{"id":31862,"date":"2026-09-17T15:54:34","date_gmt":"2026-09-17T10:24:34","guid":{"rendered":"https:\/\/mycbseguide.com\/blog\/?p=31862"},"modified":"2026-09-17T15:55:29","modified_gmt":"2026-09-17T10:25:29","slug":"a-peek-beyond-the-point-ncert-solutions-class-7-maths-ganita-prakash","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/a-peek-beyond-the-point-ncert-solutions-class-7-maths-ganita-prakash\/","title":{"rendered":"A Peek Beyond the Point – NCERT Solutions Class 7 Maths (Ganita Prakash)"},"content":{"rendered":"\n

A Peek Beyond the Point<\/strong><\/strong> – NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash).<\/p>\n\n\n\n

NCERT Solutions Class 7<\/h2>\n\n\nEnglish Poorvi<\/a>\n\n\nHindi Malhar<\/a>\n\n\nMaths Ganita Prakash<\/a>\n\n\nScience Curiosity<\/a>\n\n\nSocial Exploring Society<\/a>\n\n\n\n

A Peek Beyond the Point<\/strong><\/strong> \u2013 NCERT Solutions<\/h2>\n\n\n\n
\n\n\n\n

Q.1: Which scale helped you measure the length of the screws accurately? Why?
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

The scale with millimeter markings helped measure the length of the screws accurately because it allows for more precise and detailed measurements compared to scales with only centimeter markings.<\/p>\n\n\n\n

\n\n\n\n

Q.2: What is the meaning of {tex}2 \\frac{7}{10} {~cm}{\/tex} (the length of the first screw)?
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

It means that the length of the screw is two and seven-tenth centimeters.<\/p>\n\n\n\n

\n\n\n\n

Q.3: Can you explain why the unit was divided into smaller parts to measure the screws?
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

The unit was divided into smaller parts because the lengths of the screws were not whole centimetres. Smaller divisions, like millimetres, were needed to measure them more accurately.<\/p>\n\n\n\n

\n\n\n\n

Q.4: Measure the following objects using a scale and write their measurements in centimeters (as shown earlier for the lengths of the screws): pen, sharpener, and any other object of your choice.
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Pen: 14 cm
Sharpener: 3.2 cm
Eraser: 4.0 cm
Notebook: 21cm<\/p>\n\n\n\n

\n\n\n\n

Q.5: Write the measurements of the objects shown in the picture:
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Eraser: 2.4 cm
Pencil: 4.5 cm
Chalk: 1.4 cm<\/p>\n\n\n\n

\n\n\n\n

Q.6: Arrange these lengths in increasing order:
(a) {tex}\\frac{9}{10}{\/tex}, (b) {tex}1 \\frac{7}{10}{\/tex}, (c) {tex}\\frac{130}{10}{\/tex}, (d) {tex}13 \\frac{1}{10}{\/tex}, (e) {tex}10 \\frac{5}{10}{\/tex}, (f) {tex}7 \\frac{6}{10}{\/tex}, (g) {tex}6 \\frac{7}{10}{\/tex}, (h)\u00a0{tex}\\frac{4}{10}{\/tex},<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

{tex}0.4<0.9<1.7<6.7<7.6<10.5<13.0<13.1{\/tex}
or {tex}\\frac{4}{10}<\\frac{9}{10}<1 \\frac{7}{10}<6 \\frac{7}{10}<7 \\frac{6}{10}<10 \\frac{5}{10}<\\frac{130}{10}<13 \\frac{1}{10}{\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.7: Arrange the following lengths in increasing order: {tex}4 \\frac{1}{10^{\\prime}}, \\frac{4}{10^{\\prime}}, \\frac{41}{10^{\\prime}}, 41 \\frac{1}{10}{\/tex}.<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

{tex} \\frac{4}{10}<4 \\frac{1}{10}=\\frac{41}{10}<41 \\frac{1}{10} {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.8: Sonu is measuring some of his body parts. The length of Sonu’s lower arm is {tex}2 \\frac{7}{10}{\/tex} units, and that of his upper arm is {tex}3 \\frac{6}{10}{\/tex} units. What is the total length of his arm?<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Lower arm {tex}=2 \\frac{7}{10}{\/tex} units
Upper arm {tex}=3 \\frac{6}{10}{\/tex} units
{tex} \\text { Total length of arms } =2 \\frac{7}{10}+3 \\frac{6}{10} {\/tex}
{tex} =(2+3)+\\left(\\frac{7}{10}+\\frac{6}{10}\\right) {\/tex}
{tex} =5+\\frac{13}{10} {\/tex}
{tex} =5+\\frac{10}{10}+\\frac{3}{10} {\/tex}
{tex} =5+1+\\frac{3}{10} {\/tex}
{tex} =6 \\frac{3}{10} \\text { units. } {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.9: The lengths of the body parts of a honeybee are given. Find its total length.
Head: {tex}2 \\frac{3}{10}{\/tex} units
Thorax: {tex}5 \\frac{4}{10}{\/tex} units
Abdomen:\u00a0{tex}7 \\frac {5}{10}{\/tex}\u00a0units
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

{tex} \\text { Total length of bee } =\\text { Head }+ \\text { Thorax }+ \\text { Abdomen } {\/tex}
{tex} =2 \\frac{3}{10}+5 \\frac{4}{10}+7 \\frac{5}{10} {\/tex}
{tex} =(2+5+7)+\\left(\\frac{3}{10}+\\frac{4}{10}+\\frac{5}{10}\\right) {\/tex}
{tex} =14+\\left(\\frac{3+4+5}{10}\\right) {\/tex}
{tex} =14+\\frac{12}{10} {\/tex}
{tex} =14+\\frac{10}{10}+\\frac{2}{10} {\/tex}
{tex} =14+1+\\frac{2}{10} {\/tex}
{tex} =15 \\frac{2}{10} \\text { units. } {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.10: The length of Shylaja’s hand is {tex}12 \\frac{4}{10}{\/tex} units, and her palm is {tex}6 \\frac{7}{10}{\/tex} units, as shown in the picture. What is the length of the longest (middle) finger?
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Length of hand {tex}=12 \\frac{4}{10}{\/tex} units
Length of palm {tex}=6 \\frac{7}{10}{\/tex} units
Length of longest finger {tex}={\/tex} Hand – Palm
{tex} =12 \\frac{4}{10}-6 \\frac{7}{10} {\/tex}
{tex} =(12-6)+\\left(\\frac{4}{10}-\\frac{7}{10}\\right) {\/tex}
{tex} =6+\\frac{-3}{10} {\/tex}
{tex} =6-\\frac{3}{10} {\/tex}
{tex} =5+1-\\frac{3}{10} {\/tex}
{tex} =5+\\frac{10}{10}-\\frac{3}{10} {\/tex}
{tex} =5+\\frac{10-3}{10}=5+\\frac{7}{10}=5 \\frac{7}{10} \\text { units. } {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.11: Try computing the difference by converting both lengths to tenths.
Length of hand {tex}=12 \\frac{4}{10}{\/tex} units
Length of palm {tex}=6 \\frac{7}{10}{\/tex} units<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

{tex} \\text { Length of hand }=12 \\frac{4}{10} \\text { units }=\\frac{124}{10} \\text { units } {\/tex}
{tex} \\text { Length of palm }=6 \\frac{7}{10} \\text { units }=\\frac{67}{10} \\text { units } {\/tex}
{tex} \\text { Length of longer finger } =\\text { Hand }- \\text { Palm } {\/tex}
{tex} =\\frac{124}{10}-\\frac{67}{10} {\/tex}
{tex} =\\frac{124-67}{10} {\/tex}
{tex} =\\frac{57}{10} {\/tex}
{tex} =\\frac{50}{10}+\\frac{7}{10}=5+\\frac{7}{10}=5 \\frac{7}{10} \\text { units. } {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.12: A Celestial Pearl Danio’s length is {tex}2 \\frac{4}{10} {~cm}{\/tex}, and the length of a Philippine Goby is {tex}\\frac{9}{10} {~cm}{\/tex}. What is the difference in their lengths?<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

{tex} \\text { Celestial Pearl Dino’s length }=2 \\frac{4}{10} {~cm}=\\frac{24}{10} {~cm} {\/tex}
{tex} \\text { Philippine Goby’s length }=\\frac{9}{10} {~cm} {\/tex}
{tex} \\text { Difference in length } =\\frac{24}{10}-\\frac{9}{10} {\/tex}
{tex} =\\frac{24-9}{10} {\/tex}
{tex} =\\frac{15}{10} {\/tex}
{tex} =\\frac{10}{10}+\\frac{5}{10}=1+\\frac{5}{10}=1 \\frac{5}{10} {~cm} {\/tex}<\/p>\n\n\n\n

\n\n\n\n

Q.13: How big are these fish compared to your finger?
<\/p>\n\n\n\n

Solution:<\/p>\n\n\n\n

Celestial Pearl Dino {tex}=\\frac{24}{10} {~cm}=2.4 {~cm}{\/tex}
Philippine Goby {tex}=\\frac{9}{10}=0.9 {~cm}{\/tex}
Little finger’s length {tex}=2.7 {~cm}{\/tex}
Celestial Pearl Dino is {tex}0.3 {~cm}(2.7-2.4=0.3 {~cm}){\/tex} smaller than my little finger.
Philippine Goby is {tex}1.8 {~cm}(2.7-0.9=1.8 {~cm}){\/tex} smaller than my little finger.<\/p>\n\n\n\n

