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Sin-1(tan5π/4)

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Sin^-1(tan5π/4)

Posted by Mohana Paul 7 years ago

CBSE > Class 12 > Mathematics

1 answers

Lokendra Soni 7 years ago

{tex}\tan{5\pi\over4}{/tex} = {tex}\tan({\pi + {\pi\over4}}){/tex} = {tex}\tan{\pi\over4}{/tex}

{tex}\sin^{-1}({\tan{\pi\over4}}){/tex} = {tex}\sin^{-1}({1}){/tex} = {tex}\pi\over2{/tex}

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Posted by Arpit Sahu 3 weeks, 6 days ago

CBSE > Class 12 > Mathematics

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CBSE > Class 12 > Mathematics

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