{"id":28464,"date":"2019-11-16T10:27:07","date_gmt":"2019-11-16T04:57:07","guid":{"rendered":"http:\/\/mycbseguide.com\/blog\/?p=28464"},"modified":"2019-11-16T12:18:02","modified_gmt":"2019-11-16T06:48:02","slug":"extra-questions-of-class-6-decimals-chapter-8-mathematics","status":"publish","type":"post","link":"https:\/\/mycbseguide.com\/blog\/extra-questions-of-class-6-decimals-chapter-8-mathematics\/","title":{"rendered":"Extra Questions of Class 6 Decimals Chapter 8 Mathematics"},"content":{"rendered":"

Extra Questions of Class 6 Decimals Chapter 8 Mathematics. <\/strong>myCBSEguide has just released Chapter Wise Question Answers for class 6 Maths. There chapter wise Practice Questions with complete solutions are available for download in\u00a0myCBSEguide<\/a>\u00a0<\/strong>website and mobile app. These Extra Questions with solution are prepared by our team of expert teachers who are teaching grade in CBSE schools for years. There are around 4-5 set of solved Mathematics Extra questions from each and every chapter. The students will not miss any concept in these Chapter wise question that are specially designed to tackle Exam. We have taken care of every single concept given in\u00a0CBSE Class 6 Mathematics<\/strong>\u00a0syllabus<\/strong><\/a>\u00a0and questions are framed as per the latest marking scheme and blue print issued by CBSE for Class 6.<\/p>\n

CBSE Class 6 Maths Extra Questions<\/strong><\/p>\n

Download as PDF<\/a><\/strong><\/p>\n

CBSE Class 6 Maths Chapter 8 Important Questions<\/h2>\n
\n

Ch-8 Decimals<\/strong><\/p>\n

\n<\/div>\n
    \n
  1. Write the decimal number represented by the points S on the given number line.
    \n\"Extra<\/p>\n
      \n
    1. 1.2<\/span><\/li>\n
    2. 1.6<\/span><\/li>\n
    3. 1.5<\/span><\/li>\n
    4. 1.4<\/li>\n<\/ol>\n<\/li>\n
    5. 3 g = ________ kg\n
        \n
      1. \n
        0.03<\/span><\/div>\n<\/li>\n
      2. \n
        0.3<\/span><\/div>\n<\/li>\n
      3. \n
        None of these<\/span><\/div>\n<\/li>\n
      4. \n
        0.003<\/span><\/div>\n<\/li>\n<\/ol>\n<\/li>\n
      5. \n
        Find: 0.29 + 0.36<\/div>\n
          \n
        1. \n
          0.065<\/span><\/div>\n<\/li>\n
        2. \n
          0.65<\/span><\/div>\n<\/li>\n
        3. \n
          None of these<\/span><\/div>\n<\/li>\n
        4. \n
          65<\/span><\/div>\n<\/li>\n<\/ol>\n<\/li>\n
        5. \n
          31.24 + 7.03 = _______<\/div>\n
            \n
          1. \n
            zero<\/span><\/div>\n<\/li>\n
          2. \n
            38.07<\/span><\/div>\n<\/li>\n
          3. \n
            38.2<\/span><\/div>\n<\/li>\n
          4. \n
            38.27<\/span><\/div>\n<\/li>\n<\/ol>\n<\/li>\n
          5. \n
            1.24 + 7.23 = _______<\/div>\n
              \n
            1. \n
              8.45<\/span><\/div>\n<\/li>\n
            2. \n
              8.07<\/span><\/div>\n<\/li>\n
            3. \n
              8.4<\/span><\/div>\n<\/li>\n
            4. \n
              8.47<\/span><\/div>\n<\/li>\n<\/ol>\n<\/li>\n
            5. \n
              \n
              \n

              Match the following-<\/strong><\/p>\n\n\n\n\n\n\n\n\n
              Column I<\/th>\nColumn II<\/th>\n<\/tr>\n<\/thead>\n
              a. 2m 5cm<\/td>\ni. 20 Rupees 15 paise<\/td>\n<\/tr>\n
              b. 14.035 km<\/td>\nii. Rs. 0.50<\/td>\n<\/tr>\n
              c. Rs 20.15<\/td>\niii. 2.05 m<\/td>\n<\/tr>\n
              d. 50 paise<\/td>\niv. 14km 35m<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<\/div>\n<\/li>\n
            6. \n
              \n
              \n

