# NCERT Solutions for Class 7 Maths Exercise 2.4

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NCERT solutions for Maths Fractions and Decimals

## NCERT Solutions for Class 7 Maths Fractions and Decimals

###### Question 1.Find:

(i) {tex}12 \div \frac{3}{4}{/tex}

(ii) {tex}14 \div \frac{5}{6}{/tex}

(iii) {tex}8 \div \frac{7}{3}{/tex}

(iv) {tex}4 \div \frac{8}{3}{/tex}

(v) {tex}3 \div 2\frac{1}{3}{/tex}

(vi) {tex}5 \div 3\frac{4}{7}{/tex}

(i) {tex}12 \div \frac{3}{4}{/tex} = {tex}12 \times \frac{4}{3}{/tex} = 16

(ii){tex}14 \div \frac{5}{6}{/tex} = {tex}14 \times \frac{6}{5} = \frac{{84}}{5} = 16\frac{4}{5}{/tex}

(iii) {tex}8 \div \frac{7}{3}{/tex} = {tex}8 \times \frac{3}{7} = \frac{{24}}{7} = 3\frac{3}{7}{/tex}

(iv) {tex}4 \div \frac{8}{3}{/tex} = {tex}4 \times \frac{3}{8} = \frac{3}{2} = 1\frac{1}{2}{/tex}

(v) {tex}3 \div 2\frac{1}{3}{/tex} = {tex}3 \div \frac{7}{3} = 3 \times \frac{3}{7} = \frac{9}{7} = 1\frac{2}{7}{/tex} (vi) {tex}5 \div 3\frac{4}{7}{/tex} = {tex}5 \div \frac{{25}}{7} = 5 \times \frac{7}{{25}} = \frac{7}{5} = 1\frac{2}{5}{/tex}

NCERT Solutions for Class 7 Maths Exercise 2.4

###### Question 2. Find the reciprocal of each of the following fractions. Classify the reciprocals as proper fraction, improper fractions and whole numbers.

(i) {tex}\frac{3}{7}{/tex}

(ii) {tex}\frac{5}{8}{/tex}

(iii) {tex}\frac{9}{7}{/tex}

(iv) {tex}\frac{6}{5}{/tex}

(v) {tex}\frac{{12}}{7}{/tex}

(vi) {tex}\frac{1}{8}{/tex}

(vii) {tex}\frac{1}{{11}}{/tex}

(i) Reciprocal of {tex}\frac{3}{7}{\text{ }} = {\text{ }}\frac{7}{3}{\text{ }}\xrightarrow{{}}{/tex} Improper fraction

(ii) Reciprocal of {tex}\frac{5}{8}{\text{ }} = {\text{ }}\frac{8}{5}{\text{ }}\xrightarrow{{}}{/tex} Improper fraction

(iii) Reciprocal of {tex}\frac{9}{7}{\text{ }} = {\text{ }}\frac{7}{9}{\text{ }}\xrightarrow{{}}{/tex} Proper fraction

(iv) Reciprocal of {tex}\frac{6}{5}{\text{ }} = {\text{ }}\frac{5}{6}{\text{ }}\xrightarrow{{}}{/tex} Proper fraction

(v)Reciprocal of {tex}\frac{{12}}{7}{\text{ }} = {\text{ }}\frac{7}{{12}}{\text{ }}\xrightarrow{{}}{/tex} Proper fraction

(vi) Reciprocal of {tex}\frac{1}{8}{\text{ }} = {\text{ 8 }}\xrightarrow{{}}{/tex} Whole number

(vi) Reciprocal of {tex}\frac{1}{{11}}{\text{ }} = {\text{ 11 }}\xrightarrow{{}}{/tex} Whole number

NCERT Solutions for Class 7 Maths Exercise 2.4

##### Question 3.Find:

(i) {tex}\frac{7}{3} \div 2{/tex}

(ii) {tex}\frac{4}{9} \div 5{/tex}

(iii) {tex}\frac{6}{{13}} \div 7{/tex}

(iv) {tex}4\frac{1}{3} \div 3{/tex}

(v) {tex}3\frac{1}{2} \div 4{/tex}

(vi) {tex}4\frac{3}{7} \div 7{/tex}

(i) {tex}\frac{7}{3} \div 2 = \frac{7}{3} \times \frac{1}{2} = \frac{{7 \times 1}}{{3 \times 2}} = \frac{7}{6} = 1\frac{1}{6}{/tex}