\n\n\n\n

Q.14: Observe the given sequences of numbers. Identify the change after each term and extend the pattern:<\/p>\n\n\n\n

    \n
  1. {tex}4,4 \\frac{3}{10}, 4 \\frac{6}{10}{\/tex}, ,\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n\n\n\n
  2. {tex}8 \\frac{2}{10}, 8 \\frac{7}{10}, 9 \\frac{2}{10}{\/tex},\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n\n\n\n
  3. {tex}7 \\frac{6}{10^{\\prime}}, 8 \\frac{7}{10^{\\prime}}{\/tex},\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n<\/ol>\n\n\n\n

    Solution:<\/p>\n\n\n\n

      \n
    1. {tex}4,4 \\frac{3}{10}, 4 \\frac{6}{10}{\/tex}, …
      Change {tex}={\/tex} Addition of {tex}\\frac{3}{10}{\/tex}.
      {tex} 4,4 \\frac{3}{10}, 4 \\frac{6}{10^{\\prime}}, 4 \\frac{9}{10^{\\prime}}, 5 \\frac{2}{10^{\\prime}}, 5 \\frac{5}{10^{\\prime}}, \\ldots{\/tex}<\/li>\n\n\n\n
    2. {tex}8 \\frac{2}{10}, 8 \\frac{7}{10}, 9 \\frac{2}{10}{\/tex}, …
      Change {tex}={\/tex} Addition of {tex}\\frac{5}{10}{\/tex}.
      {tex} 8 \\frac{2}{10^{\\prime}}, 8 \\frac{7}{10^{\\prime}}, 9 \\frac{2}{10^{\\prime}}, 9 \\frac{7}{10}, 10 \\frac{2}{10^{\\prime}}, 10 \\frac{7}{10^{\\prime}}, \\ldots{\/tex}<\/li>\n\n\n\n
    3. {tex}7 \\frac{6}{10^{\\prime}}, 8 \\frac{7}{10^{\\prime}}{\/tex} …
      Change {tex}={\/tex} Addition of {tex}1 \\frac{1}{10}{\/tex}.
      {tex} 7 \\frac{6}{10^{\\prime}}, 8 \\frac{7}{10^{\\prime}}, 9 \\frac{8}{10^{\\prime}}, 10 \\frac{9}{10^{\\prime}}, 12,13 \\frac{1}{10^{\\prime}}, \\ldots{\/tex}<\/li>\n<\/ol>\n\n\n\n
      \n\n\n\n

      Q.15: Observe the given sequences of numbers. Identify the change after each term and extend the pattern:<\/p>\n\n\n\n

        \n
      1. {tex}5 \\frac{7}{10^{\\prime}}, 5 \\frac{4}{10^{\\prime}}{\/tex}\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n\n\n\n
      2. {tex}13 \\frac{5}{10}, 13,12 \\frac{5}{10}{\/tex},\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n\n\n\n
      3. {tex}11 \\frac{5}{10}, 10 \\frac{4}{10}, 9 \\frac{3}{10}{\/tex},\u00a0________,\u00a0________,\u00a0________,\u00a0________<\/li>\n<\/ol>\n\n\n\n

        Solution:<\/p>\n\n\n\n

          \n
        1. {tex}5 \\frac{7}{10}, 5 \\frac{3}{10}, \\ldots{\/tex}
          Change {tex}={\/tex} Subtraction of {tex}\\frac{4}{10}{\/tex}. {tex}5 \\frac{7}{10}, 5 \\frac{3}{10}, 4 \\frac{9}{10}, 4 \\frac{5}{10}, 4 \\frac{1}{10}, 3 \\frac{7}{10}, \\ldots{\/tex}<\/li>\n\n\n\n
        2. {tex}13 \\frac{5}{10}, 13,12 \\frac{5}{10}{\/tex},
          Change {tex}={\/tex} Subtraction of {tex}\\frac{5}{10}{\/tex}.
          {tex} 13 \\frac{5}{10}, 13,12 \\frac{5}{10}, 12,11 \\frac{5}{10}, 11,10 \\frac{5}{10}, 10, \u00a0\\ldots\u00a0 {\/tex}<\/li>\n\n\n\n
        3. {tex}11 \\frac{5}{10}, 10 \\frac{4}{10}, 9{\/tex}, {tex}\\qquad{\/tex}
          Change {tex}={\/tex} Subtraction of {tex}1 \\frac{1}{10}{\/tex}.
          {tex} 11 \\frac{5}{10}, 10 \\frac{4}{10}, 9 \\frac{3}{10}, 8 \\frac{2}{10}, 7 \\frac{1}{10}, 6, \\ldots {\/tex}<\/li>\n<\/ol>\n\n\n\n
          \n\n\n\n

          Q.16: What is the length of this smaller part? How many such smaller parts make a unit length?<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          Length of each smaller part on splitting each one-tenth into 10 parts {tex}=\\frac{1}{100}{\/tex}. 100 such smaller parts make a unit length.<\/p>\n\n\n\n

          \n\n\n\n

          Q.17: How many one-hundredths make one-tenth? Can we also say that the length is 4 units and 45 one-hundredths? (Length is 4 units and 4 one-tenths and 5 one-hundredths)<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          Number of one-hundredths in one-tenth {tex}=\\frac{1}{100} \\div \\frac{1}{10}=10{\/tex}.
          4 units and 4 one-tenths and 5 one-hundredths {tex}=4+\\frac{4}{10}+\\frac{5}{100}=4+0.4+0.45=4.45{\/tex} units.
          4 units and 45 one-hundredths {tex}=4+\\frac{45}{100}=4+0.45=4.45{\/tex} units.
          Hence, 4 units and 4 one-tenths and 5 one-hundredths can also be written as 4 units and 45 one-hundredths.<\/p>\n\n\n\n

          \n\n\n\n

          Q.18: Observe the figure below. Notice the markings and the corresponding lengths written in the boxes when measured from 0. Fill the lengths in the empty boxes.
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          \"\"\/<\/figure>\n\n\n\n
          \n\n\n\n

          Q.19: For the lengths shown below write the measurements and read out the measures in words.
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex}5 \\frac{3}{10} \\frac{7}{100}={\/tex} Five and three-tenths and seven-hundredths.
          {tex}15 \\frac{3}{100}={\/tex} Fifteen and three-hundredths.<\/p>\n\n\n\n

          \n\n\n\n

          Q.20: For the lengths shown below write the measurements and read out the measures in words.
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex}7 \\frac{5}{10} \\frac{2}{100}={\/tex} Seven and five-tenths and two-hundredths.
          {tex}9 \\frac{80}{100}={\/tex} Nine and eighty-hundredths.<\/p>\n\n\n\n

