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Find dy/dx:: sin xy + cos …

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Find dy/dx::

sin xy + cos xy =1

Posted by Rohit Kumar 6 years, 9 months ago

CBSE > Class 12 > Mathematics

1 answers

Payal Singh 6 years, 9 months ago

sin xy + cos xy = 1

Differentiate with respect to x, we get

cos xy ( y + x{tex}dy\over dx{/tex}) - sin xy (y+x{tex}dy\over dx{/tex}) = 0

=> cos xy ( y + x{tex}dy\over dx{/tex}) = sin xy (y+x{tex}dy\over dx{/tex})

=> tan xy = 1

Differentiate with respect to x,

=> sec² xy (y+ x{tex}dy\over dx{/tex}) = 0

=> y+ x {tex}dy\over dx{/tex}= 0

=> {tex}dy\over dx{/tex} = {tex}-y\over x{/tex}

0Thank You

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CBSE > Class 12 > Mathematics

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CBSE > Class 12 > Mathematics