k2x3-kx2+3k-k find the value of k …
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Rashmi Bajpayee 6 years, 11 months ago
k2x3 - kx2 + 3k - k = 0
=> k2(3)3 - k(3)2 + 3k - k = 0
=> 27k2 - 9k + 3k - k = 0
=> 27k2 - 7k = 0
=> k(27k - 7) = 0
=> k = 0 or 27k - 7 = 0
=> k = 0 or k = 7/27
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