres of cloth are needed for 3 shirts?<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Each shirt needs 1.65 m of cloth.
      For 3 shirts:
      {tex} 1.65 \\times 3=4.95 {\/tex}
      Thejus needs 4.95 metres of cloth for 3 shirts.<\/p>\n\n\n\n

      \n\n\n\n

      Q.6: Meenu bought 4 notebooks and 3 erasers. The cost of each book was \u20b9 15.50 and each eraser was \u20b9 2.75. How much did she spend in all?<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Cost of 1 notebook {tex}=\u20b9 15.50{\/tex}
      Number of notebooks {tex}=4{\/tex}
      {tex} 4 \\times 15.50=62.00 {\/tex}
      Cost of 1 eraser {tex}=\u20b9 2.75{\/tex}
      Number of erasers = 3
      {tex} 3 \\times 2.75=8.25 {\/tex}
      Total cost {tex}=62.00+8.25=70.25{\/tex}
      Meenu spent \u20b9 70.25 in all.<\/p>\n\n\n\n

      \n\n\n\n

      Q.7: The thickness of a rupee coin is 1.45 mm. What is the total height of the cylinder formed by placing 36 rupee coins one over the other? Write the answer in centimeters.<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Thickness of one rupee coin {tex}=1.45 \\mathrm{~mm}{\/tex}
      Number of coins {tex}=36{\/tex}
      Total height in millimeters:
      {tex} 1.45 \\times 36=52.2 {~mm} {\/tex}
      Now, convert millimeters to centimeters:
      {tex} 1 {~cm}=10 {~mm} {\/tex}
      {tex} 52.2 {~mm}=52.2 \\div 10=5.22 {~cm} {\/tex}
      The total height of the cylinder is 5.22 cm.<\/p>\n\n\n\n

      \n\n\n\n

      Q.8: The price of 1 kg of oranges is \u20b9 56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Given: Price of 1 kg oranges {tex}=\u20b9 56.50{\/tex}
      Weight {tex}=2.250 \\mathrm{~kg}{\/tex}
      Step 1: {tex} 56.50 \\times 2.250=127.125 {\/tex}<\/strong>
      Total price = \u20b9 127.13 (rounded to two decimal places)
      Step 2: {tex} 56.50=56.5 \\text { and } 2.250=2.25 {\/tex}<\/strong>
      Adding or removing zeros after the decimal point does not change the value of a decimal number.
      If we multiply:
      {tex} 56.5 \\times 2.25=127.125 {\/tex}
      It gives the same product.
      Final Answer:
      Price of 2.250 kg oranges {tex}=\u20b9 127.13{\/tex}
      Yes, we can write 56.50 as 56.5 and 2.250 as 2.25 because trailing zeros after the decimal point do not change the value, and the product remains the same.<\/p>\n\n\n\n

      \n\n\n\n

      Q.9: Dwarakanath purchases notebooks at a wholesale price of \u20b9 23.6 per piece and sells each notebook at \u20b9 30\/-. How much profit does he make if he sells 50 books in a week?<\/p>\n\n\n\n

      Solution:<\/p>\n\n\n\n

      Cost price (C.P.) of 1 notebook {tex}=\u20b9 23.60{\/tex}
      Selling price (S.P.) of 1 notebook {tex}=\u20b9 30.00{\/tex}
      Step 1:<\/strong> Profit on 1 notebook
      Profit per notebook {tex}=30-23.6=6.4{\/tex}
      Step 2: <\/strong>Profit on 50 notebooks
      {tex} 6.4 \\times 50=320 {\/tex}
      Hence, Dwarakanath makes a profit of \u20b9320 by selling 50 notebooks in a week.<\/p>\n\n\n\n

      \n\n\n\n

      Q.10: Given that {tex}18 \\times 12=216{\/tex}, find the products:<\/p>\n\n\n\n

        \n
      1. {tex}18 \\times 1.2{\/tex}<\/li>\n\n\n\n
      2. {tex}18 \\times 0.12{\/tex}<\/li>\n\n\n\n
      3. {tex}1.8 \\times 1.2{\/tex}<\/li>\n\n\n\n
      4. {tex}0.18 \\times 0.12{\/tex}<\/li>\n\n\n\n
      5. {tex}0.018 \\times 0.012{\/tex}<\/li>\n\n\n\n
      6. {tex}1.8 \\times 12{\/tex}<\/li>\n<\/ol>\n\n\n\n