              Fill in the blanks.<\/strong><\/p>\n

                \n
              1. {tex}25.135 = 25 + \\frac{1}{{\\__{}}} + \\frac{3}{{\\__{}}} + \\frac{5}{{\\__{}}}{\/tex}<\/span><\/li>\n
              2. {tex}66.606 = 60 + \\__{} + \\frac{6}{{\\__{}}} + 0 + \\frac{6}{{\\__{}}}{\/tex}<\/span><\/li>\n
              3. {tex}14 + \\frac{5}{{1000}} + \\frac{6}{{10}} = 14.\\__{}0\\__{}{\/tex}<\/span><\/li>\n
              4. {tex}\\frac{4}{{100}} + 5 = \\_\\_.0\\_\\_{\/tex}<\/span><\/li>\n<\/ol>\n<\/div>\n
                <\/div>\n<\/div>\n<\/li>\n
              5. \n
                \n
                \n

                State True or False:-<\/strong><\/p>\n

                  \n
                1. Rs. 60.75 can also expressed as 60Rs 75p.<\/li>\n
                2. Adding 70.25 and 14.6 gives 84.85.<\/li>\n
                3. 1 kg is equals to 100 grams.<\/li>\n
                4. Expanded form of 23.05 is {tex}20 + 3 + \\frac{0}{{10}} + \\frac{5}{{100}}{\/tex}<\/span>.<\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/li>\n
                5. \n
                  \n
                  \n

                  Arrange the following decimal numbers in descending order.
                  \n8.51, 8.06, 9.10, 8.57<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                6. \n
                  \n
                  \n

                  Express {tex}\\frac{6}{{100}}{\/tex}<\/span> as decimal.<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                7. \n
                  \n
                  \n

                  Express the following as cm using decimals : 30 mm<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                8. \n
                  \n
                  \n

                  Show 1.1 on the number line.<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                9. \n
                  \n
                  \n

                  Express the following as cm using decimals
                  \n116 mm.<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                10. \n
                  \n
                  \n

                  Subtract 0.314 kg from 2.107 kg.<\/p>\n<\/div>\n<\/div>\n<\/li>\n

                11. \n
                  \n
                  \n

                  Subtract the sum of 114.753 and 70.14 from the sum of 93.12 and 212.15.<\/p>\n<\/div>\n<\/div>\n<\/li>\n<\/ol>\n