          \n\n\n\n

          Q.21: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}\\frac{3}{10}, \\frac{3}{100}, \\frac{33}{100}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} \\frac{3}{10}=\\frac{30}{100} ; \\frac{3}{100} ; \\frac{33}{100} {\/tex}
          {tex} \\text { Longest length }=\\frac{33}{100} {\/tex}
          {tex} \\text { Shortest length }=\\frac{3}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.22: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}3 \\frac{1}{10}, \\frac{30}{10}, 1 \\frac{3}{10}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} 3 \\frac{1}{10}=\\frac{31}{10}=3.1 ; \\frac{30}{10}=3 ; 1 \\frac{3}{10}=\\frac{13}{10}=1.3 {\/tex}
          {tex} \\text { Longest length }=3 \\frac{1}{10} {\/tex}
          Shortest length {tex}=1 \\frac{3}{10}{\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.23: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}\\frac{45}{100}, \\frac{54}{100}, \\frac{5}{10}, \\frac{4}{10}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} \\frac{45}{100} ; \\frac{54}{100} ; \\frac{5}{10}=\\frac{50}{100} ; \\frac{4}{10}=\\frac{40}{100} {\/tex}
          {tex} \\text { Longest length }=\\frac{54}{100} {\/tex}
          {tex} \\text { Shortest length }=\\frac{40}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.24: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}3 \\frac{6}{10^{\\prime}}, 3 \\frac{6}{100}, 3 \\frac{6}{10} \\frac{6}{100}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} 3 \\frac{6}{10}=\\frac{36}{10} ; 3 \\frac{6}{100}=\\frac{30}{10} \\frac{6}{100} ; 3 \\frac{6}{10} \\frac{6}{100}=\\frac{36}{10} \\frac{6}{100} {\/tex}
          {tex} \\text { Largest number }=3 \\frac{6}{10} \\frac{6}{100} {\/tex}
          {tex} \\text { Smallest number }=3 \\frac{6}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.25: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}\\frac{8}{10} \\frac{2}{100}, \\frac{9}{100}, 1 \\frac{8}{100}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} \\text { Largest number }=1 \\frac{8}{100} {\/tex}
          {tex} \\text { Smallest number }=\\frac{9}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.26: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}7 \\frac{3}{10} \\frac{5}{100}, 7 \\frac{5}{10}, 7 \\frac{41}{100}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} 7 \\frac{3}{10} \\frac{5}{100}=\\frac{73}{10} \\frac{5}{100} ; 7 \\frac{5}{10}=\\frac{75}{10} {\/tex}
          {tex} 7 \\frac{41}{100}=7+\\frac{41}{100}=\\frac{70}{10}+\\frac{41}{100}=\\frac{70}{10}+\\frac{40}{100}+\\frac{1}{100}=\\frac{70}{10}+\\frac{4}{10}+\\frac{1}{100}=\\frac{74}{10}+\\frac{1}{100}=\\frac{74}{10} \\frac{1}{100} {\/tex}
          {tex} \\text { Largest number }=7 \\frac{5}{10} {\/tex}
          {tex} \\text { Smallest number }=7 \\frac{3}{10} \\frac{5}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.27: Identify the longest and the shortest lengths. Mark each length on the scale.
          {tex}\\frac{65}{10} \\frac{15}{100}, 5 \\frac{87}{100}, 5 \\frac{7}{100}{\/tex}
          <\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} \\frac{65}{10} \\frac{15}{100}=\\frac{65}{10}+\\frac{15}{100}=\\frac{65}{10}+\\frac{10}{100}+\\frac{5}{100}=\\frac{65}{10}+\\frac{1}{10}+\\frac{5}{100}=\\frac{66}{10}+\\frac{5}{100}=\\frac{66}{10} \\frac{5}{100} {\/tex}
          {tex} 5 \\frac{87}{100}=5+\\frac{87}{100}=5+\\frac{80}{100}+\\frac{7}{100}=5+\\frac{8}{10}+\\frac{7}{100}=5 \\frac{8}{10} \\frac{7}{100} {\/tex}
          {tex} 5 \\frac{7}{100} {\/tex}
          {tex} \\text { Largest number }=\\frac{65}{10} \\frac{15}{100} {\/tex}
          {tex} \\text { Smallest number }=5 \\frac{7}{100} {\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.28: What will be the sum of {tex}15 \\frac{3}{10} \\frac{4}{100}{\/tex} and {tex}2 \\frac{6}{10} \\frac{8}{100} ?{\/tex}<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} \\text { Method 1: } {\/tex}
          {tex} 15 \\frac{3}{10} \\frac{4}{100}+2 \\frac{6}{10} \\frac{8}{100} {\/tex} {tex}=(15+2)+\\left(\\frac{3}{10}+\\frac{6}{10}\\right)+\\left(\\frac{4}{100}+\\frac{8}{100}\\right) {\/tex}
          {tex} =17+\\frac{9}{10}+\\frac{12}{100} {\/tex}
          {tex} =17+\\frac{9}{10}+\\frac{10}{100}+\\frac{2}{100} {\/tex}
          {tex} =17+\\frac{9}{10}+\\frac{1}{10}+\\frac{2}{100} {\/tex}
          {tex} =17+\\frac{10}{10}+\\frac{2}{100} {\/tex}
          {tex} =17+1+\\frac{2}{100}=18+\\frac{2}{100} . {\/tex}
          Method 2: {tex}15 \\frac{3}{10} \\frac{4}{100}+2 \\frac{6}{10} \\frac{8}{100}{\/tex}
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.29: Are both these methods different?<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          No, both methods are the same in logic and result but differ in structure. Method 1 uses a step-by-step horizontal layout for addition, while Method 2 uses a vertical layout.<\/p>\n\n\n\n

          \n\n\n\n

          Q.30: What is the difference:\u00a0{tex}25 \\frac{9}{10}-6 \\frac{4}{10} \\frac{7}{100}{\/tex}?<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          {tex} 25 \\frac{9}{10}=25 \\frac{90}{100} ; 6 \\frac{4}{10} \\frac{7}{100}=6 \\frac{47}{100} {\/tex}
          {tex} 25 \\frac{9}{10}-6 \\frac{4}{10} \\frac{7}{100}{\/tex} {tex}=25 \\frac{90}{100}-6 \\frac{47}{100}{\/tex}{tex}=(25-6)+\\left(\\frac{90}{100}-\\frac{47}{100}\\right)=19+\\frac{43}{100}=19 \\frac{43}{100} . {\/tex}<\/p>\n\n\n\n

          \n\n\n\n

          Q.31:<\/p>\n\n\n\n


          Can we extend this further?<\/p>\n\n\n\n

          Solution:<\/p>\n\n\n\n

          Yes, it can be extended on both sides infinitely.
          <\/p>\n\n\n\n

          \n\n\n\n

          Q.32: We can ask similar questions about fractional parts:<\/p>\n\n\n\n

            \n
          1. How many thousandths make one unit?<\/li>\n\n\n\n
          2. How many thousandths make one tenth?<\/li>\n\n\n\n
          3. How many thousandths make one hundredth?<\/li>\n\n\n\n
          4. How many tenths make one ten?<\/li>\n\n\n\n
          5. How many hundredths make one ten?<\/li>\n<\/ol>\n\n\n\n

            Solution:<\/p>\n\n\n\n

              \n
            1. Since, {tex}\\frac{1}{1000} \\times 1000=1{\/tex}.
              {tex}\\therefore 1000{\/tex} thousandths make one unit.<\/li>\n\n\n\n
            2. Since, {tex}\\frac{1}{1000} \\times 100=\\frac{1}{10}{\/tex}.
              {tex}\\therefore 100{\/tex} thousandths make one tenth.<\/li>\n\n\n\n
            3. Since, {tex}\\frac{1}{1000} \\times 10=\\frac{1}{100}{\/tex}.
              {tex}\\therefore 10{\/tex} thousandths make one hundredth.<\/li>\n\n\n\n
            4. Since, {tex}\\frac{1}{10} \\times 100=10{\/tex}.
              {tex}\\therefore 100{\/tex} tenths make one ten.<\/li>\n\n\n\n
            5. Since, {tex}\\frac{1}{100} \\times 1000=10{\/tex}.
              {tex}\\therefore 1000{\/tex} tenths make one ten.<\/li>\n<\/ol>\n\n\n\n
              \n\n\n\n

              Q.33: We can ask similar questions about fractional parts:<\/p>\n\n\n\n

                \n
              1. How many hundredths make one unit?<\/li>\n\n\n\n
              2. How many tenths make one unit?<\/li>\n\n\n\n
              3. How many tenths make one hundredth?<\/li>\n\n\n\n
              4. How many hundredths make one tenth?<\/li>\n<\/ol>\n\n\n\n

                Solution:<\/p>\n\n\n\n

                  \n
                1. Since, {tex}\\frac{1}{100} \\times 100=1{\/tex}.
                  {tex}\\therefore 100{\/tex} hundredths make one unit.<\/li>\n\n\n\n
                2. Since, {tex}\\frac{1}{10} \\times 10=1{\/tex}.
                  {tex}\\therefore 10{\/tex} tenths make one unit.<\/li>\n\n\n\n
                3. Since, {tex}\\frac{1}{10} \\times \\frac{1}{10}=\\frac{1}{100}{\/tex}.
                  {tex}\\therefore \\frac{1}{10}{\/tex} tenths make one hundredth.<\/li>\n\n\n\n
                4. Since, {tex}\\frac{1}{100} \\times 10=\\frac{1}{10}{\/tex}.
                  {tex}\\therefore 10{\/tex} hundredths make one tenth.<\/li>\n<\/ol>\n\n\n\n
                  \n\n\n\n

                  Q.34: Make a place value table similar to the one above. Write each quantity in decimal form and in terms of place value and read the number:<\/p>\n\n\n\n

                    \n
                  1. 2 ones, 3 tenths and 5 hundredths<\/li>\n\n\n\n
                  2. 1 ten and 5 tenths<\/li>\n\n\n\n
                  3. 4 ones and 6 hundredths<\/li>\n\n\n\n
                  4. 1 hundred, 1 one and 1 hundredth<\/li>\n\n\n\n
                  5. {tex} \\frac{8}{100} \\text { and } \\frac{9}{10} {\/tex}<\/li>\n\n\n\n
                  6. {tex} \\frac{5}{100} {\/tex}<\/li>\n\n\n\n
                  7. {tex} \\frac{1}{10} {\/tex}<\/li>\n\n\n\n
                  8. {tex} 2 \\frac{1}{100}, 4 \\frac{1}{10} \\text { and } 7 \\frac{1}{1000} {\/tex}<\/li>\n<\/ol>\n\n\n\n

