Electric Field due to Multiple Point Charges:
Now consider the more complex case, when the electric field is produced by two point charges <i>Q1</i> and <i>Q2, </i>located at points defined by vectors 
and 
respectively, where we want to find the net electric field 
. We can readily get the electric fields 
and 
produced by charges <i>Q1 </i>and <i>Q2</i>taken separately by using coulomb's law:
Electric field due to multiple point
First, Find the force of <a href="http://4.bp.blogspot.com/_iw6iAVe9Rhs/StiBbz0-VRI/AAAAAAAAACk/jmCWH7UNyyE/s1600-h/image044.gif" onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}">
</a>
Second, Find the force of <a href="http://4.bp.blogspot.com/_iw6iAVe9Rhs/StiCE66yqNI/AAAAAAAAACs/zWw2I_xkGCY/s1600-h/image051.gif" onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}">
</a>
The net electric field is equal to the vector sum of individual fields
Putting the above formulas gives
The vector 
can be readily determined graphically by parallelogram rule, which states that the vector is defined by the diagonal of the parallelogram with sides 
and 
.
Akshat Shrivastava 6 years, 9 months ago
Electric Field due to Multiple Point Charges:
Now consider the more complex case, when the electric field is produced by two point charges <i>Q1</i> and <i>Q2, </i>located at points defined by vectors
and 
respectively, where we want to find the net electric field 
. We can readily get the electric fields 
and 
produced by charges <i>Q1 </i>and <i>Q2</i>taken separately by using coulomb's law:
Electric field due to multiple point
First, Find the force of <a href="http://4.bp.blogspot.com/_iw6iAVe9Rhs/StiBbz0-VRI/AAAAAAAAACk/jmCWH7UNyyE/s1600-h/image044.gif" onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}">
</a>
Second, Find the force of <a href="http://4.bp.blogspot.com/_iw6iAVe9Rhs/StiCE66yqNI/AAAAAAAAACs/zWw2I_xkGCY/s1600-h/image051.gif" onblur="try {parent.deselectBloggerImageGracefully();} catch(e) {}">
</a>
The net electric field is equal to the vector sum of individual fields
Putting the above formulas gives
The vector
can be readily determined graphically by parallelogram rule, which states that the vector 
is defined by the diagonal of the parallelogram with sides 
and 
.
0Thank You