Tan(xo+45o)
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Sahdev Sharma 6 years, 8 months ago
Using tan (a+b) = {tex}tan \ a +tan \ b\over 1- tan\ a.tan\ b{/tex}
we get
{tex}tan (x+45) = { tan x + tan 45\over 1-tanx\times tan 45}{/tex}
= {tex}{tan\ x + 1 \over 1-tan\ x}\\ [ as \ tan \ 45 = 1]{/tex}
= {tex}1+tan \ x\over 1- tan \ x{/tex}
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