{"id":31874,"date":"2026-09-17T17:11:36","date_gmt":"2026-09-17T11:41:36","guid":{"rendered":"https:\/\/mycbseguide.com\/blog\/?p=31874"},"modified":"2026-09-17T17:12:18","modified_gmt":"2026-09-17T11:42:18","slug":"geometric-twins-ncert-solutions-class-7-maths-ganita-prakash","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/","title":{"rendered":"Geometric Twins &#8211; NCERT Solutions Class 7 Maths (Ganita Prakash)"},"content":{"rendered":"\n<p><strong><strong>Geometric Twins<\/strong><\/strong> &#8211; NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash).<\/p>\n\n\n\n<h2 class=\"wp-block-heading\">NCERT Solutions Class 7<\/h2>\n\n\n<a class=\"mks_button mks_button_small rounded\" href=\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/ncert-solutions-class-7\/ncert-solutions-class-7-english-poorvi\/\" target=\"_self\" style=\"color: #FFFFFF; background-color: #0066bf;\" >English Poorvi<\/a>\n\n\n<a class=\"mks_button mks_button_small rounded\" href=\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/ncert-solutions-class-7\/ncert-solutions-class-7-hindi-malhar\/\" target=\"_self\" style=\"color: #FFFFFF; background-color: #0066bf;\" >Hindi Malhar<\/a>\n\n\n<a class=\"mks_button mks_button_small rounded\" href=\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/ncert-solutions-class-7\/ncert-solutions-class-7-maths-ganita-prakash\/\" target=\"_self\" style=\"color: #FFFFFF; background-color: #0066bf;\" >Maths Ganita Prakash<\/a>\n\n\n<a class=\"mks_button mks_button_small rounded\" href=\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/ncert-solutions-class-7\/ncert-solutions-class-7-science-curiosity\/\" target=\"_self\" style=\"color: #FFFFFF; background-color: #0066bf;\" >Science Curiosity<\/a>\n\n\n<a class=\"mks_button mks_button_small rounded\" href=\"https:\/\/mycbseguide.com\/blog\/category\/ncert-solutions\/ncert-solutions-class-7\/ncert-solutions-class-7-social-exploring-society\/\" target=\"_self\" style=\"color: #FFFFFF; background-color: #0066bf;\" >Social Exploring Society<\/a>\n\n\n\n<h2 class=\"wp-block-heading\"><strong><strong>Geometric Twins<\/strong><\/strong> \u2013 NCERT Solutions<\/h2>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.1: Check if the two figures are congruent.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762843793-bcfke7.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Yes, the two figures are <strong>congruent<\/strong>, because their <strong>angles and sides (arms)<\/strong> are equal in measure.<br>They may appear as mirror images, but that does <strong>not<\/strong> affect congruence &#8211; reflection still preserves size and shape.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.2: Circle the pairs that appear congruent.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762844105-af8ubk.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<figure class=\"wp-block-image\"><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762844482-kbabby.jpg\" alt=\"\"\/><\/figure>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.3: What measurements would you take to create a figure congruent to a given:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>Circle<\/li>\n\n\n\n<li>Rectangle<\/li>\n<\/ol>\n\n\n\n<p>Using this, state how would you check if two\u2009\u2014<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>Circles are congruent?<\/li>\n\n\n\n<li>Rectangles are congruent?<\/li>\n<\/ol>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p><strong>To create a congruent figure:<\/strong><\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Circle:<\/strong> Measure the <strong>radius<\/strong>. The new circle should have the <strong>same radius<\/strong>.<\/li>\n\n\n\n<li><strong>Rectangle:<\/strong> Measure the <strong>length<\/strong> and <strong>breadth<\/strong>. The new rectangle should have the <strong>same length and breadth<\/strong>.