                  Ch-8 Decimals<\/strong><\/p>\n

                  \n

                  Answer<\/strong><\/p>\n

                    \n
                  1. \n
                      \n
                    1. 1.5
                      \nExplanation: S is lies after 1 and fifth part toward right. So the decimal number represented by the points S on the given number line is 1.5.<\/li>\n<\/ol>\n<\/li>\n
                    2. \n
                        \n
                      1. 0.003
                        \nExplanation: 1000 g = 1 kg3 g = {tex}{3 \\over {1000}}{\/tex}<\/span> kg= 0.003 kg<\/li>\n<\/ol>\n<\/li>\n
                      2. \n
                          \n
                        1. 0.65
                          \nExplanation: 0.29 + 0.36 = 0.65<\/li>\n<\/ol>\n<\/li>\n
                        2. \n
                            \n
                          1. 38.27
                            \nExplanation: 31.24 + 7.03 = 38.27<\/li>\n<\/ol>\n<\/li>\n
                          2. \n
                              \n
                            1. 8.47
                              \nExplanation: 1.24 + 7.23 = 8.47<\/li>\n<\/ol>\n<\/li>\n
                            2. \n
                                \n
                              1. {tex} \\to {\/tex}<\/span> iii
                                \n100 cm = 1 m
                                \nso, 5 cm = {tex}\\frac{5}{100}{\/tex}<\/span> m
                                \nTherefore, 2 m 5 cm = 2 m + {tex}\\frac{5}{100}{\/tex}<\/span> m
                                \n= 2 m + 0.05 m
                                \n= 2.05 m<\/li>\n
                              2. {tex} \\to {\/tex}<\/span> iv
                                \n1 km = 1000 m
                                \n14.035 km = 14.035 {tex}\\times{\/tex}<\/span> 1000 m
                                \n= 14035 m
                                \n= 14000 m + 35 m
                                \n= 14 km + 35 m = 14 km 35 m.<\/li>\n
                              3. {tex} \\to {\/tex}<\/span> i
                                \n1 Rupee = 100 paise
                                \nRs. 20.15 = 20.15 {tex}\\times{\/tex}<\/span> 100 p
                                \n= 2015 paise
                                \n= 2000 paise + 15 paise
                                \n= 20 Rupees + 15 paise = 20 Rupees 15 paise.<\/li>\n
                              4. {tex} \\to {\/tex}<\/span> ii
                                \n100 paise = 1 Rupee
                                \n50 paise = Rs. {tex}\\frac{50}{100}{\/tex}<\/span> = Rs. 0.50.<\/li>\n<\/ol>\n<\/li>\n
                              5. \n
                                  \n
                                1. 10, 100, 1000.
                                  \nIn the decimal number, 25.135, 1 is in tenths place. So its place value is {tex}\\frac{1}{10}{\/tex}<\/span>, 3 is in hundredths place. So, its place value is {tex}\\frac{3}{100}{\/tex}<\/span>.
                                  \n6 is in thousandths place. So, its place value is {tex}\\frac{6}{1000}{\/tex}<\/span>.
                                  \nTherefore, {tex}25.135 = 25 + \\frac{1}{10} + \\frac{3}{100} + \\frac{5}{1000}{\/tex}<\/span><\/li>\n
                                2. 6, 10, 1000
                                  \nIn the decimal number, 66..606, the place values of each 6 from left to right are: 60, 6, {tex}\\frac{6}{10}{\/tex}<\/span>, {tex}\\frac{0}{100}, \\frac{6}{1000}{\/tex}<\/span>
                                  \nTherefore, 66.606 = 60 + 6 + {tex}\\frac{6}{10}{\/tex}<\/span> + 0 + {tex}\\frac{6}{1000}{\/tex}<\/span><\/li>\n
                                3. 6, 5
                                  \nThe given expanded form 14 + {tex}\\frac{5}{1000} + \\frac{6}{10}{\/tex}<\/span> can be written in the correct order as, 14 + {tex}\\frac{6}{10}+\\frac{0}{100}+\\frac{5}{1000}{\/tex}<\/span>
                                  \ni.e., 6 is in tenths place, 0 is in hundredths place and 5 is in thousandths place.
                                  \nSo, the decimal number can be written as 14.605.<\/li>\n
                                4. 5, 4
                                  \nThe given expanded form {tex}\\frac{4}{100} + 5{\/tex}<\/span> can be written in the correct order as, 5 + {tex}\\frac{0}{10} + \\frac{4}{100}{\/tex}<\/span>.
                                  \ni.e., 0 is in tenths place and 4 is in hundredths place. So, the decimal number can be written as 5.04.<\/li>\n<\/ol>\n<\/li>\n
                                5. \n
                                    \n
                                  1. True(Rs.60.75 = Rs 60 + Rs 0.75 = Rs 60 + Rs {tex}\\frac{75}{100}{\/tex}<\/span>= 60Rs 75p)<\/li>\n
                                  2. True ( By changing both numbers in to like decimals and adding, 70.25 + 14.60 = 84.85)<\/li>\n
                                  3. False (We know that 1Kg = 1000g)<\/li>\n
                                  4. True ( The expanded form of 23.05 = 2 Tens + 3 Ones + 0 Tenths + 5 Hundredths = 20 + 3 + {tex}\\frac{0}{10}{\/tex}<\/span> + {tex}\\frac{5}{100}{\/tex}<\/span>)<\/li>\n<\/ol>\n<\/li>\n
                                  5. The given decimal numbers are like decimals. By checking the digits before decimal, we observe that 9.10 is largest of given numbers. Among the remaining numbers, by checking the tenths place, we observe that 8.06 is the least. Out of remaining numbers, by checking the hundredths place, we observe that 8.57 is bigger than 8.51. So, by arranging the given numbers from big to small, we have,
                                    \n{tex} \\Rightarrow {\/tex}<\/span> 9.10, 8.57, 8.51, 8.06<\/li>\n
                                  6. {tex}\\frac{6}{100}{\/tex}<\/span> = 0.06<\/li>\n
                                  7. {tex}\\begin{array}{l}\\;1\\;mm\\;=\\;\\frac1{10}\\;cm\\\\so\\;30\\;mm\\;=\\;\\frac{30}{10}\\;\\;cm\\\\\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;\\;=\\;\\;3\\;cm\\;=\\;3.0\\;cm\\;\\end{array}{\/tex}<\/span><\/li>\n
                                  8. We know that 1.1 is more than one but less than two. There is one-tenth in it. Divide the unit length between 1 and 2 into 10 equal parts and take 1 part as shown below :
                                    \n\"Extra<\/li>\n
                                  9. 116 mm = {tex}\\frac{116}{10}{\/tex}<\/span> cm [{tex}\\because{\/tex}<\/span> 1 mm {tex}=\\frac{1}{10}{\/tex}<\/span>cm]\n{tex}=\\frac{110+6}{10}{\/tex}<\/span> cm {tex}=\\left(\\frac{110}{10}+\\frac{6}{10}\\right){\/tex}<\/span>cm {tex}=\\left(11+\\frac{6}{10}\\right){\/tex}<\/span>cm
                                    \n= 11.6 cm<\/li>\n
                                  10. 0.314 kg from 2.107 kg = 1.793 kg \"Extra<\/li>\n
                                  11. Sum of 114.753 and 70.14:- {tex}\\frac{{ + \\begin{array}{*{20}{c}} {114.753} \\\\ {70.140} \\end{array}}}{{184.893}}{\/tex}<\/span> Sum of 212.15 and 93.12:- {tex}\\frac{{ + \\begin{array}{*{20}{c}} {212.15} \\\\ {93.12} \\end{array}}}{{305.27}}{\/tex}<\/span>
                                    \nDifference in their sums = {tex}\\frac{{ – \\begin{array}{*{20}{c}} {305.270} \\\\ {184.893} \\end{array}}}{{120.377}}{\/tex}<\/span><\/li>\n<\/ol>\n