                    Solution:<\/p>\n\n\n\n

                    Quantity<\/strong><\/td>Decimal Notation<\/strong><\/td><\/tr>
                    (a) 2 ones, 3 tenths and 5 hundredths {tex}\\left(2+\\frac{3}{10}+\\frac{5}{100}\\right){\/tex}<\/td>2.35<\/td><\/tr>
                    b) 1 ten and 5 tenths {tex}\\left(10+0+\\frac{5}{10}\\right){\/tex}<\/td>10.5<\/td><\/tr>
                    (c) 4 ones and 6 hundredths {tex}\\left(4+0+\\frac{6}{100}\\right){\/tex}<\/td>4.06<\/td><\/tr>
                    (d) 1 hundred, 1 one and 1 hundredth {tex}\\left(100+0+1+0+\\frac{1}{100}\\right){\/tex}<\/td>101.01<\/td><\/tr>
                    (e) {tex}\\frac{8}{100}{\/tex} and {tex}\\frac{9}{10}{\/tex} {tex}\\left(\\frac{9}{10}+\\frac{8}{100}\\right){\/tex}<\/td>0.98<\/td><\/tr>
                    (f) {tex}\\frac{5}{100}{\/tex}<\/td>0.05<\/td><\/tr>
                    (g) {tex}\\frac{1}{10}{\/tex}<\/td>0.1<\/td><\/tr>
                    (h) {tex}2 \\frac{1}{100}, 4 \\frac{1}{10}{\/tex} and {tex}7 \\frac{1}{1000}{\/tex} {tex}\\left(\\frac{4}{10}+\\frac{2}{100}+\\frac{7}{1000}\\right){\/tex}<\/td>0.427<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
                    Decimal Number<\/strong><\/td>Hundreds<\/strong><\/td>Tens<\/strong><\/td>Units<\/strong><\/td>Tenth<\/strong><\/td>Hundreds<\/strong><\/td>Thousands<\/strong><\/td><\/tr>
                    (a) 2.35<\/td> <\/td> <\/td>{tex}2 \\times 1{\/tex}<\/td>{tex}3 \\times \\frac{1}{10}{\/tex}<\/td>{tex}5 \\times \\frac{1}{100}{\/tex}<\/td> <\/td><\/tr>
                    (b) 10.5<\/td> <\/td>{tex}1 \\times 10{\/tex}<\/td>{tex}0 \\times 1{\/tex}<\/td>{tex}5 \\times \\frac{1}{10}{\/tex}<\/td> <\/td> <\/td><\/tr>
                    (c) 4.06<\/td> <\/td> <\/td>{tex}4 \\times 1{\/tex}<\/td>{tex}0 \\times \\frac{1}{10}{\/tex}<\/td>{tex}6 \\times \\frac{1}{100}{\/tex}<\/td> <\/td><\/tr>
                    (d) 101.01<\/td>{tex}1 \\times 100{\/tex}<\/td>{tex}0 \\times 10{\/tex}<\/td>{tex}1 \\times 1{\/tex}<\/td>{tex}0 \\times \\frac{1}{10}{\/tex}<\/td>{tex}1 \\times \\frac{1}{100}{\/tex}<\/td> <\/td><\/tr>
                    (e) 0.98<\/td> <\/td> <\/td> <\/td>{tex}9 \\times \\frac{1}{10}{\/tex}<\/td>{tex}8 \\times \\frac{1}{100}{\/tex}<\/td> <\/td><\/tr>
                    (f) 0.05<\/td> <\/td> <\/td> <\/td>{tex}0 \\times \\frac{1}{10}{\/tex}<\/td>{tex}5 \\times \\frac{1}{100}{\/tex}<\/td> <\/td><\/tr>
                    (g) 0.1<\/td> <\/td> <\/td> <\/td>{tex}1 \\times \\frac{1}{10}{\/tex}<\/td> <\/td> <\/td><\/tr>
                    (h) 0.427<\/td> <\/td> <\/td> <\/td>{tex}4 \\times \\frac{1}{10}{\/tex}<\/td>{tex}2 \\times \\frac{1}{100}{\/tex}<\/td>{tex}7 \\times \\frac{1}{1000}{\/tex}<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n
                      \n
                    1. 2.35 – Two point three five.<\/li>\n\n\n\n
                    2. 10.35 – Ten point three five.<\/li>\n\n\n\n
                    3. 4.06 – Four point zero six.<\/li>\n\n\n\n
                    4. 101.01 – One hundred one point zero one.<\/li>\n\n\n\n
                    5. 0.98 – zero point nine eight.<\/li>\n\n\n\n
                    6. 0.05 – zero-point zero five.<\/li>\n\n\n\n
                    7. 0.1 – zero point one.<\/li>\n\n\n\n
                    8. 0.427 – zero point four two seven.<\/li>\n<\/ol>\n\n\n\n
                      \n\n\n\n

                      Q.35: Write these quantities in decimal form:<\/p>\n\n\n\n

                        \n
                      1. 234 hundredths,<\/li>\n\n\n\n
                      2. 105 tenths.<\/li>\n<\/ol>\n\n\n\n

                        Solution:<\/p>\n\n\n\n

                          \n
                        1. {tex} 234 \\text { hundredths }=\\frac{234}{100}=2.34 {\/tex}<\/li>\n\n\n\n
                        2. {tex} 105 \\text { tenths }=\\frac{105}{10}=10.5 {\/tex}<\/li>\n<\/ol>\n\n\n\n
                          \n\n\n\n

                          Q.36: Fill in the blanks below (mm cm)
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex} 70 {~mm}=\\frac{70}{10} {~cm}=7 {~cm} {\/tex}
                          {tex} 0.9 {~cm}=(0.9 \\times 10) {mm}=\\left(\\frac{9}{10} \\times 10\\right) {mm}=9 {~mm} {\/tex}
                          {tex} 134 {~mm}=\\frac{134}{10} {~cm}=13.4 {~cm} {\/tex}
                          {tex} 203.6 {~cm}=(203.6 \\times 10) {mm}=\\left(\\frac{2036}{10} \\times 10\\right) {mm}=2036 {~mm} {\/tex}
                          <\/p>\n\n\n\n

                          \n\n\n\n

                          Q.37: Fill in the blanks below (cm < – >\u00a0m):
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex} 36 {~cm}=\\frac{36}{100} {~m}=\\left(\\frac{30}{100}+\\frac{6}{100}\\right) {m}=\\left(\\frac{3}{10}+\\frac{6}{100}\\right) {m}=0.36 {~m} {\/tex}
                          {tex} 50 {~cm}=\\frac{50}{100} {~m}=\\frac{5}{10} {~m}=0.5 {~m} {\/tex}
                          {tex} 0.89 {~m}=(0.89 \\times 100) {cm}=\\left(\\frac{89}{100} \\times 100\\right) {cm}=89 {~cm} {\/tex}
                          {tex} 4 {~cm}=\\frac{4}{100} {~m}=0.04 {~m} {\/tex}
                          {tex} 325 {~cm}=\\frac{325}{100} {~m}=\\left(\\frac{300}{100}+\\frac{20}{100}+\\frac{5}{100}\\right) {m}=\\left(3+\\frac{2}{10}+\\frac{5}{100}\\right) {m}=3.25 {~m} {\/tex}
                          {tex} 2.07 {~m}=(2.07 \\times 100) {cm}=\\left(\\frac{207}{100} \\times 100\\right) {cm}=207 {~cm} {\/tex}
                          <\/p>\n\n\n\n

                          \n\n\n\n

                          Q.38: How many mm does 1 meter have?<\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex}1 {~m}=(1 \\times 100) {cm}=100 {~cm}{\/tex} {tex}=(100 \\times 10) {mm}=1000 {~mm}{\/tex}.<\/p>\n\n\n\n

                          \n\n\n\n

                          Q.39: Can we write {tex}1 {~mm}=\\frac{1}{1000} {~m}{\/tex}?<\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          Yes, 1 mm can be written as {tex}\\frac{1}{1000} {~m}{\/tex}.
                          Because {tex}1 {~mm}=\\frac{1}{10} {~cm}=\\frac{1}{10 \\times 100} {~m}=\\frac{1}{1000} {~m}{\/tex}<\/p>\n\n\n\n

                          \n\n\n\n

                          Q.40: Fill in the blanks below (g < – > kg)
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex} 465 {~g}=\\frac{465}{1000} {~kg}=\\left(\\frac{400}{1000}+\\frac{60}{1000}+\\frac{5}{1000}\\right) {kg}={\/tex}{tex}\\left(\\frac{4}{10}+\\frac{6}{100}+\\frac{5}{1000}\\right) {kg}=0.465 {~kg} {\/tex}
                          {tex} 68 {~g}=\\frac{68}{1000} {~kg}=\\left(\\frac{60}{1000}+\\frac{8}{1000}\\right) {kg}{\/tex}{tex}=\\left(\\frac{6}{100}+\\frac{8}{1000}\\right) {kg}=0.068 {~kg} {\/tex}
                          {tex} 1560 {~g}=\\frac{1560}{1000} {~kg}{\/tex}{tex}=\\left(\\frac{1000}{1000}+\\frac{500}{1000}+\\frac{60}{1000}\\right) {kg}{\/tex}{tex}=\\left(1+\\frac{5}{10}+\\frac{6}{100}\\right) {kg}=1.56 {~kg} {\/tex}
                          {tex} 704 {~g}=\\frac{704}{1000} {~kg}=\\left(\\frac{700}{1000}+\\frac{4}{1000}\\right) {kg}{\/tex}{tex}=\\left(\\frac{7}{10}+\\frac{4}{1000}\\right) {kg}=0.704 {~kg} {\/tex}
                          {tex} 0.56 {~kg}=(0.56 \\times 1000) {g}={\/tex}{tex}\\left(\\frac{56}{100} \\times 1000\\right) {g}=560 {~g} {\/tex}
                          {tex} 2.5 {~kg}=(2.5 \\times 1000) {g}={\/tex}{tex}\\left(\\frac{25}{10} \\times 1000\\right) {g}=2500 {~g} {\/tex}
                          <\/p>\n\n\n\n