<\/li>\n<\/ol>\n\n\n\n<p><strong>To check if two figures are congruent:<\/strong><\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li><strong>Circles:<\/strong> Two circles are congruent if they have the <strong>same radius<\/strong>.<\/li>\n\n\n\n<li><strong>Rectangles:<\/strong> Two rectangles are congruent if their <strong>lengths and breadths are equal<\/strong>.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.4: Suppose {tex}\\triangle \\mathrm{HEN}{\/tex} is congruent to {tex}\\triangle \\mathrm{BIG}{\/tex}. List all the other correct ways of expressing this congruence.<\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>If {tex}\\triangle H E N \\cong \\triangle B I G{\/tex}, the order of letters shows the correspondence between vertices:<br>{tex} H \\leftrightarrow B, E \\leftrightarrow I \\text {, and } N \\leftrightarrow G \\text {. } {\/tex}<br>So, all other correct ways of expressing this congruence are:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>{tex}\\triangle E N H \\cong \\triangle I G B{\/tex}<\/li>\n\n\n\n<li>{tex}\\triangle N H E \\cong \\triangle G B I{\/tex}<\/li>\n\n\n\n<li>{tex}\\triangle H N E \\cong \\triangle B G I{\/tex}<\/li>\n\n\n\n<li>{tex}\\triangle N E H \\cong \\triangle G I B{\/tex}<\/li>\n\n\n\n<li>{tex}\\triangle E H N \\cong \\triangle I B G{\/tex}<\/li>\n<\/ol>\n\n\n\n<p>Each pair keeps the correct correspondence of vertices ({tex}H \\rightarrow B, E \\rightarrow I, N \\rightarrow G{\/tex}).<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.5: Determine whether the triangles are congruent. If yes, express the congruence.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762845264-9v65mk.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Let&#8217;s compare the sides of the two triangles:<br>In {tex}\\triangle \\mathrm{RED}{\/tex}:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>{tex}\\mathrm{RE}=3.5 \\mathrm{~cm}{\/tex}<\/li>\n\n\n\n<li>{tex}\\mathrm{ED}=5 \\mathrm{~cm}{\/tex}<\/li>\n\n\n\n<li>{tex}\\mathrm{RD}=6 \\mathrm{~cm}{\/tex}<\/li>\n<\/ul>\n\n\n\n<p>In {tex}\\triangle \\mathrm{JAM}{\/tex}:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>{tex}\\mathrm{JA}=3.5 \\mathrm{~cm}{\/tex}<\/li>\n\n\n\n<li>{tex}\\mathrm{AM}=5 \\mathrm{~cm}{\/tex}<\/li>\n\n\n\n<li>{tex}J M=6 \\mathrm{~cm}{\/tex}<\/li>\n<\/ul>\n\n\n\n<p>The three corresponding sides are equal:<br>{tex}R E=J A, E D=A M, R D=J M{\/tex}<br>Therefore, the two triangles are congruent by SSS (Side-Side-Side) criterion.<br><strong>Congruence statement:<\/strong><br>{tex} \\triangle R E D \\cong \\triangle J A M {\/tex}<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.6: In the figure below, are {tex}\\triangle \\mathrm{DFE} \\text { and } \\triangle \\mathrm{GED}{\/tex} congruent to each other? It is given that DF = DG and FE = GE.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762846202-wy2z4g.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Yes, triangles {tex}\\triangle \\mathrm{DFE}{\/tex} and {tex}\\triangle \\mathrm{GED}{\/tex} are congruent to each other. This can be proved using the Side-Side-Side (SSS) congruence criterion.<br>Reasoning<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>It is given that {tex}D F=D G{\/tex} and {tex}F E=G E{\/tex}<\/li>\n\n\n\n<li>Both triangles share the side {tex}D E{\/tex}, which is common to both triangles<\/li>\n\n\n\n<li>Thus, the three sides of triangle {tex}\\triangle \\mathrm{DFE}{\/tex} are respectively equal to the three sides of triangle {tex}\\triangle \\mathrm{GED}{\/tex}:<\/li>\n\n\n\n<li>{tex}D F=D G{\/tex}<\/li>\n\n\n\n<li>{tex}D E=D E{\/tex} (common side)\u00a0<\/li>\n\n\n\n<li>{tex}F E=G E{\/tex}<\/li>\n<\/ul>\n\n\n\n<p>By the SSS congruence rule, if the three sides of one triangle are equal to the three sides of another triangle, then the triangles are congruent.