At what rate % per annum …
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Posted by Rathi Kajal 7 years, 1 month ago
- 1 answers
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Naveen Sharma 7 years, 1 month ago
Ans. Amount (A)= 86400
Time(n) = 3 years
Principal (P)= 50000
Let rate (r) = r%
Then We Know,
{tex}A = P \times ({1 +{r\over 100}})^n{/tex}
{tex}=> 86400 = 50000\times ({1+{r\over 100}})^3{/tex}
{tex}=> {86400\over 50000} = ({1+{r\over 100}})^3{/tex}
{tex}=> {216\over 125} = ({1+{r\over 100}})^3{/tex}
{tex}=> ({6\over 5})^3= ({1+{r\over 100}})^3{/tex}
On comparing, We get
{tex}=> ({6\over 5})= ({1+{r\over 100}}){/tex}
{tex}=> {6\over 5} - 1= {r\over 100}{/tex}
{tex}=> {1\over 5} = {r\over 100} => r = 20\%{/tex}
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