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# NCERT Solutions class 12 Maths Exercise 13.5

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## NCERT Solutions class 12 Maths Probability

1.  A die is thrown 6 times. If ‘getting an odd number’ is a success, what is the probability of:

(i)  5 successes?

(ii)  at least 5 successes?

(iii)  at most 5 successes?

Ans.  S = {1, 2, 3, 4, 5, 6}    = 6

A = {1, 3, 5}       = 3

=  and

= 6 and P (X = ) = C

(i)

P (X = 5) = C (6, 5)  =

(ii)

P (at least 5 success) = P (X = 5) + P (X = 6) =

(iii)  P (at most 5 success) = 1 – P (X = 6) =

2.  A pair of dice is thrown 4 times. If getting a doublet is considered a success, find the probability of two successes.

Ans.   = 36, A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)}    = 6

=  and

= 4 and  = 2

P (X = ) = C

P (X = 2) = C (4, 2)  =

3.  There are 5% defective items in a large bulk of items. What is the probability that a sample of 10 items will include not more than one defective item?

Ans.   and

= 10,  = 0, 1

P (not more than one defective items) = P (X = 0) + P (X = 1)

= C (10, 0)  + C (10, 1)

=

#### 4.  Five cards are drawn successively with replacement from a well-shuffled deck of 52 cards. What is the probability that:

(i)  all the five cards are spade?

(ii)  only 3 cards are spades?

Ans.  S = 52 cards    = 52 and A = {13 spades}     13

and

(i)   = 5,  = 5

P (X = ) =

P (X = 5) =

(ii)   = 5,  = 0

P (X = 3) =

(iii)   = 5,  = 0

P (X = 0) =

#### 5.  The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05. Find the probability that out of 5 such bulbs.

Ans.   = 0.05 and  = 1 – 0.05 = 0.96

= 5 and P (X = ) = C

(i)   = 0

P (X = 0) = C (5, 0),

(ii)  Not more than one success

P (not more than one success) = P (X = 0) + P (X = 1)

=

=

=

=

(iii)  P (more than one success) = 1 – [P (X = 0) + P (X = 1)]

=

(iv)  P (at least one success) = 1 – P (X = 0)

=

#### 6.  A bag consists of 10 balls each marked with one of the digits 0 to 9. If four balls are drawn successively with replacement from the bag, what is the probability that none is marked with the digit 0?

Ans.  S = {0, 1, 2 3, 4, 5, 6, 7, 8, 9}    = 10

Let A represents that the ball is marked with the digit 0.

A = {0}     = 1

and

and P (X = ) =

Now P (one is marked with its digit 0) =

#### 7.  In an examination, 20 questions of true-false are asked. Suppose a student tosses a fair coin to determine his answer to each question. If the coin falls heads, he answers ‘true’, if it falls tails, he answers ‘false’. Find the probability that he answers at least 12 questions correctly.

Ans.  S = {H, T}    = 2

A = {H}     = 1

and

and  P (X = ) =

P (at least 12 success) = P (X = 12) + P (X = 13) + ……… P (X = 20)

=

=

#### 8.  Suppose X has a binomial distribution B. Show that X = 3 is the most likely outcome.

Ans.  B

= 0, 1, 2, 3, 4, 5, 6

P (X = ) = C

Since

Therefore, P (X = ) = C

Now,  out of C (6, 0), C (6, 1), C (6, 2), C (6, 3), C (6, 4), C (6, 5), C (6, 6), here C (6, 3) is maximum.

P (X = 3) = C (6, 3)  =  =

Therefore, P (X = 3) is maximum, i.e.,

#### 9.  On a multiple choice examination with three possible answers for each of the five questions, what is the probability that a candidate would get four or more correct answers just by guessing?

Ans.   and

and P (X = ) =

P (Four or more success) = P (X = 4) + P (X = 5)

= =  =

#### 10.  A person buys a lottery ticket in 50 lotteries, in each of which his chance of winning a prize is   What is the probability that he will win a prize:

(a) at least once

(b) exactly once

(c) at least twice?

Ans.   and

(a)  P (at least one prize) = 1 – P (X = 0) =

(b)  P (exactly one prize) = P (X = 1) =

(c)  P (at least twice) = 1 – [P (X = 0) + P (X = 1)] =

=

#### 11.  Find the probability of getting 5 exactly twice in 7 throws of a die.

Ans.  S = {1, 2, 3, 4, 5, 6}    = 6

A = {5}       = 1

and

and P (X = ) =

P (X = 2) =

#### 12.  Find the probability of throwing at most 2 sixes in 6 throws of a single die.

Ans.  S = {1, 2, 3, 4, 5, 6}    = 6

Let A represents the favourable event i.e., 6

A = {6}     = 1

and

and P (X = ) =

P (X = 0) =

P (X = 1) =

P (X = 2) =

P (at most 2 success) = P (X = 0) + P (X = 1) + P (X = 2)

=  +  +

=   =

Ans.   and

and P (X = ) =

P (X = 9) =  =

#### In each of the following, choose the correct answer:

14.  Binomial distribution is given this name because:

(A)  This distribution was evolved by James binomial.

(B)  Each trial has only two outcomes. Namely success and failure.

(C)  Its probability function is obtained by general of binomial expansion.

(D)  It is obtained by combining two distributions.

Ans.   and

P (X = 0) =

Therefore, option (C) is correct.

#### 15.  In a box containing 100 bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is:

(A)

(B)

(C)

(D)

Ans.   and

P (X = 4) =

Therefore, option (A) is correct.

## NCERT Solutions class 12 Maths Exercise 13.5

NCERT Solutions Class 12 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 12 Maths includes text book solutions from both part 1 and part 2. NCERT Solutions for CBSE Class 12 Maths have total 13 chapters. 12 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 12 solutions PDF and Maths ncert class 12 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide

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### 2 thoughts on “NCERT Solutions class 12 Maths Exercise 13.5”

1. Q 15 is wrong. The answer is C.

2. thank you sir for this biggest help