<br>Conclusion<br>Triangles {tex}\\triangle \\mathrm{DFE}{\/tex} and {tex}\\triangle \\mathrm{GED}{\/tex} are congruent by SSS criterion.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.7: Identify whether the triangles below are congruent. What conditions did you use to establish their congruence? Express the congruence.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762850467-hqpmvp.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Yes, the triangles shown in the image &#8211; triangle {tex}\\triangle A B C{\/tex} and triangle {tex}\\triangle X Y Z-{\/tex} are congruent to each other.<br><strong>Conditions for Congruence<\/strong><br>The given conditions are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>{tex}A B=X Z=7 \\mathrm{~cm}{\/tex} {tex}\\square{\/tex}\u00a0<\/li>\n\n\n\n<li>{tex}B C=Y Z=5 \\mathrm{~cm}{\/tex} {tex}\\bigcirc{\/tex}\u00a0<\/li>\n\n\n\n<li>Angle {tex}B=\\angle Y=47^{\\circ}{\/tex}<\/li>\n<\/ul>\n\n\n\n<p>These satisfy the SAS (Side-Angle-Side) congruence criterion, which states that if two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle, then the triangles are congruent.<br><strong>Expressing the Congruence<\/strong><br>Triangles are congruent as follows:<br>{tex} \\triangle A B C \\cong \\triangle X Y Z {\/tex}<br>by the SAS criterion.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.8: Given that CD and AB are parallel, and AB = CD, what are the other equal parts in this figure? (<strong>Hint: <\/strong>When the lines are parallel, the alternate angles are equal. Are the two resulting triangles congruent? If so, express the congruence.)<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762850565-zpp5xv.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>First, {tex}A B{\/tex} and {tex}C D{\/tex} are parallel lines, and their lengths are equal ({tex}A B=C D{\/tex}).<\/li>\n\n\n\n<li>When two lines are parallel, the alternate interior angles between them and a transversal are also equal.<\/li>\n\n\n\n<li>The side that connects {tex}A B{\/tex} to {tex}C D{\/tex} (the transversal) is the same for both triangles, so it is a common side.<\/li>\n\n\n\n<li>Now, both triangles have two equal sides and the angle between them equal (by the SAS rule).<\/li>\n\n\n\n<li>Therefore, the triangles are congruent, meaning they are equal in size and shape.<\/li>\n\n\n\n<li>We write this as: {tex}\\triangle A B C \\cong \\triangle D C B{\/tex} (depending on the figure&#8217;s points).<\/li>\n<\/ol>\n\n\n\n<p>This method uses the SAS (Side-Angle-Side) congruence rule.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.9: Identify the equal parts in the following figure, given that {tex}\\angle \\mathrm{ABD}= \\angle \\mathrm{DCA}{\/tex} and {tex}\\angle \\mathrm{ACB}=\\angle \\mathrm{DBC}{\/tex}.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762852038-hsb3fn.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>In the figure, the given equal parts are:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>{tex}\\angle A B D=\\angle D C A{\/tex} (given).<\/li>\n\n\n\n<li>{tex}\\angle A C B=\\angle D B C{\/tex} (given).<br>These are pairs of equal angles in triangles {tex}A B D{\/tex} and {tex}D C A{\/tex}.<br>Equal Parts Identified<\/li>\n\n\n\n<li>Angle {tex}A B D{\/tex} in triangle {tex}A B D{\/tex} is equal to angle {tex}D C A{\/tex} in triangle {tex}D C A{\/tex}.<\/li>\n\n\n\n<li>Angle {tex}A C B{\/tex} in triangle {tex}A C B{\/tex} is equal to angle {tex}D B C{\/tex} in triangle {tex}D B C{\/tex}.<\/li>\n<\/ul>\n\n\n\n<p>If lines {tex}A B{\/tex} and {tex}C D{\/tex} intersect at interior points, the equal angles make the two triangles similar, but not necessarily congruent unless the sides are also equal.