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Differtiate w.r to x Sin2(2x+1)

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Differtiate w.r to x Sin^2_(2x+1)

Posted by Ajhar Sultan 6 years, 11 months ago

CBSE > Class 12 > Mathematics

1 answers

Payal Singh 6 years, 11 months ago

Ans. {tex}{d\over dx}(sin^2(2x+1)){/tex}

Using chain rule, we get

={tex}cos^2(2x+1).{d\over dx}(2x+1){/tex}

{tex}= cos^2(2x+1).2{/tex}

{tex}=2. cos^2(2x+1){/tex}

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