a man wants to donate rectangular …
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a man wants to donate rectangular plot of land for a school in his village. when he was asked to give the dimension of the plot, he told that if its length is decreased by 50m and breadth is increased by 50m then its area will remain same but if its length is decreased by 10m and breadth is decreased by 20m, then its area will decrease by 5300m^2. using matrices, find the dimension of the plot. also give reason why he wants to donate the plot for a school.
Posted by Tahmid Hossain 6 years, 10 months ago
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Naveen Sharma 6 years, 10 months ago
Ans. Let the length of Plot = x m
Breadth of plot = y m
Area of Plot = xy
According to First condition,
(x-50) (y+50) = xy
=> xy + 50x -50y - 2500 = xy
=> 50x - 50y = 2500
=> x- y = 50 ........ (1)
According to 2nd condition,
(x-10) (y-20) = xy - 5300
=> xy - 20x - 10y + 200 = xy - 5300
=> -20x - 10y = -5500
=> 20x + 10y = 5500
=> 2x + y = 550 ........(2)
We can represent these two equation using Matrix
A = {tex}\begin{bmatrix} 1 & -1 \\ 2& 1 \end{bmatrix}{/tex}, |A| = 1+2 = 3
X = {tex}\begin{bmatrix} x \\ y \end{bmatrix}{/tex}
B = {tex}\begin{bmatrix} 50 \\ 550 \end{bmatrix}{/tex}
Such that AX = B
X = A-1B
A-1 = {tex}Adjoint \space of \space A\over Determinant \space of \space A {/tex}
=> X= {tex}{1\over 3} \begin{bmatrix} 1 & 1 \\ -2& 1 \end{bmatrix}\begin{bmatrix} 50 \\ 550 \end{bmatrix}{/tex}
=> X = {tex}{1\over 3}\begin{bmatrix} 600 \\ 450 \end{bmatrix}{/tex}
=>X = {tex}\begin{bmatrix} 200 \\ 150 \end{bmatrix}{/tex}
x = 200
y = 150
So Length of Plot = 200 m
Breadth of Plot = 150 m
He wants to donate land for school because he know the worth of being educated.
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