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The equilibirum constant kp for the reaction …

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The equilibirum constant kp for the reaction H2+I2= HI

is 130 at 510k.calculate kc for the reaction

    • Posted by Ramesh Makadiya 7 years, 3 months ago

    CBSE > Class 11 > Chemistry
    • 1 answers

    Yakshith K 7 years, 3 months ago

    Given

    Kp=130.

    T=510K

    We know that,  Kp=Kc(RT)n 

    balance equation    H2+I2→2HI    

    Therfore,

    Kc=Kp/(RT)n

    =130(8.314*510)0

    Kc=130

    0Thank You

    ANSWER
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