NCERT Solutions for Class 7 Maths Exercise 11.1

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NCERT Solutions for Class 7 Maths Exercise 11.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Perimeter and Area Download as PDF

NCERT Solutions for Class 7 Maths Exercise 11.1

NCERT Solutions for Class 7 Maths Perimeter and Area

Class –VII Mathematics (Ex. 11.1)
Question 1.The length and breadth of a rectangular piece of land are 500 m and 300 m respectively. Find:

(i) Its area.

(ii) The cost of the land, if 1 {tex}{m^2}{/tex}of the land costs Rs. 10,000.

Answer:

Given: Length of a rectangular piece of land = 500 m and

Breadth of a rectangular piece of land = 300 m

(i) Area of a rectangular piece of land = Length x Breadth

= 500 x 300 = 1,50,000 {tex}{m^2}{/tex}

(ii) Since, the cost of 1 {tex}{m^2}{/tex}land = Rs. 10,000

Therefore, the cost of 1,50,000 m2 land = 10,000 x 1,50,000

= Rs. 1,50,00,00,000


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 2.Find the area of a square park whose perimeter is 320 m.

Answer:

Given: Perimeter of square park = 320 m

{tex} \Rightarrow {/tex} 4 x side = 320

{tex} \Rightarrow {/tex} side = {tex}\frac{{320}}{4}{/tex} = 80 m

Now, Area of square park = side x side

= 80 x 80 = 6400 {tex}{m^2}{/tex}

Thus, the area of square park is 6400{tex}{m^2}{/tex}.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 3.Find the breadth of a rectangular plot of land, if its area is 440 {tex}{m^2}{/tex}and the length is 22 m. Also find its perimeter.

Answer:

Area of rectangular park = 440 {tex}{m^2}{/tex}

{tex} \Rightarrow {/tex} length x breadth = 440 {tex}{m^2}{/tex}

{tex} \Rightarrow {/tex} 22 x breadth = 440 {tex} \Rightarrow {/tex} breadth = {tex}\frac{{440}}{{22}}{/tex} = 20 m

Now, Perimeter of rectangular park = 2 (length + breadth)

= 2 (22 + 20)

= 2 x 42 = 84 m

Thus, the perimeter of rectangular park is 84 m.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 4.The perimeter of a rectangular sheet is 100 cm. If the length is 35 cm, find its breadth. Also find the area.

Answer:

Perimeter of the rectangular sheet = 100 cm

{tex} \Rightarrow {/tex} 2 (length + breadth) = 100 cm

{tex} \Rightarrow {/tex} 2 (35 + breadth) = 100 {tex} \Rightarrow {/tex} 35 + breadth = {tex}\frac{{100}}{2}{/tex}

{tex} \Rightarrow {/tex} 35 + breadth = 50 {tex} \Rightarrow {/tex} breadth = 50 – 35

{tex} \Rightarrow {/tex} breadth = 15 cm

Now, Area of rectangular sheet = length x breadth

= 35 x 15 = 525{tex}c{m^2}{/tex}

Thus, breadth and area of rectangular sheet are 15 cm and 525 {tex}c{m^2}{/tex}respectively.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 5.The area of a square park is the same as of a rectangular park. If the side of the square park is 60 m and the length of the rectangular park is 90 cm, find the breadth of the rectangular park.

Answer:

Given: The side of the square park = 60 m

The length of the rectangular park = 90 m

According to the question,

Area of square park = Area of rectangular park

{tex} \Rightarrow {/tex} side x side = length x breadth

{tex} \Rightarrow {/tex} 60 x 60 = 90 x breadth

{tex} \Rightarrow {/tex} breadth = {tex}\frac{{60 \times 60}}{{90}}{/tex} = 40 m

Thus, the breadth of the rectangular park is 40 m.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 6. A wire is in the shape of a rectangle. Its length is 40 cm and breadth is 22 cm. If the same wire is rebent in the shape of a square, what will be the measure of each side. Also find which shape encloses more area?

Answer:

According to the question,

Perimeter of square = Perimeter of rectangle

{tex} \Rightarrow {/tex} 4 x side = 2 (length + breadth)

{tex} \Rightarrow {/tex} 4 x side = 2 (40 + 22) {tex} \Rightarrow {/tex} 4 x side = 2 x 62

{tex} \Rightarrow {/tex} side = {tex}\frac{{2 \times 62}}{4}{/tex} = 31 cm

Thus, the side of the square is 31 cm.

Now, Area of rectangle = length x breadth = 40 x 22 = 880 {tex}c{m^2}{/tex}

And Area of square = side x side = 31 x 31 = 961 {tex}c{m^2}{/tex}

Therefore, on comparing, the area of square is greater than that of rectangle.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 7. The perimeter of a rectangle is 130 cm. If the breadth of the rectangle is 30 cm, find its length. Also, find the area of the rectangle.

Answer:

Perimeter of rectangle = 130 cm

{tex} \Rightarrow {/tex} 2 (length + breadth) = 130 cm

{tex} \Rightarrow {/tex} 2 (length + 30) = 130 {tex} \Rightarrow {/tex} length + 30 = {tex}\frac{{130}}{2}{/tex}

{tex} \Rightarrow {/tex} length + 30 = 65 {tex} \Rightarrow {/tex} length = 65 – 30 = 35 cm

Now area of rectangle = length x breadth = 35 x 30 = 1050 {tex}c{m^2}{/tex}

Thus, the area of rectangle is 1050 {tex}c{m^2}{/tex}.


NCERT Solutions for Class 7 Maths Exercise 11.1

Question 8.A door of length 2 m and breadth 1 m is fitted in a wall. The length of the wall is 4.5 m and the breadth is 3.6 m. Find the cost of white washing the wall, if the rate of white washing the wall is Rs. 20 per{tex}{m^2}{/tex}.

Answer:

Area of rectangular door = length x breadth = 2 m x 1 m = 2 {tex}{m^2}{/tex}

Area of wall including door = length x breadth = 4.5 m x 3.6 m = 16.2 {tex}{m^2}{/tex}

Now, Area of wall excluding door

= Area of wall including door – Area of door

= 16.2 – 2 = 14.2{tex}{m^2}{/tex}

Since, The rate of white washing of 1 {tex}{m^2}{/tex}the wall = Rs. 20

Therefore, the rate of white washing of 14.2{tex}{m^2}{/tex} the wall = 20 x 14.2

= Rs. 284

Thus, the cost of white washing the wall excluding the door is Rs. 284.

NCERT Solutions for Class 7 Maths Exercise 11.1

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