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.10: Each of the following cases contains certain measurements taken from two triangles. Identify the pairs in which the triangles are congruent to each other, with reason. Express the congruence whenever they are congruent.<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>{tex} {AB}={DE} {\/tex}<br>{tex} {BC}={EF} {\/tex}<br>{tex} {CA}={DF} {\/tex}<\/li>\n\n\n\n<li>{tex} {AB}={EF} {\/tex}<br>{tex} \\angle {~A}=\\angle {E} {\/tex}<br>{tex} {AC}={ED} {\/tex}<\/li>\n\n\n\n<li>{tex} {AB}={DF} {\/tex}<br>{tex} \\angle {~B}=\\angle {D}=90^{\\circ} {\/tex}<br>{tex} {AC}={FE} {\/tex}<\/li>\n\n\n\n<li>{tex} \\angle {A} =\\angle {D} {\/tex}<br>{tex} \\angle {~B} =\\angle {E} {\/tex}<br>{tex} {AC} ={DF} {\/tex}<\/li>\n\n\n\n<li>{tex} {AB}={DF} {\/tex}<br>{tex} \\angle {~B}=\\angle {F} {\/tex}<br>{tex} {AC}={DE} {\/tex}<\/li>\n<\/ol>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>{tex}A B=D E, B C=E F, C A=D F{\/tex}<br>&#8211; All three corresponding sides are equal.<br>&#8211; Congruence by SSS criterion.<br>&#8211; Express: {tex}\\triangle A B C \\cong \\triangle D E F{\/tex}. image.jpg<\/li>\n\n\n\n<li>{tex}A B=E F, \\angle A=\\angle E, A C=E D{\/tex}<br>&#8211; Two sides and the included angle are equal.<br>&#8211; Congruence by SAS criterion.<br>&#8211; Express: {tex}\\triangle A B C \\cong \\triangle E F D{\/tex}. image.jpg<\/li>\n\n\n\n<li>{tex}A B=D F, \\angle B=\\angle D=90^{\\circ}, A C=F E{\/tex}<br>&#8211; Hypotenuse and one side of right triangle equal.<br>&#8211; Congruence by RHS criterion (Right angle-Hypotenuse-Side).<br>&#8211; Express: {tex}\\triangle A B C \\cong \\triangle D F E{\/tex}. image.jpg<\/li>\n\n\n\n<li>{tex}\\angle A=\\angle D, \\angle B=\\angle E, A C=D F{\/tex}<br>&#8211; Two angles and the side between them are equal.<br>&#8211; Congruence by ASA criterion.<br>&#8211; Express: {tex}\\triangle A B C \\cong \\triangle D E F{\/tex}.<\/li>\n\n\n\n<li>{tex}A B=D F, \\angle B=\\angle F, A C=D E{\/tex}<br>&#8211; Two sides and a non-included angle are given.<br>&#8211; Not necessarily congruent (no rule applies here directly).<br>&#8211; Not Congruent.<\/li>\n<\/ol>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.11: It is given that OB = OC, and OA = OD. Show that AB is parallel to CD.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762854149-sc8u8q.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>Given: {tex}O B=O C{\/tex} and {tex}O A=O D{\/tex}.\u00a0<\/li>\n\n\n\n<li>Triangles {tex}O B A{\/tex} and {tex}O C D{\/tex} :<br>In triangle OBA : sides {tex}O B{\/tex} and {tex}O A{\/tex}.<br>In triangle {tex}O C D{\/tex} : sides {tex}O C{\/tex} and {tex}O D{\/tex}.<br>These pairs are equal by given information.<\/li>\n\n\n\n<li>{tex}A D{\/tex} acts as a transversal to {tex}A B{\/tex} and {tex}C D{\/tex}.<\/li>\n\n\n\n<li>Alternate Angles:\n<ul class=\"wp-block-list\">\n<li>In both triangles, angle {tex}O B A{\/tex} equals angle {tex}O C D{\/tex} (since triangles OBA and OCD have two pairs of equal sides including one common angle at O).<\/li>\n\n\n\n<li>Therefore, alternate interior angles formed by {tex}A B{\/tex} and {tex}C D{\/tex} with transversal {tex}A D{\/tex} are equal.<\/li>\n<\/ul>\n<\/li>\n\n\n\n<li>Conclusion:<br>Because alternate angles are equal, by the property of parallel lines, {tex}A B{\/tex} is parallel to {tex}C D{\/tex}.<\/li>\n<\/ol>\n\n\n\n<p>So, with {tex}\\mathrm{OB}=\\mathrm{OC}, \\mathrm{OA}=\\mathrm{OD}{\/tex}, and equal alternate angles formed by the transversal AD, it is proved that {tex}A B \\| C D{\/tex}.&nbsp;<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.12: ABCD is a square. Show that {tex}\\triangle \\mathrm{ABC} \\cong \\triangle \\mathrm{ADC}{\/tex}. Is {tex}\\triangle \\mathrm{ABC}{\/tex} also congruent to {tex}\\triangle C D A{\/tex}?