Find an ap whose first term …
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Shweta Gulati 7 years ago
a=1
S4= {tex}{1\over 3}{/tex}[S8-S4]
4\2 [ 2+3d] = 1\3 [2+7d-2-3d]
2 (2+3d) = 1/3 (4d)
6(2+3d) = 4d
12 +18d = 4d
12 = -14d
-6/7 =d
So, A.P. becomes 1,1/7,-5/7....
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