P and Q are centres of …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Shivam Nagar 2 days, 18 hours ago
- 0 answers
Posted by M Thirugnanam 2 days, 7 hours ago
- 0 answers
Posted by Aayush Yadav 1 day, 12 hours ago
- 0 answers
Posted by Lohan Lima 2 days, 11 hours ago
- 2 answers
Posted by Bhavya Bansal 1 day, 15 hours ago
- 1 answers
Posted by Aryan Agrawal 1 day, 12 hours ago
- 2 answers
Posted by Garv . 2 days, 1 hour ago
- 2 answers
Posted by Sakshi Bhalshankar 17 hours ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Naveen Sharma 7 years, 1 month ago
Ans. If two circles touch each other externally, then sum of their radii is equal to the distance between their centres.
RP = x+9
RQ= x+2
PQ = 17
Given, angle PRQ= 90, So In Triangle PRQ => RP2 + RQ2 = PQ2 …(using Pythagoras)
=> (x+9)2 + (x+2)2= (17)2
=> x2 + 18x + 81 + x2 + 4x + 4 = 289
=> 2x2 + 22x -204 =0
=> x2 + 11x -102 = 0
On Solving We get
x = -17 and 6
So radius of circle is 6cm.
1Thank You