                          \n\n\n\n

                          Q.41: Fill in the blanks below (rupee < – >\u00a0 paise)
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex} 10 p=\u20b9 \\frac{10}{100}=\u20b9 \\frac{1}{10}=\u20b9 0.1 {\/tex}
                          {tex} \u20b9 0.05=(0.05 \\times 100) p=\\left(\\frac{5}{100} \\times 100\\right) p=5 p {\/tex}
                          {tex} \u20b9 0.36=(0.36 \\times 100) p=\\left(\\frac{36}{100} \\times 100\\right) p=36 p {\/tex}
                          {tex} \u20b9 0.50=(0.50 \\times 100) p=\\left(\\frac{50}{100} \\times 100\\right) p=50 p {\/tex}
                          {tex} 99 p=\u20b9 \\frac{99}{100}=\u20b9\\left(\\frac{90}{100}+\\frac{9}{100}\\right)=\u20b9\\left(\\frac{9}{10}+\\frac{9}{100}\\right)=\u20b9 0.99 {\/tex}
                          {tex} 250 p=\u20b9 \\frac{250}{100}=\u20b9\\left(\\frac{200}{100}+\\frac{50}{100}\\right)=\u20b9\\left(2+\\frac{5}{10}\\right)=\u20b9 2.5 {\/tex}
                          <\/p>\n\n\n\n

                          \n\n\n\n

                          Q.42: Name all the divisions between 1 and 1.1 on the number line.
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          1 – 1.01 – 1.02 – 1.03 – 1.04 – 1.05 – 1.06 – 1.07 – 1.08 – 1.09 -1.1<\/p>\n\n\n\n

                          \n\n\n\n

                          Q.43: Identify and write the decimal numbers against the letters.
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          \"\"\/<\/figure>\n\n\n\n
                          \n\n\n\n

                          Q.44: Can you tell which of these is the smallest and which is the largest? 0.2, 0.20, 0.200, 0.02, 0.002<\/p>\n\n\n\n

                          Decimal number<\/strong><\/td>Units<\/strong><\/td>Tents<\/strong><\/td>Hundreds<\/strong><\/td>Thousands<\/strong><\/td><\/tr>
                          0.2<\/td>0<\/td>2<\/td> <\/td> <\/td><\/tr>
                          0.20<\/td>0<\/td>2<\/td>0<\/td> <\/td><\/tr>
                          0.200<\/td>0<\/td>2<\/td>0<\/td>0<\/td><\/tr>
                          0.02<\/td>0<\/td>0<\/td>2<\/td> <\/td><\/tr>
                          0.002<\/td>0<\/td>0<\/td>0<\/td>2<\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          {tex} 0.002<0.02<0.2=0.20=0.200 {\/tex}
                          {tex} \\text { Smallest }=0.002 {\/tex}
                          {tex} \\text { Largest }=0.2 {\/tex}<\/p>\n\n\n\n

                          \n\n\n\n

                          Q.45: Which of these are the same: 4.5, 4.05, 0.405, 4.050, 4.50, 4.005, 04.50?<\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          Decimal Number<\/strong><\/td>Units<\/strong><\/td>Tenths<\/strong><\/td>Hundredths<\/strong><\/td>Thousandths<\/strong><\/td><\/tr>
                          4.5<\/td>4<\/td>5<\/td> <\/td> <\/td><\/tr>
                          4.05<\/td>4<\/td>0<\/td>5<\/td> <\/td><\/tr>
                          0.405<\/td>0<\/td>4<\/td>0<\/td>5<\/td><\/tr>
                          4.050<\/td>4<\/td>0<\/td>5<\/td>0<\/td><\/tr>
                          4.50<\/td>4<\/td>5<\/td>0<\/td> <\/td><\/tr>
                          4.005<\/td>4<\/td>0<\/td>0<\/td>5<\/td><\/tr>
                          04.50<\/td>4<\/td>5<\/td>0<\/td> <\/td><\/tr><\/tbody><\/table><\/figure>\n\n\n\n

                          Therefore, 4.50 = 04.50 & 4.05 = 4.050<\/p>\n\n\n\n

                          \n\n\n\n

                          Q.46: Identify the decimal number in the last number line in Figure (b) denoted by\u2018?\u2019
                          <\/p>\n\n\n\n

                          Solution:<\/p>\n\n\n\n

                          \"\"\/<\/figure>\n\n\n\n
                          \n\n\n\n

                          Q.47: Make such number lines for the decimal numbers:<\/p>\n\n\n\n

                            \n
                          1. 9.876<\/li>\n\n\n\n
                          2. 0.407<\/li>\n<\/ol>\n\n\n\n

                            Solution:<\/p>\n\n\n\n

                              \n
                            1. 9.876
                              <\/li>\n\n\n\n
                            2. 0.407
                              <\/li>\n<\/ol>\n\n\n\n
                              \n\n\n\n

                              Q.48: In the number line shown below, what decimal numbers do the boxes labelled \u2018a\u2019, \u2018b\u2019, and \u2018c\u2019 denote?
                              <\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Divisions between 5 and {tex}10=10{\/tex}
                              Each division {tex}=\\frac{10-5}{10}=\\frac{5}{10}=0.5{\/tex} units
                              Therefore,
                              {tex} a=5+(2 \\times 0.5)=5+1=6 {\/tex}
                              {tex} b=5+(5 \\times 0.5)=5+2.5=7.5 {\/tex}
                              {tex} c=5+(9 \\times 0.5)=5+4.5=9.5 {\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.49: Using similar reasoning, find out the decimal numbers represented by the values in the boxes below.
                              <\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Divisions between 8 and 8.1 = 10
                              Each division {tex}=(8.1-8) \\div 10=0.1 \\div 10{\/tex}{tex}=\\frac{1}{10} \\times \\frac{1}{10}=\\frac{1}{100}=0{\/tex}.
                              Therefore,
                              {tex} d=8+0.01=8.01 {\/tex}
                              {tex} e=8+(5 \\times 0.01)=8+0.05=8.05 {\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.50: Using similar reasoning, find out the decimal numbers represented by the values in the boxes below
                              <\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Divisions between 4.3 and 4.8 = 10
                              {tex} \\text { Each division }=(4.8-4.3) \\div 10=0.5 \\div 10{\/tex}{tex}=\\frac{5}{10} \\times \\frac{1}{10}=\\frac{5}{100}=0.05 {\/tex}
                              Therefore,
                              {tex} f=4.3+0.05=4.35 {\/tex}
                              {tex} g=4.3+(4 \\times 0.05)=4.3+0.2=4.50 {\/tex}
                              {tex} h=4.3+(11 \\times 0.05)=4.3+0.55=4.85 {\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.51: Which is larger: 6.456 or 6.465?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Comparing both numbers:
                              Units place – Both have 6 in the units place.
                              Tenths place – Both have 4 in the tenths place.
                              Hundredths place -6.456 has 5 in the hundredths place, while 6.465 has 6.
                              Since {tex}6>5{\/tex},
                              6.465 is greater than 6.456 at the hundredths place.
                              Therefore, 6.465 is the larger number.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.52: Why can we stop comparing at this point? Can we be sure that whatever digits are there after this will not affect our conclusion?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              When comparing decimal numbers, stop at the place value where the digits are different. The number with the larger digit at that place is the greater number.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.53: Which decimal number is greater:\u00a01.23<\/strong> or 1.32<\/strong>?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Comparing both numbers:
                              Units place – Both have 1 in the units place.
                              Tenths place -1.23 has 2 in the tenths place, while 1.32 has 3 .
                              Since {tex}3>2{\/tex},
                              1.32 is greater than 1.23 at the tenths place.
                              Therefore, 1.32 is the larger number.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.54: Which decimal number is greater: 3.81<\/strong> or 13.800<\/strong>?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Comparing both numbers:
                              Tenths place – 3.81 has 0 in the tens place while 13.800 has 1.
                              Since {tex}0<1{\/tex},
                              13.800 is greater than 3.81 at the tens place.
                              Therefore, 13.800 is the larger number.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.55: Which decimal number is greater: 1.009<\/strong> or 1.090<\/strong>?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Comparing both numbers:
                              Units place – Both have 1 in the units place.
                              Tenths place – Both have 0 in the tenths place.
                              Hundredths place – 1.009 has 0 in the hundredths place while 1.090 has 9.
                              Since {tex}0<9{\/tex},
                              1.090 is greater than 1.009 at the hundredths place.
                              Therefore, 1.090 is the larger number.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.56: Which of the above is closest to 1.09? (Decimal numbers: 0.9, 1.1, 1.01, and 1.11)<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Arranging all numbers in ascending order:
                              {tex} 0.9<1.01<1.09<1.1<1.11 {\/tex}
                              Here, neighbours of 1.09 are 1.01 and 1.1.
                              1.1 (or 1.10 ) is {tex}\\frac{1}{100}{\/tex} away from 1.09
                              1.01 is {tex}\\frac{8}{100}{\/tex} away from 1.09
                              Therefore, 1.1 is closest to 1.09 .<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.57: Which among these is closest to 4: 3.56, 3.65, 3.099?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Arranging all numbers in ascending order:
                              {tex} 3.099<3.56<3.65 {\/tex}
                              Now, compare the distance of each number from 4:
                              {tex} 4-3.099=0.901 {\/tex}
                              {tex} 4-3.56=0.44 {\/tex}
                              {tex} 4-3.65=0.35 {\/tex}
                              Among these, 3.65 is the smallest distance from 4. Therefore, 3.65 is closest to 4.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.58: Which among these is closest to 1: 0.8, 0.69, 1.08?<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Arranging all numbers in ascending order:
                              {tex} 0.69<0.8<1.08 {\/tex}
                              Now, compare the distance of each number from 1:
                              {tex} 1-0.69=0.31 {\/tex}
                              {tex} 1-0.8=0.2 {\/tex}
                              {tex} 1.08-1=0.08 {\/tex}
                              Among these, 1.08 is the smallest distance from 1.
                              Therefore, 1.08 is closest to 1<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.59: In each case below use the digits 4, 1, 8, 2, and 5 exactly once and try to make a decimal number as close as possible to 25.
                              <\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              \"\"\/<\/figure>\n\n\n\n
                              \n\n\n\n

