If sinA +sin (2)^A=1 Prove that …
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Posted by Aditya Narayan Panda 6 years, 9 months ago
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Poulami Dasgupta 6 years, 9 months ago
{tex}SinA + Sin\ ^ 2A = 1{/tex}
{tex}SinA = 1-Sin\ ^ 2A{/tex}
{tex}SinA = Cos\ ^ 2 A{/tex}( Using identity)
Squaring both sides,
{tex}(SinA)\ ^ 2 = ( Cos\ ^2 A )\ ^ 2{/tex}
{tex}Sin\ ^ 2 A=Cos\ ^ 4 A{/tex}
{tex}1- Cos\ ^ 2 A= Cos \ ^ 4 A{/tex}( Using identity)
{tex}1 = Cos \ ^ 2A + Cos \ ^ 4 A{/tex}
{tex}Cos \ ^ 2A + Cos \ ^ 4 A = 1{/tex}
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