The side of a rectangles are …
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Posted by Shahista Anjum 6 years, 9 months ago
- 3 answers
Payal Singh 6 years, 9 months ago
Side of rectangle = 22 cm, 120 cm
Diagonal of triangle = {tex}\sqrt {(22)^2+(120)^2}{/tex}
= {tex}\sqrt {484+14400}{/tex}
= {tex}\sqrt {14884}{/tex}= 122 cm
Rashmi Bajpayee 6 years, 9 months ago
Let ABCD be a rectangle.
Given: AB = 22 cm and BC = 120 cm
To find: Diagonal AC.
Using Pythagoras theorem,
AC2 = AB2 + BC2
= (22)2 + (120)2
= 484 + 14400
= 14884
AC = 122 cm
The length of given rectangle is 122 cm.
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Sahdev Sharma 6 years, 9 months ago
Given: sides of rectangle = 22 cm 120 cm To find:
Diagonal of rectangle =
Using Pythagoras theorem,
Diagonal = {tex}\sqrt {(22)^2+(120)^2}{/tex}
= {tex}\sqrt {14884}{/tex}
= 122 cm.
So length of diagonal is 122 cm.
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