                              Q.60: Write the detailed place value computation for 84.691 – 77.345, and its compact form.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              \"\"\/<\/figure>\n\n\n\n
                              \n\n\n\n

                              Q.61: Continue this sequence and write the next 3 terms. (Sequence -4.4, 4.8. 5.2, 5.6, 6.0, …)<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Sequence: {tex}4.4,4.8,5.2,5.6,6.0, \\ldots{\/tex}
                              Each term increases by 0.4 .
                              Next after 6.0: {tex} 6.0+0.4=6.4{\/tex}
                              Next: {tex} 6.4+0.4=6.8{\/tex}
                              Next: {tex} 6.8+0.4=7.2{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are 6.4, 6.8, 7.2.<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.62: Identify the pattern of change in the sequence 4.4, 4.45, 4.5<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term increases by 0.05
                              Next after 4.5: {tex}4.5+0.05=4.55{\/tex}
                              Next: {tex} 4.55+0.05=4.6{\/tex}
                              Next: {tex}4.6+0.05=4.65{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}4.55,4.6,4.65{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.63: Identify the pattern of change in the sequence 25.75, 26.25, 26.75<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term increases by 0.5
                              Next after 26.75: {tex}26.75+0.5=27.25{\/tex}
                              Next: {tex} 27.25+0.5=27.75{\/tex}
                              Next: {tex} 27.75+0.5=28.25{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}27.25,27.75,28.25{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.64: Identify the pattern of change in the sequence 10.56, 10.67, 10.78<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term increases by 0.11
                              Next after 10.78: {tex}10.78+0.11=10.89{\/tex}
                              Next: {tex} 10.89+0.11=11.00{\/tex}
                              Next: {tex} 11.00+0.11=11.11{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}10.89,11.00,11.11{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.65: Identify the pattern of change in the sequence 13.5, 16, 18.5<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term increases by 2.5
                              Next after 18.5: {tex} 18.5+2.5=21.0{\/tex}
                              Next: {tex} 21.0+2.5=23.5{\/tex}
                              Next: {tex} 23.5+2.5=26.0{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}21.0,23.5,26.0{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.66: Identify the pattern of change in the sequence 8.5, 9.4, 10.3<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term increases by 0.9
                              Next after 10.3: {tex}10.3+0.9=11.2{\/tex}
                              Next: {tex} 11.2+0.9=12.1{\/tex}
                              Next: {tex} 12.1+0.9=13.0{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are 11.2, 12.1, 13.0<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.67: Identify the pattern of change in the sequence 5, 4.95, 4.90<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term decreases by 0.05
                              Next after {tex}4.90: 4.90-0.05=4.85{\/tex}
                              Next: {tex} 4.85-0.05=4.80{\/tex}
                              Next: {tex} 4.80-0.05=4.75{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}4.85,4.80,4.75{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.68: Identify the pattern of change in the sequence 12.45, 11.95, 11.45<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term decreases by 0.5
                              Next after 11.45: {tex}11.45-0.5=10.95{\/tex}
                              Next: {tex} 10.95-0.5=10.45{\/tex}
                              Next: {tex}10.45-0.5=9.95{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}10.95,10.45,9.95{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.69: Identify the pattern of change in the sequence 36.5, 33, 29.5<\/strong>, and find the next three terms.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Each term decreases by 3.5
                              Next after 29.5: {tex}29.5-3.5=26.0{\/tex}
                              Next: {tex}26.0-3.5=22.5{\/tex}
                              Next: {tex}22.5-3.5=19.0{\/tex}
                              {tex}\\therefore{\/tex} Next 3 terms are {tex}26.0,22.5,19.0{\/tex}<\/p>\n\n\n\n

                              \n\n\n\n

                              Q.70: Make your own sequences and challenge your classmates to extend the pattern.<\/p>\n\n\n\n

                              Solution:<\/p>\n\n\n\n

                              Some more sequences and their solutions:<\/p>\n\n\n\n

                                \n
                              1. {tex}7.2,7.5,7.8, \\ldots{\/tex}
                                Each term increases by 0.3
                                Next after 7.8: {tex} 7.8+0.3=8.1{\/tex}
                                Next: {tex}8.1+0.3=8.4{\/tex}
                                Next: {tex}8.4+0.3=8.7{\/tex}
                                {tex}\\therefore{\/tex} Next 3 terms are 8.1, 8.4, 8.7<\/li>\n\n\n\n
                              2. {tex}15,14.6,14.2, \\ldots{\/tex}
                                Each term decreases by 0.4
                                Next after 14.2: {tex}14.2-0.4=13.8{\/tex}
                                Next: {tex} 13.8-0.4=13.4{\/tex}
                                Next: {tex}13.4-0.4=13.0{\/tex}
                                {tex}\\therefore{\/tex} Next 3 terms are 13.8, 13.4, 13.0<\/li>\n\n\n\n
                              3. 22.1, 23.3, 24.5, …
                                Each term increases by 1.2
                                Next after 24.5: {tex}24.5+1.2=25.7{\/tex}
                                Next: {tex} 25.7+1.2=26.9{\/tex}
                                Next: {tex} 26.9+1.2=28.1{\/tex}
                                {tex}\\therefore{\/tex} Next 3 terms are 25.7, 26.9, 28.1<\/li>\n\n\n\n
                              4. {tex}0.5,1.0,1.5, \\ldots{\/tex}
                                Each term increases by 0.5
                                Next after 1.5: {tex} 1.5+0.5=2.0{\/tex}
                                Next: {tex}2.0+0.5=2.5{\/tex}
                                Next: {tex}2.5+0.5=3.0{\/tex}
                                {tex}\\therefore{\/tex} Next 3 terms are 2.0, 2.5, 3.0<\/li>\n\n\n\n
                              5. {tex}18.25,17.75,17.25, \\ldots{\/tex}
                                Each term decreases by 0.5
                                Next after 17.25: {tex}17.25-0.5=16.75{\/tex}
                                Next: {tex}16.75-0.5=16.25{\/tex}
                                Next: {tex}16.25-0.5=15.75{\/tex}
                                {tex}\\therefore{\/tex} Next 3 terms are 16.75, 16.25, 15.75<\/li>\n<\/ol>\n\n\n\n
                                \n\n\n\n

                                Q.71: What do you think about this claim? Verify if this is true for these numbers. Will it work for any 2 decimal numbers?<\/p>\n\n\n\n

                                Solution:<\/p>\n\n\n\n

                                Both the claims hold true.
                                Verifying for 25.936 and 8.202:

                                Verifying with other numbers:
                                <\/p>\n\n\n\n

                                \n\n\n\n

                                Q.72: What about the sum of 25.93603259 and 8.202?<\/p>\n\n\n\n

                                Solution:<\/p>\n\n\n\n

                                The given numbers are 25.93603259 and 8.202.
                                Sum of whole number parts = 25 + 8 = 33
                                Sum of given decimal numbers = 25.93603259 + 8.202 = 34.13803259
                                Clearly, 33 < 34.13803259 < (33 + 2)<\/p>\n\n\n\n

                                \n\n\n\n

                                Q.73: Where else can we see such \u2018non-decimals\u2019 with a decimal-like notation?<\/p>\n\n\n\n

                                Solution:<\/p>\n\n\n\n

                                  \n
                                1. Train or flight schedules like 08.20 or 17.55 are in HH.MM format, not decimal.<\/li>\n\n\n\n
                                2. Software versions like 3.6.2 version number-not a decimal, but a versioning system (3 major, 6 minor, 2 patch updates).<\/li>\n\n\n\n
                                3. In books and chapter like Chapter 5.4 = Chapter 5, Section 4.<\/li>\n<\/ol>\n\n\n\n
                                  \n\n\n\n

