A wire's diameter is doubled. What …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Pranzal Kumar Sinha 6 years, 10 months ago
- 1 answers
Related Questions
Posted by Sss Sss 2 days, 17 hours ago
- 1 answers
Posted by Rachit Aglawe 2 days, 14 hours ago
- 0 answers
Posted by Mukesh Kumar Mukesh Kumar 1 day, 1 hour ago
- 1 answers
Posted by Mannat Gill 1 day ago
- 0 answers
Posted by Anuj Gupta 1 day, 17 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Naveen Sharma 6 years, 10 months ago
Ans.
We know that
Resistance R = {tex}\rho {L\over A}{/tex}
Where {tex}\rho{/tex} is resistivity of material
L is length of wire
A is area of Cross-section of wire
Area A = {tex}\pi r^2{/tex}
If we double the Diameter it means radius is also doubled
So now Area = {tex}\pi (2r)^2= 4\pi r^2{/tex} = 4A
So New Resistance R' = {tex}\rho {L\over 4A} = {R\over 4}{/tex}
Means new resistance will be {tex}({1\over 4})^{th}{/tex} of old resistance .
2Thank You