## myCBSEguide App

CBSE, NCERT, JEE Main, NEET-UG, NDA, Exam Papers, Question Bank, NCERT Solutions, Exemplars, Revision Notes, Free Videos, MCQ Tests & more.

Install Now

NCERT Solutions for Class 10 Maths Exercise 14.3 Class 10 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 10 Maths chapter wise NCERT solution for Maths Book for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

**NCERT solutions for Maths ****Statistics ****Download as PDF**

## NCERT Solutions for Class 10 Maths Statistics

**Exercise 14.3**

**1. The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.**

**Ans. For Median**:

Here, , then , which lies in interval 125 – 145.

Median class = 125 – 145

So, and

Now, Median =

=

= = 125 + 12 = 137

**For Mean**:

From given data, Assume mean = 135, Width of the class = 20

=

Using formula, Mean = 135 + 20 (0.102)

= 135 + 2.04 = 137.04

**For Mode**:

In the given data, maximum frequency is 20 and it corresponds to the class interval 125 – 145.

Modal class = 125 – 145

And and

Mode =

=

=

=

= 125 + 10.76923

= 125 + 10.77

= 135.77

Hence, median, mean and mode of given data is 137 units, 137.04 units and 135.77 units.

NCERT Solutions for Class 10 Maths Exercise 14.3

**2. If the median of the distribution given below is 28.5, then find the values of and **

**Ans. **

Here, , then , also, median of the distribution is 28.5, which lies in interval 20 – 30.

Median class = 20 – 30

So, and

……….(i)

Now, Median =

Putting the value of in eq. (i), we get,

Hence the value of and is 8 and 7 respectively.

NCERT Solutions for Class 10 Maths Exercise 14.3

**3. A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are only given to persons having age 18 years onwards but less than 60 years.**

**Ans. **

Here, , then , which lies in interval 35 – 40.

Median class = 35 – 40

So, and

Now, Median =

=

=

=

= 35 + 0.7575

= 35 + 0.76 (approx.)

= 35.76

Hence median age of given data is 35.76 years.

NCERT Solutions for Class 10 Maths Exercise 14.3

**4. The lengths of 40 leaves of a plant are measured correct to the nearest millimeter and data obtained is represented in the following table. Find the median length of the leaves.**

**Ans. **Since the frequency distribution is not continuous, so firstly we shall make it continuous.

Here, , then , which lies in interval 144.5 – 153.5.

Median class = 144.5 – 153.5

So, and

Now, Median =

=

=

= 144.5 + 2.25

= 146.75

Hence median length of the leaves is 146.75 mm.

NCERT Solutions for Class 10 Maths Exercise 14.3

**5. The following table gives the distribution of the life time of 400 neon lamps. Find the median life time of the lamps.**

**Ans. **

Here, , then , which lies in interval 3000 – 3500.

Median class = 3000 – 3500

So, and

Now, Median =

=

=

= 3000 + 406.9767441

= 3000 + 406.98 (approx.)

= 3406.98

Hence median life time of a lamp is 3406.98 hours.

NCERT Solutions for Class 10 Maths Exercise 14.3

**6. 100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:**

**Determine the median number of letters in the surnames. Find the mean number of letters in the surnames. Also find the modal size of the surnames.**

**Ans. For Median**:

Here, , then , which lies in interval 7 – 10.

Median class = 7 – 10

So, and

Now, Median =

=

=

= 7 + 1.05

= 8.05

**For Mean**:

From given data, Assume mean = 8.5, Width of the class = 3

=

Using formula, Mean = 8.5 + 3 (– 0.06) = 8.5 – 0.18 = 8.32

**For Mode**:

In the given data, maximum frequency is 40 and it corresponds to the class interval 7 – 10.

Modal class = 7 – 10

And and

Mode =

=

=

=

= 7 + 0.88 (approx.)

= 7.88

Hence, median, mean and mode of given data is 8.05 letters, 8.32 letters and 7.88 letters respectively.

NCERT Solutions for Class 10 Maths Exercise 14.3

**7. The distribution below gives the weights of 30 students of a class. Find the median weight of the students.**

**Ans. **

Here, , then , which lies in interval 55 – 60.

Median class = 55 – 60

So, and

Now, Median =

=

=

= 55 + 1.66666

= 5 + 1.67 (approx.)

= 56.67

Hence median weight of the students are 56.67 kg.

## NCERT Solutions for Class 10 Maths Exercise 14.3

NCERT Solutions Class 10 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

## CBSE app for Class 10

To download NCERT Solutions for Class 10 Maths, Computer Science, Home Science,Hindi ,English, Social Science do check myCBSEguide app or website. myCBSEguide provides sample papers with solution, test papers for chapter-wise practice, NCERT solutions, NCERT Exemplar solutions, quick revision notes for ready reference, CBSE guess papers and CBSE important question papers. Sample Paper all are made available through **the best app for CBSE **

Tq a lot

Gud for helping others

U r doing a good job

good job

Thanks. It help me so much

Mostly in exam time

Thanks… It really helped me

Really helpful ?

Thank you very

Much for all body help what u don’t explain clearly

Thanks ?? for your website ?

Thanks for helping me to do my homework early

This is my favourite website very helpful for me and all other students

Really helped me .it clear my doubt

Was really helpful

Best app for exam preparation