                                  Q.74: Find the sum\u00a0and difference of\u00a0{tex}\\frac{3}{10}+3 \\frac{4}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex}\\frac{3}{10}+3 \\frac{4}{100}=\\frac{30}{100}+3+\\frac{4}{100}{\/tex} {tex}=3+\\left(\\frac{30}{100}+\\frac{4}{100}\\right)=3+\\frac{34}{100}=3 \\frac{34}{100}{\/tex}<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.75: Find the sum and difference of\u00a0{tex}9 \\frac{5}{10} \\frac{7}{100}+2 \\frac{1}{10} \\frac{3}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex} =(9+2)+\\left(\\frac{5}{10}+\\frac{1}{10}\\right)+\\left(\\frac{7}{100}+\\frac{3}{100}\\right) {\/tex}
                                  {tex} =11+\\left(\\frac{5+1}{10}\\right)+\\left(\\frac{7+3}{100}\\right) {\/tex}
                                  {tex} =11+\\frac{6}{10}+\\frac{10}{100} {\/tex}
                                  {tex} =11+\\frac{6}{10}+\\frac{1}{10}=11+\\frac{7}{10}=11 \\frac{7}{10} . {\/tex}<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.76: Find the sum\u00a0and difference of\u00a0{tex}15 \\frac{6}{10} \\frac{4}{100}+14 \\frac{3}{10} \\frac{6}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex} =(15+14)+\\left(\\frac{6}{10}+\\frac{3}{10}\\right)+\\left(\\frac{4}{100}+\\frac{6}{100}\\right) {\/tex}
                                  {tex} =29+\\left(\\frac{6+3}{10}\\right)+\\left(\\frac{4+6}{100}\\right) {\/tex}
                                  {tex} =29+\\frac{9}{10}+\\frac{10}{100} {\/tex}
                                  {tex} =29+\\frac{9}{10}+\\frac{1}{10} {\/tex}
                                  {tex} =29+\\frac{10}{10}=29+1=30 . {\/tex}<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.77: Find the sum\u00a0and difference of\u00a0{tex}7 \\frac{7}{100}-4 \\frac{4}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex}7 \\frac{7}{100}-4 \\frac{4}{100}=(7-4)+\\left(\\frac{7}{100}-\\frac{4}{100}\\right){\/tex} {tex}=3+\\frac{3}{100}=3 \\frac{3}{100}{\/tex}.<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.78: Find the sum\u00a0and difference of\u00a0{tex}8 \\frac{6}{100}-5 \\frac{3}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex}8 \\frac{6}{100}-5 \\frac{3}{100}=(8-5)+\\left(\\frac{6}{100}-\\frac{3}{100}\\right)=3+\\frac{3}{100}=3 \\frac{3}{100}{\/tex}.<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.79: Find the sum\u00a0and difference of\u00a0{tex}12 \\frac{6}{10} \\frac{2}{100}-\\frac{9}{10} \\frac{9}{100}{\/tex}<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  {tex}12 \\frac{6}{10} \\frac{2}{100}-\\frac{9}{10} \\frac{9}{100}{\/tex}
                                  {tex} =12 \\frac{62}{100}-\\frac{99}{100} {\/tex}
                                  {tex} =11+1+\\frac{62}{100}-\\left(\\frac{99}{100}\\right) {\/tex}
                                  {tex} =11+\\frac{100}{100}+\\frac{62}{100}-\\left(\\frac{99}{100}\\right) {\/tex}
                                  {tex} =11+\\frac{162}{100}-\\left(\\frac{99}{100}\\right) {\/tex}
                                  {tex} =11+\\left(\\frac{162}{100}-\\frac{99}{100}\\right) {\/tex}
                                  {tex} =11+\\frac{63}{100}=11 \\frac{63}{100} . {\/tex}<\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.80: Find the sum of 5.3<\/strong> +<\/strong>\u00a02.6<\/strong><\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  5.3 + 2.6 = 7.9
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.81: Find the sum of 18 + 8.8<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  18 + 8.8 = 18.0 + 8.8 = 26.8
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.82: Find the sum of 2.15 + 5.26<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  2.15 + 5.26 = 7.41
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.83: Find the sum of 9.01 + 9.10<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  9.01 + 9.10 = 18.11
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.84: Find the sum of 29.19 + 9.91<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  29.19 + 9.91 = 39.10
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.85: Find the sum of 0.934 + 0.6<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  0.934 + 0.6 = 1.534
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.86: Find the sum of 0.75 + 0.03<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  0.75 + 0.03 = 0.78
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.87: Find the sum of 6.236 + 0.487<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  6.236 + 0. 487 = 6.723
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.88: Find the difference of 5.6 –\u00a02.3<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  5.6 – 2.3 = 3.3
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.89: Find the difference of 18 – 8.8<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  18 – 8.8 = 9.2
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.90: Find the difference of 10.4 – 4.5<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  10.4 – 4.5 = 5.9
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.91: Find the difference of 17 – 16.198<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  17 – 16.198 = 0.802
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.92: Find the difference of 17 – 0.05<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  17 – 0.05 = 16.95
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.93: Find the difference of 34.505 – 18.1<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  34.505 – 18.1 = 16.405
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.94: Find the difference of 9.9 – 9.09<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  9.9 – 9.09 = 0.81
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.95: Find the difference of 6.236 – 0.487<\/p>\n\n\n\n

                                  Solution:<\/p>\n\n\n\n

                                  6.236 – 0.487 = 5.749
                                  <\/p>\n\n\n\n

                                  \n\n\n\n

                                  Q.96: Convert the following fractions into decimals:<\/p>\n\n\n\n

                                    \n
                                  1. {tex}\\frac{5}{10}{\/tex}<\/li>\n\n\n\n
                                  2. {tex}\\frac{16}{1000}{\/tex}<\/li>\n\n\n\n
                                  3. {tex}\\frac{12}{10}{\/tex}<\/li>\n\n\n\n
                                  4. {tex}\\frac{254}{1000}{\/tex}<\/li>\n<\/ol>\n\n\n\n

                                    Solution:<\/p>\n\n\n\n

                                      \n
                                    1. {tex}\\frac{5}{10}=0.5{\/tex}<\/li>\n\n\n\n
                                    2. {tex}\\frac{16}{1000}=0.016{\/tex}<\/li>\n\n\n\n
                                    3. {tex}\\frac{12}{10}=1.2{\/tex}<\/li>\n\n\n\n
                                    4. {tex}\\frac{254}{1000}=0.254{\/tex}<\/li>\n<\/ol>\n\n\n\n
                                      \n\n\n\n

                                      Q.97: Convert the following decimals into a sum of tenths, hundredths and thousandths:<\/p>\n\n\n\n

                                        \n
                                      1. 0.34<\/li>\n\n\n\n
                                      2. 1.02<\/li>\n\n\n\n
                                      3. 0.8<\/li>\n\n\n\n
                                      4. 0.362<\/li>\n<\/ol>\n\n\n\n

                                        Solution:<\/p>\n\n\n\n

                                          \n
                                        1. {tex}0.34=\\left(3 \\times \\frac{1}{10}\\right)+\\left(4 \\times \\frac{1}{100}\\right){\/tex}.<\/li>\n\n\n\n
                                        2. {tex}1.02=(1 \\times 1)+\\left(2 \\times \\frac{1}{100}\\right){\/tex}.<\/li>\n\n\n\n
                                        3. {tex}0.8=\\left(8 \\times \\frac{1}{10}\\right){\/tex}.<\/li>\n\n\n\n
                                        4. {tex}0.362=\\left(3 \\times \\frac{1}{10}\\right)+\\left(6 \\times \\frac{1}{100}\\right)+\\left(2 \\times \\frac{1}{1000}\\right){\/tex}.<\/li>\n<\/ol>\n\n\n\n
                                          \n\n\n\n

                                          Q.98: What decimal number does each letter represent in the number line below?
                                          <\/p>\n\n\n\n

                                          Solution:<\/p>\n\n\n\n

                                          Divisions between 6.4 and {tex}6.6=8{\/tex}
                                          Each division {tex}=\\frac{6.6-6.4}{8}=\\frac{0.2}{8}=\\frac{2}{80}=0.025{\/tex}
                                          Therefore,
                                          {tex} a=6.4+(2 \\times 0.025)=6.4+0.050=6.425 . {\/tex}
                                          {tex} c=6.4+(5 \\times 0.025)=6.4+0.125=6.525 . {\/tex}
                                          {tex} b=6.4+(6 \\times 0.025)=6.4+0.150=6.550 . {\/tex}<\/p>\n\n\n\n

                                          \n\n\n\n

                                          Q.99:<\/p>\n\n\n\n

                                          Arrange the following quantities in descending order:<\/p>\n\n\n\n

                                            \n
                                          1. 11.01, 1.011, 1.101, 11.10, 1.01<\/li>\n\n\n\n
                                          2. 2.567, 2.675, 2.768, 2.499, 2.698<\/li>\n\n\n\n
                                          3. 4.678 g, 4.595 g, 4.600 g, 4.656 g, 4.666 g<\/li>\n\n\n\n
                                          4. 33.13 m, 33.31 m, 33.133 m, 33.331 m, 33.313 m<\/li>\n<\/ol>\n\n\n\n

