A balloon start rising from the …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Supanpreet Kaur 4 days, 17 hours ago
- 0 answers
Posted by Harsumit Kaur Brar 4 days, 12 hours ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Naveen Sharma 7 years, 1 month ago
Ans.
Initial Velocity of balloon u = 0
Acceleration a = 1.25m/s2
Time t = 10s
Final velocity v = {tex}u + at = 0 + 1.25\times 10 = 12.5m/s{/tex}
Distance traveled in 10 s,
{tex}=> S = ut +{1\over 2}at^2{/tex}
{tex}=> S = 0\times 10 +{1\over 2}\times1.25\times 100{/tex}
=> S = 62.50m
Now, balloon will drop down with initial velocity, u'= v=12.5 m/s with acceleration, a'= -g =-10 m/s2 and cover distance -62.5 m(as it is moving downwards).
Using,
{tex}=> S = ut +{1\over 2}at^2{/tex}
{tex}=> - 62.5 = 12.5t +{1\over 2}(-10)t^2{/tex}
{tex}=> - 62.5 = 12.5t -5t^2{/tex}
{tex}=> 5t^2 - 12.5t - 62.5 = 0{/tex}
{tex}=> t^2 - 2.5t + 12.5 = 0{/tex}
On Solving, We get
t = 5.0 or -2.5
Time can not be negative so the required answer is 5.0 seconds. the stone will reach the ground in 5.0 seconds.
1Thank You