        In which of the cases above is the product less than 1?<\/p>\n\n\n\n

        Solution:<\/p>\n\n\n\n

          \n
        1. {tex} \\text { Since } 1.2=12 \\div 10_x {\/tex}
          {tex} 18 \\times 1.2=\\frac{18 \\times 12}{10}=\\frac{216}{10}=21.6 {\/tex}<\/li>\n\n\n\n
        2. {tex} \\text { Since } 0.12=12 \\div 100 \\text {, } {\/tex}
          {tex} 18 \\times 0.12=\\frac{18 \\times 12}{100}=\\frac{216}{100}=2.16 {\/tex}<\/li>\n\n\n\n
        3. {tex} \\text { Here } 1.8=18 \\div 10 \\text { and } 1.2=12 \\div 10 \\text {, } {\/tex}
          {tex} 1.8 \\times 1.2=\\frac{18 \\times 12}{100}=\\frac{216}{100}=2.16 {\/tex}<\/li>\n\n\n\n
        4. {tex} \\text { Here } 0.18=18 \\div 100 \\text { and } 0.12=12 \\div 100 {\/tex}
          {tex} 0.18 \\times 0.12=\\frac{18 \\times 12}{10000}=\\frac{216}{10000}=0.0216 {\/tex}<\/li>\n\n\n\n
        5. {tex} \\text { Here } 0.018=18 \\div 1000 \\text { and } 0.012=12 \\div 1000 \\text {, } {\/tex}
          {tex} 0.018 \\times 0.012=\\frac{18 \\times 12}{1000000}=\\frac{216}{1000000}=0.000216 {\/tex}<\/li>\n\n\n\n
        6. {tex} \\text { Here } 1.8=18 \\div 10 \\text {, } {\/tex}
          {tex} 1.8 \\times 12=\\frac{18 \\times 12}{10}=\\frac{216}{10}=21.6 {\/tex}<\/li>\n<\/ol>\n\n\n\n

          Products less than 1 are:
          {tex} 0.18 \\times 0.12=0.0216 {\/tex}
          {tex} 0.018 \\times 0.012=0.000216 {\/tex}<\/p>\n\n\n\n

          \n\n\n\n

          Q.11: In which of the following multiplications is the product less than 1? Can you find the answer without actually doing the multiplications?<\/p>\n\n\n\n

            \n
          1. {tex}7 \\times 0.6{\/tex}<\/li>\n\n\n\n
          2. {tex}0.7 \\times 0.6{\/tex}<\/li>\n\n\n\n
          3. {tex}0.7 \\times 6{\/tex}<\/li>\n\n\n\n
          4. {tex}0.07 \\times 0.06{\/tex}<\/li>\n<\/ol>\n\n\n\n

            Solution:<\/p>\n\n\n\n

              \n
            1. Here, {tex}7>1{\/tex} and {tex}0.6<1{\/tex}
              The large number dominates.
              {tex} 7 \\times 0.6=4.2>1 {\/tex}
              Product is greater than 1<\/li>\n\n\n\n
            2. Both numbers are less than 1
              Product of two numbers less than 1 is less than 1
              {tex} 0.7 \\times 0.6=0.42<1 {\/tex}
              Product is less than 1<\/li>\n\n\n\n
            3. {tex} 6>1 \\text { and } 0.7<1 {\/tex}
              {tex} 0.7 \\times 6=4.2>1 {\/tex}
              {tex} \\text { Product is greater than } 1 {\/tex}<\/li>\n\n\n\n
            4. Both are less than 1
              {tex} 0.07 \\times 0.06=0.0042<1 {\/tex}
              Product is less than 1<\/li>\n<\/ol>\n\n\n\n
              \n\n\n\n

              Q.12: Multiplying the following numbers by 10, 100 and 1000 to complete the table.<\/p>\n\n\n\n

               <\/td>{tex}\\times 10{\/tex}<\/td>{tex}\\times 100{\/tex}<\/td>{tex}\\times 1000{\/tex}<\/td><\/tr>
              5.7<\/td> <\/td> <\/td> <\/td><\/tr>
              23.02<\/td> <\/td> <\/td> <\/td><\/tr>
              0.92<\/td> <\/td> <\/td> <\/td><\/tr>
              0.306<\/td> <\/td> <\/td> <\/td><\/tr>
              24.67<\/td> <\/td> <\/td> <\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

              Solution:<\/p>\n\n\n\n

              Number<\/th>\u00d710<\/th>\u00d7100<\/th>\u00d71000<\/th><\/tr><\/thead>
              5.7<\/td>57<\/td>570<\/td>5700<\/td><\/tr>
              23.02<\/td>230.2<\/td>2302<\/td>23020<\/td><\/tr>
              0.92<\/td>9.2<\/td>92<\/td>920<\/td><\/tr>
              0.306<\/td>3.06<\/td>30.6<\/td>306<\/td><\/tr>
              24.67<\/td>246.7<\/td>2467<\/td>24670<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n