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NCERT Solutions for Class 7 Maths Exercise 10.4 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

**NCERT solutions for Maths Practical Geometry ****Download as PDF**

## NCERT Solutions for Class 7 Maths Practical Geometry

**Class –VII Mathematics (Ex. 10.4)**

**Question 1.**Construct {tex}\Delta {/tex}ABC, given {tex}m\angle {/tex}A = {tex}{60^ \circ },{/tex}{tex}m\angle {/tex}B = {tex}{30^ \circ }{/tex} and AB = 5.8 cm.

**Answer:**

**To construct**: {tex}\Delta {/tex}ABC where {tex}m\angle {/tex}A = {tex}{60^ \circ },{/tex}{tex}m\angle {/tex}B = {tex}{30^ \circ }{/tex} and AB = 5.8 cm.

**Steps of construction**:

(a) Draw a line segment AB = 5.8 cm.

(b) At point A, draw an angle {tex}\angle {/tex}YAB = {tex}{60^ \circ }{/tex} with the help of compass.

(c) At point B, draw {tex}\angle {/tex}XBA = {tex}{30^ \circ }{/tex} with the help of compass.

(d) AY and BX intersect at the point C.

It is the required triangle ABC.

NCERT Solutions for Class 7 Maths Exercise 10.4

**Question 2.**Construct {tex}\Delta {/tex}PQR if PQ = 5 cm, {tex}m\angle {/tex}PQR = {tex}105^\circ {/tex} and {tex}m\angle {/tex}QRP = {tex}40^\circ .{/tex}

**Answer:**

**Given**: {tex}m\angle {/tex}PQR = {tex}105^\circ {/tex} and {tex}m\angle {/tex}QRP = {tex}40^\circ {/tex}

We know that sum of angles of a triangle is {tex}180^\circ .{/tex}

{tex}\therefore {/tex} {tex}m\angle {/tex}PQR + {tex}m\angle {/tex}QRP + {tex}m\angle {/tex}QPR = {tex}180^\circ {/tex}

{tex} \Rightarrow {/tex} {tex}105^\circ + 40^\circ + m\angle {/tex}QPR = {tex}180^\circ {/tex}

{tex} \Rightarrow {/tex} {tex}145^\circ {/tex} + {tex}m\angle {/tex}QPR = {tex}180^\circ {/tex}

{tex} \Rightarrow {/tex} {tex}m\angle {/tex}QPR = {tex}180^\circ {/tex} – {tex}145^\circ {/tex}

{tex} \Rightarrow {/tex} {tex}m\angle {/tex}QPR = {tex}35^\circ {/tex}

NCERT Solutions for Class 7 Maths Exercise 10.4

**Question 3.**Examine whether you can construct {tex}\Delta {/tex}DEF such that EF = 7.2 cm, {tex}m\angle {/tex}E = {tex}110^\circ {/tex} and {tex}m\angle {/tex}F = {tex}80^\circ .{/tex} Justify your answer.

**Answer:**

**To construct**: {tex}\Delta {/tex}PQR where {tex}m\angle {/tex}P = {tex}35^\circ {/tex}, {tex}m\angle {/tex}Q = {tex}105^\circ {/tex} and PQ = 5 cm.

**Steps of construction**:

(a) Draw a line segment PQ = 5 cm.

(b) At point P, draw {tex}\angle {/tex}XPQ = {tex}35^\circ {/tex} with the help of protractor.

(c) At point Q, draw {tex}\angle {/tex}YQP = {tex}105^\circ {/tex} with the help of protractor.

(d) XP and YQ intersect at point R.

It is the required triangle PQR.

## NCERT Solutions for Class 7 Maths Exercise 10.4

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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