a football is picked vertically upwards …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
a football is picked vertically upwards from the ground and a student gazing out for windows sees it moving upwards pass her at 5m/s the window is 15m about the ground
<hr />A=how high does the football above the ground
<hr />B=how much time does it take to go from the ground to its highest point
Posted by Uday Bhardwaj 6 years, 10 months ago
- 1 answers
Related Questions
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Payal Singh 6 years, 10 months ago
let the initial velocity of football is u m/sec motion from ground to window
v=5m/sec
h=15m
v2 -u2 =2gh
=> 25 -u2 = 2*(-10)*15
=> u2=325
=u = {tex}\sqrt {325} = 5\sqrt{13}{/tex}m/s
A)motion from window to maximum height
v2-u2 = 2as
Here v is final velocity of ball = 0m/s
u is initial velocity of ball = 5m/s
a is acceleration due to gravity = -10 as it is going upward
s is distance traveled by it = ?
So,
=> 0 - 25 = 2*(-10)*h
=> -25 = -20h
=> h = {tex}{-25\over -20}= {5\over 4}{/tex}
Total height = 15 + {tex}{5\over 4} = {65\over 4}{/tex}m
B)motion from ground to max height
u= {tex}5\sqrt{13}{/tex}
v=0
v=u-gt
t={tex}{5\sqrt {13}\over 10}= {\sqrt {13}\over 2} sec{/tex}
1Thank You