<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762854611-s8s3az.jpg\"><br>Give more examples of two triangles where one triangle is congruent to the other in two different ways, as in the case above. Can you give an example of two triangles where one is congruent to the other in six different ways?<\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Examples of Two Triangles Congruent in Two Different Ways<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>In a Rectangle:<br>Draw a diagonal in a rectangle PQRS.<br>Triangles {tex}\\triangle P Q S{\/tex} and {tex}\\triangle Q R S{\/tex} are congruent by SSS.<br>Also, they are congruent by SAS (since the diagonal and two sides are equal).<\/li>\n\n\n\n<li>In an Equilateral Triangle:<br>Draw median AM in {tex}\\triangle A B C{\/tex} where all sides are equal.<br>Triangles {tex}\\triangle A B M{\/tex} and {tex}\\triangle A C M{\/tex} are congruent by SSS (side AM is common, sides {tex}\\mathrm{AB}={\/tex} AC, and {tex}\\mathrm{BM}=\\mathrm{CM}{\/tex} as medians of an equilateral triangle).<br>Also, they are congruent by SAS (AM, angle at A, and AB = AC).<\/li>\n<\/ol>\n\n\n\n<p>Showing {tex}\\triangle A B C \\cong \\triangle A D C{\/tex}<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>ABCD is a square, so all sides are equal: {tex}A B=B C=C D=D A{\/tex}.<\/li>\n\n\n\n<li>Diagonal AC is common for both triangles.<\/li>\n\n\n\n<li>Angles at B and D are right angles ({tex}90^{\\circ}{\/tex} each).<\/li>\n\n\n\n<li>So, triangles {tex}A B C{\/tex} and {tex}A D C{\/tex} have:<br>{tex}A B=A D{\/tex} (square sides)<br>{tex}B C=D C{\/tex} (square sides)<br>{tex}A C{\/tex} (common side)<\/li>\n\n\n\n<li>By SSS (Side-Side-Side) criterion, {tex}\\triangle A B C \\cong \\triangle A D C{\/tex}.<br>{tex}\\triangle A B C{\/tex} is also congruent to {tex}\\triangle C D A{\/tex}, because the parts correspond exactly as above due to the symmetric nature of a square.<\/li>\n<\/ol>\n\n\n\n<p>So, {tex}\\triangle A B C \\cong \\triangle C D A{\/tex} by SSS.<br>{tex}\\triangle A B C \\cong \\triangle A D C{\/tex} (SSS criterion).&nbsp;<br>Yes, {tex}\\triangle A B C{\/tex} is also congruent to {tex}\\triangle C D A{\/tex}.<\/p>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.13: Find {tex}\\angle \\mathrm{B}{\/tex} and {tex}\\angle \\mathrm{C}{\/tex}, if A is the centre of the circle.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762855281-euv7tk.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<p>Given: {tex}A{\/tex} is the center of the circle and {tex}\\angle B A C=120^{\\circ}{\/tex}.<br>To Find: {tex}\\angle B{\/tex} and {tex}\\angle C{\/tex}<br>Since {tex}A{\/tex} is the center, {tex}A B{\/tex} and {tex}A C{\/tex} are radii, so the triangle {tex}B A C{\/tex} is isosceles with {tex}A B=A C{\/tex}.<br>Let us use the properties:<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>The sum of angles in any triangle is {tex}180^{\\circ}{\/tex}.<\/li>\n\n\n\n<li>\u00a0Let {tex}x{\/tex} be the value of {tex}\\angle B{\/tex} and {tex}\\angle C{\/tex} (since triangle is isosceles).<\/li>\n<\/ul>\n\n\n\n<p>So,<br>{tex} \\angle B A C+\\angle B+\\angle C=180^{\\circ} {\/tex}<br>{tex} 120^{\\circ}+x+x=180^{\\circ} {\/tex}<br>{tex} 2 x=60^{\\circ} {\/tex}<br>{tex} x=30^{\\circ} {\/tex}<\/p>\n\n\n\n<ul class=\"wp-block-list\">\n<li>{tex}\\angle B=30^{\\circ}{\/tex}<\/li>\n\n\n\n<li>{tex}\\angle C=30^{\\circ}{\/tex}<\/li>\n<\/ul>\n\n\n\n<hr class=\"wp-block-separator has-alpha-channel-opacity\"\/>\n\n\n\n<p>Q.14: Find the missing angles. As per the convention that we have been following, all line segments marked with a single \u2018|\u2019 are equal to each other and those marked with a double \u2018|\u2019 are equal to each other, etc.<br><img decoding=\"async\" src=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762855451-x32zxb.jpg\"><\/p>\n\n\n\n<p>Solution:<\/p>\n\n\n\n<ol start=\"1\" class=\"wp-block-list\">\n<li>Identify isosceles triangles by equal line markings.