The perimeter of a rectangular field …
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Naveen Sharma 6 years, 11 months ago
Ans. Perimeter of Field = 84 meter
Let Length of Field = x meter
Perimeter = {tex}2(x+breadth\space of \space field ){/tex}
=> {tex}84 = 2(x+breadth\space of \space field ){/tex}
{tex}=> 42 = x+breadth\space of \space field {/tex}
{tex}=> breadth\space of \space field = (42 - x ) meter{/tex}
Old Area = {tex}x\times (42-x) = 42x - x^2{/tex}
According to Ques,
New breadth = 42 - x + 2 = (44 - x) meter
New length = (x - 4 ) meter
New Area = {tex}(44 - x) (x-4) = 44x - 176-x^2+4x {/tex}
So, New Area = Old Area - 32
=> {tex}44x - 176 -x^2 +4x = 42x-x^2 -32{/tex}
=> {tex}44x +4x - 42x -x^2 + x^2 = -32 + 176{/tex}
=> {tex}6x = 144{/tex}
=> x = 24
So, Length of Field = 24 meter
Breadth of Field = 42- 24 = 18 meter
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