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Cos-1 (cos (680)

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Cos^-1(cos (680)

Posted by Deepanshu Saini 6 years, 9 months ago

CBSE > Class 12 > Mathematics

2 answers

Sahdev Sharma 6 years, 9 months ago

{tex}cos^{-1}[cos(680^°)]{/tex}

{tex}= cos^{-1}[cos(4\pi -40^°)]{/tex}

{tex}= cos^{-1}[cos(40^°)]{/tex}

={tex}= 40^°{/tex}

1Thank You

Payal Singh 6 years, 9 months ago

{tex}cos^{-1}[cos(680^°)]{/tex}

= {tex}cos^{-1}[cos(4\pi -40^°)]{/tex}

{tex}= cos^{-1}[cos(40^°)]{/tex}

= {tex}40^°{/tex}

0Thank You

ANSWER

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