A train first travels for 30 …
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Payal Singh 6 years, 11 months ago
Solution : D1 = Distance traveled in 30 minute with velocity 30km/h = 15km
D2 = Distance traveled in 40 minute with velocity 40km/h = {tex}80\over 3{/tex}km
Total distance = {tex}15 + {80\over 3} = {125\over 3}{/tex}Km
Total time taken = 30+40 = 70m = {tex}{70\over 60} = {7\over 6}h{/tex}
Average velocity = {tex}{Total\space distance \over time \space taken }= {125 \times 6\over 3\times 7}{/tex}
=,{tex}{250\over 7 } = 35{5\over 7}Km/h{/tex}
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