(ii) {tex}\frac{4}{9} \div 5 = \frac{4}{9} \times \frac{1}{5} = \frac{{4 \times 1}}{{9 \times 5}} = \frac{4}{{45}}{/tex}

(iii) {tex}\frac{6}{{13}} \div 7 = \frac{6}{{13}} \times \frac{1}{7} = \frac{{6 \times 1}}{{13 \times 7}} = \frac{6}{{91}}{/tex}

(iv) {tex}4\frac{1}{3} \div 3 = \frac{{13}}{3} \div 3 = \frac{{13}}{3} \times \frac{1}{3} = \frac{{13}}{9} = 1\frac{4}{9}{/tex}

(v) {tex}3\frac{1}{2} \div 4 = \frac{7}{2} \div 4 = \frac{7}{2} \times \frac{1}{4} = \frac{7}{8}{/tex}

(vi) {tex}4\frac{3}{7} \div 7 = \frac{{31}}{7} \div 7 = \frac{{31}}{7} \times \frac{1}{7} = \frac{{31}}{{49}}{/tex}

NCERT Solutions for Class 7 Maths Exercise 2.4

###### Question 4.Find:

(i) {tex}\frac{2}{5} \div \frac{1}{2}{/tex}

(ii) {tex}\frac{4}{9} \div \frac{2}{3}{/tex}

(iii) {tex}\frac{3}{7} \div \frac{8}{7}{/tex}

(iv) {tex}2\frac{1}{3} \div \frac{3}{5}{/tex}

(v) {tex}3\frac{1}{2} \div \frac{8}{3}{/tex}

(vi) {tex}\frac{2}{5} \div 1\frac{1}{2}{/tex}

(vii) {tex}3\frac{1}{5} \div 1\frac{2}{3}{/tex}

(viii) {tex}2\frac{1}{5} \div 1\frac{1}{5}{/tex}

(i) {tex}\frac{2}{5} \div \frac{1}{2} = \frac{2}{5} \times \frac{2}{1} = \frac{{2 \times 2}}{{5 \times 1}} = \frac{4}{5}{/tex}

(ii) {tex}\frac{4}{9} \div \frac{2}{3} = \frac{4}{9} \times \frac{3}{2} = \frac{2}{3}{/tex}

(iii) {tex}\frac{3}{7} \div \frac{8}{7} = \frac{3}{7} \times \frac{7}{8} = \frac{3}{8}{/tex}

(iv) {tex}2\frac{1}{3} \div \frac{3}{5} = \frac{7}{3} \div \frac{3}{5} = \frac{7}{3} \times \frac{5}{3} = \frac{{35}}{9} = 3\frac{8}{9}{/tex}

(v) {tex}3\frac{1}{2} \div \frac{8}{3} = \frac{7}{2} \div \frac{8}{3} = \frac{7}{2} \times \frac{3}{8} = \frac{{7 \times 3}}{{2 \times 8}} = \frac{{21}}{{16}} = 1\frac{5}{{16}}{/tex}

(vi) {tex}\frac{2}{5} \div 1\frac{1}{2} = \frac{2}{5} \div \frac{3}{2} = \frac{2}{5} \times \frac{2}{3} = \frac{{2 \times 2}}{{5 \times 3}} = \frac{4}{{15}}{/tex}

(vii) {tex}3\frac{1}{5} \div 1\frac{2}{3} = \frac{{16}}{5} \div \frac{5}{3} = \frac{{16}}{5} \times \frac{3}{5} = \frac{{16 \times 3}}{{5 \times 5}} = \frac{{48}}{{25}} = 1\frac{{23}}{{25}}{/tex}

(viii) {tex}2\frac{1}{5} \div 1\frac{1}{5} = \frac{{11}}{5} \div \frac{6}{5} = \frac{{11}}{5} \times \frac{5}{6} = \frac{{11}}{6} = 1\frac{5}{6}{/tex}

## NCERT Solutions for Class 7 Maths Exercise 2.4

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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