<br>Base angles of isosceles triangles are equal.<\/li>\n\n\n\n<li>Use the sum of angles in a triangle:<br>{tex}\\angle 1+\\angle 2+\\angle 3=180^{\\circ}{\/tex}<\/li>\n\n\n\n<li>Work systematically:<br>For each triangle, use given angles plus your equal side marker clues to solve for unknown angles.<\/li>\n<\/ol>\n\n\n\n<p>Examples:<br><strong>Triangle URK:<\/strong><br>{tex}R U=U K, \\angle U K R=34^{\\circ}{\/tex} (given).<br>The base angles at {tex}U{\/tex} and {tex}R{\/tex} are equal, let them be {tex}x{\/tex}.<br>{tex}x+x+34^{\\circ}=180^{\\circ}{\/tex}<br>{tex}2 x=146^{\\circ} \\Longrightarrow x=73^{\\circ}{\/tex}<br>So, {tex}\\angle K U R=\\angle K R U=73^{\\circ}{\/tex}.<br><strong>Triangle KUL:<\/strong><br>If you have a right angle at K or L, and another angle is given, use {tex}180^{\\circ}{\/tex} total for the triangle.<br>For example:<br>{tex}\\angle K U L=56^{\\circ}, \\angle U K L=90^{\\circ}{\/tex}, then<br>{tex}\\angle L K U=180^{\\circ}-56^{\\circ}-90^{\\circ}=34^{\\circ}{\/tex}.<br>Repeat for all triangles in the figure using these steps.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Geometric Twins &#8211; NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash). NCERT Solutions Class 7 Geometric Twins \u2013 NCERT Solutions Q.1: Check if the two figures are congruent. Solution: Yes, the two figures are congruent, because their angles and sides (arms) &#8230; <a title=\"Geometric Twins &#8211; NCERT Solutions Class 7 Maths (Ganita Prakash)\" class=\"read-more\" href=\"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/\" aria-label=\"More on Geometric Twins &#8211; NCERT Solutions Class 7 Maths (Ganita Prakash)\">Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[281,2082,2106],"tags":[216],"class_list":["post-31874","post","type-post","status-publish","format-standard","hentry","category-ncert-solutions","category-ncert-solutions-class-7","category-ncert-solutions-class-7-maths-ganita-prakash","tag-ncert-solutions"],"yoast_head":"<!-- This site is optimized with the Yoast SEO plugin v26.0 - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Geometric Twins - NCERT Solutions Class 7 Maths (Ganita Prakash) | myCBSEguide<\/title>\n<meta name=\"description\" content=\"Geometric Twins - NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Geometric Twins - NCERT Solutions Class 7 Maths (Ganita Prakash) | myCBSEguide\" \/>\n<meta property=\"og:description\" content=\"Geometric Twins - NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths\" \/>\n<meta property=\"og:url\" content=\"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/\" \/>\n<meta property=\"og:site_name\" content=\"myCBSEguide\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/mycbseguide\/\" \/>\n<meta property=\"article:published_time\" content=\"2026-09-17T11:41:36+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2026-09-17T11:42:18+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/media-mycbseguide.s3.amazonaws.com\/images\/question_images\/1762843793-bcfke7.jpg\" \/>\n<meta name=\"author\" content=\"myCBSEguide\" \/>\n<meta name=\"twitter:card\" content=\"summary_large_image\" \/>\n<meta name=\"twitter:creator\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:site\" content=\"@mycbseguide\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"myCBSEguide\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"12 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Article\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/#article\",\"isPartOf\":{\"@id\":\"https:\/\/mycbseguide.com\/blog\/geometric-twins-ncert-solutions-class-7-maths-ganita-prakash\/\"},\"author\":{\"name\":\"myCBSEguide\",\"@id\":\"https:\/\/mycbseguide.com\/blog\/#\/schema\/person\/10b8c7820ff29025ab8524da7c025f65\"},\"headline\":\"Geometric Twins &#8211; 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