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An open vessel contains 200 mg …

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An open vessel contains 200 mg of air at 17 Celsius  wht weight percentage of air would be expelled if vessel is geared to 117 Celsius 

  • 1 answers

Govind Singh 6 years, 2 months ago

Approach: We have PV=nRT

n can be rewritten as {tex}\frac{m}{M}{/tex}, where m is the weight of the gas while M is the molecular mass of the gas. Thus:

{tex}PV = \frac{m}{M}RT{/tex}

The only two variables changing are m and T

Substituting values, we have:

{tex}PV = \frac{{0.200}}{M}R\left( {290} \right){/tex}

{tex}PV = \frac{m}{M}R\left( {390} \right){/tex}

Where m is the mass of the gas remaining in the vessel. Dividing the two equations:

{tex}\frac{{390}}{{290}} = \frac{{0.200}}{m}{/tex}

m = 149mg

From here, the percentage can be calculated easily. Is there any problem with this approach? Or is there any simpler approach that can be used. I am actually supposed to solve this question using Gay-Lussac's Law.

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