                                            Solution:<\/p>\n\n\n\n

                                              \n
                                            1. {tex} 11.10>11.01>1.101>11.011>1.01 . {\/tex}<\/li>\n\n\n\n
                                            2. {tex} 2.768>2.698>2.675>2.567>2.499 . {\/tex}<\/li>\n\n\n\n
                                            3. {tex} 4.678 {~g}>4.666 {~g}>4.656 {~g}>4.600 {~g}>4.595 {~g} . {\/tex}<\/li>\n\n\n\n
                                            4. {tex} 33.331 {~m}>33.313 {~m}>33.31 {~m}>33.133 {~m}>33.13 {~m} . {\/tex}<\/li>\n<\/ol>\n\n\n\n
                                              \n\n\n\n

                                              Q.100: Using the digits 1, 4, 0, 8, and 6 make:<\/p>\n\n\n\n

                                                \n
                                              1. the decimal number closest to 30<\/li>\n\n\n\n
                                              2. the smallest possible decimal number between 100 and 1000.<\/li>\n<\/ol>\n\n\n\n

                                                Solution:<\/p>\n\n\n\n

                                                  \n
                                                1. Possible numbers: {tex}14.860,40.168{\/tex}
                                                  {tex} 30-14.860=15.14 {\/tex}
                                                  {tex} 40.168-30=10.168 {\/tex}
                                                  Hence, 40.168 is the closet number to 30.<\/li>\n\n\n\n
                                                2. Smallest number between 100 and 1000 = 104.68<\/li>\n<\/ol>\n\n\n\n
                                                  \n\n\n\n

                                                  Q.101: Will a decimal number with more digits be greater than a decimal number with fewer digits?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  Not always. A number with more decimal digits may be smaller.
                                                  Example:
                                                  0.9 has 1 decimal digit.
                                                  0.89 has 2 decimal digits.
                                                  But, 0.9 > 0.89.<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.102: Mahi purchases 0.25 kg of beans, 0.3 kg of carrots, 0.5 kg of potatoes, 0.2 kg of capsicums, and 0.05 kg of ginger. Calculate the total weight of the items she bought.<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  Beans = 0.25 kg
                                                  Carrots = 0.3 kg
                                                  Potatoes = 0.5 kg
                                                  Capsicum = 0.2 kg
                                                  Ginger = 0.05 kg
                                                  Total weight = (0.25 + 0.3 +0.5 + 0.2 + 0.05) kg = 1.3 kg<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.103: Pinto supplies 3.79 L, 4.2 L, and 4.25 L of milk to a milk dairy in the first three days. In 6 days, he supplies 25 litres of milk. Find the total quantity of milk supplied to the dairy in the last three days.<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  Milk supplied in first 3 days {tex}=3.79+4.2+4.25=12.24 {~L}{\/tex}
                                                  Milk supplied in 6 days {tex}=25 {~L}{\/tex}
                                                  Milk supplied in last three days {tex}=25 {~L}-12.24 {~L}=12.76{\/tex}.<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.104: Tinku weighed 35.75 kg in January and 34.50 kg in February. Has he gained or lost weight? How much is the change?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  Tinku’s weight:
                                                  In January {tex}=35.75 {~kg}{\/tex}
                                                  In February {tex}=34.50 {~kg}{\/tex}
                                                  Change in weight {tex}=35.75 {~kg}-34.50 {~kg}=1.25 {~kg}{\/tex}
                                                  Tinku has lost weight and the change in weight is 1.25 kg.<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.105: How many millimeters make 1 kilometer?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  {tex} 1 {~km}=1000 {~m}=(1000 \\times 100) {cm}{\/tex} {tex}=(100000 \\times 10)=10,00,000 {~mm} . {\/tex}
                                                  {tex} \\therefore 10,00,000 {~mm} \\text { make } 1 {~km} . {\/tex}<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.106: What is the decimal form of 87 ones, 5 tenths and 60 hundredths = 88.10?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  {tex} 87 \\text { ones, } 5 \\text { tenths and } 60 \\text { hundredths } {\/tex}{tex}=(87 \\times 1)+\\left(5 \\times \\frac{1}{10}\\right)+\\left(60 \\times \\frac{1}{100}\\right) {\/tex}
                                                  {tex} =87+\\frac{5}{10}+\\frac{6}{10} {\/tex}
                                                  {tex}=87+0.5+0.6=88.10{\/tex}<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.107: What is the decimal form of 12 tens and 12 tenths?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  {tex} 12 \\text { tens and } 12 \\text { tenths } =(12 \\times 10)+\\left(12 \\times \\frac{1}{10}\\right) {\/tex}
                                                  {tex} =120+\\frac{12}{10} {\/tex}
                                                  {tex} =120+1.2=121.2 {\/tex}<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.108: What is the decimal form of 10 tens, 10 ones, 10 tenths, and 10 hundredths?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  10 tens, 10 ones, 10 tenths, and 10 hundredths
                                                  {tex} =(10 \\times 10)+(10 \\times 1)+\\left(10 \\times \\frac{1}{10}\\right)+\\left(10 \\times \\frac{1}{100}\\right) {\/tex}
                                                  {tex} =100+10+1+\\frac{1}{10} {\/tex}
                                                  {tex} =111+10+1+0.1 {\/tex}
                                                  {tex} =111.1 {\/tex}<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.109: What is the decimal form of 25 tens, 25 ones, 25 tenths, and 25 hundredths?<\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  25 tens, 25 ones, 25 tenths, and 25 hundredths
                                                  {tex} =(25 \\times 10)+(25 \\times 1)+\\left(25 \\times \\frac{1}{10}\\right)+\\left(25 \\times \\frac{1}{100}\\right) {\/tex}
                                                  {tex} =250+25+\\frac{25}{10}+\\frac{25}{100} {\/tex}
                                                  {tex} =250+25+2.5+0.25 {\/tex}
                                                  {tex} =277.75 {\/tex}<\/p>\n\n\n\n

                                                  \n\n\n\n

                                                  Q.110: Using each digit 0 \u2013 9 not more than once, fill the boxes below so that the sum is closest to 10.5:
                                                  <\/p>\n\n\n\n

                                                  Solution:<\/p>\n\n\n\n

                                                  \"\"\/<\/figure>\n\n\n\n
                                                  \n\n\n\n

                                                  Q.111: Write the following fractions in decimal form:<\/p>\n\n\n\n

                                                    \n
                                                  1. {tex}\\frac{1}{2}{\/tex}<\/li>\n\n\n\n
                                                  2. {tex}\\frac{3}{2}{\/tex}<\/li>\n\n\n\n
                                                  3. {tex}\\frac{1}{4}{\/tex}<\/li>\n\n\n\n
                                                  4. {tex}\\frac{3}{4}{\/tex}<\/li>\n\n\n\n
                                                  5. {tex}\\frac{1}{5}{\/tex}<\/li>\n\n\n\n
                                                  6. {tex}\\frac{4}{5}{\/tex}<\/li>\n<\/ol>\n\n\n\n

                                                    Solution:<\/p>\n\n\n\n

                                                      \n
                                                    1. {tex}\\frac{1}{2}=\\frac{1}{2} \\times 1{\/tex}
                                                      {tex} =\\frac{1}{2} \\times \\frac{10}{10}=\\frac{5}{10}=0.5 {\/tex}<\/li>\n\n\n\n
                                                    2. {tex} \\frac{3}{2} =\\frac{3}{2} \\times 1 {\/tex}
                                                      {tex} =\\frac{3}{2} \\times \\frac{10}{10}=\\frac{15}{10}=1.5 {\/tex}<\/li>\n\n\n\n
                                                    3. {tex} \\frac{1}{4} =\\frac{1}{4} \\times 1 {\/tex}
                                                      {tex} =\\frac{1}{4} \\times \\frac{100}{100}=\\frac{25}{100}=0.25 {\/tex}<\/li>\n\n\n\n
                                                    4. {tex} \\frac{3}{4} =\\frac{3}{4} \\times 1 {\/tex}
                                                      {tex} =\\frac{3}{4} \\times \\frac{100}{100}=\\frac{75}{100}=0.75 {\/tex}<\/li>\n\n\n\n
                                                    5. {tex} \\frac{1}{5} =\\frac{1}{5} \\times 1 {\/tex}
                                                      {tex} =\\frac{1}{5} \\times \\frac{10}{10}=\\frac{2}{10}=0.2 {\/tex}<\/li>\n\n\n\n
                                                    6. {tex} \\frac{4}{5} =\\frac{4}{5} \\times 1 {\/tex}
                                                      {tex} =\\frac{4}{5} \\times \\frac{10}{10}=\\frac{8}{10}=0.8 {\/tex}<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"

                                                      A Peek Beyond the Point – NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT Class 7 Maths (Ganita Prakash). NCERT Solutions Class 7 A Peek Beyond the Point \u2013 NCERT Solutions Q.1: Which scale helped you measure the length of the screws accurately? Why? Solution: The … Read more<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[281,2082,2106],"tags":[216],"class_list":["post-31862","post","type-post","status-publish","format-standard","hentry","category-ncert-solutions","category-ncert-solutions-class-7","category-ncert-solutions-class-7-maths-ganita-prakash","tag-ncert-solutions"],"yoast_head":"\nA Peek Beyond the Point - NCERT Solutions Class 7 Maths (Ganita Prakash) | myCBSEguide<\/title>\n<meta name=\"description\" content=\"A Peek Beyond the Point - NCERT Solutions Class 7 Maths (Ganita Prakash) includes all the questions with solutions given in the NCERT.\" \/>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" 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