A force of 10 Newton acts on …
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Payal Singh 6 years, 11 months ago
Solution:
Let initial velocity u = 0
let final velocity v = ?
foce (f) = 10N
Mass of body m = 2Kg
Time t = 3s
Acceleration a = {tex}{v-u\over t } = {v-0\over 3} = {v\over 3}{/tex}
As we know
f = ma
=> {tex}10 = 2\times {v\over 3}{/tex}
=> v = 15m/s
0Thank You