                                    Chapter Wise Extra Questions for Class 6 Mathematics<\/h2>\n
                                    \n
                                    \n
                                    \n
                                      \n
                                    1. Knowing our Numbers<\/a><\/li>\n
                                    2. Whole Numbers<\/a><\/li>\n
                                    3. Playing with Numbers<\/a><\/li>\n
                                    4. Basic Geometrical Ideas<\/a><\/li>\n
                                    5. Understanding Elementary Shapes<\/a><\/li>\n
                                    6. Integers<\/a><\/li>\n
                                    7. Fractions<\/a><\/li>\n
                                    8. Decimals<\/a><\/li>\n
                                    9. Data handling<\/a><\/li>\n
                                    10. Mensuration<\/a><\/li>\n
                                    11. Algebra<\/a><\/li>\n
                                    12. Ratio and Proportion<\/a><\/li>\n
                                    13. Symmetry<\/a><\/li>\n
                                    14. Practical Geometry<\/a><\/li>\n<\/ol>\n<\/div>\n<\/div>\n<\/div>\n","protected":false},"excerpt":{"rendered":"

                                      Extra Questions of Class 6 Decimals Chapter 8 Mathematics. myCBSEguide has just released Chapter Wise Question Answers for class 6 Maths. There chapter wise Practice Questions with complete solutions are available for download in\u00a0myCBSEguide\u00a0website and mobile app. These Extra Questions with solution are prepared by our team of expert teachers who are teaching grade in … Read more<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1346,1395],"tags":[1877,1871,1839,1838,1833,1832],"class_list":["post-28464","post","type-post","status-publish","format-standard","hentry","category-cbse","category-mathematics-cbse-class-06","tag-cbse-class-6-mathematics","tag-chapter-wise-important-questions","tag-extra-questions","tag-important-questions","tag-latest-exam-questions","tag-practice-questions"],"yoast_head":"\nExtra Questions of Class 6 Decimals Chapter 8 Mathematics<\/title>\n<meta name=\"description\" content=\"Extra Questions of Class 6 Decimals Chapter 8 Mathematics 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