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A balloon start rising from the …

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A balloon start rising from the ground  with an acceleration of 1.25m/s2 after 10s a stone is released from the balloon determine 

Maximum height of stone from ground 

Time taken by stone to reach ground

  • 1 answers

Naveen Sharma 7 years, 1 month ago

Ans. 

Initial Velocity of balloon u = 0 

Acceleration a = 1.25m/s2

Time t = 10s

Final velocity v = {tex}u + at = 0 + 1.25\times 10 = 12.5m/s{/tex}

Distance traveled in 10 s,

{tex}=> S = ut +{1\over 2}at^2{/tex}

{tex}=> S = 0\times 10 +{1\over 2}\times1.25\times 100{/tex}

=> S = 62.50m 

Now, balloon will drop down with initial velocity, u'= v=12.5 m/s with acceleration, a'= -g =-10 m/s2 and cover distance -62.5 m(as it is moving downwards).

Using,

{tex}=> S = ut +{1\over 2}at^2{/tex}

{tex}=> - 62.5 = 12.5t +{1\over 2}(-10)t^2{/tex}

{tex}=> - 62.5 = 12.5t -5t^2{/tex}

{tex}=> 5t^2 - 12.5t - 62.5 = 0{/tex}

{tex}=> t^2 - 2.5t + 12.5 = 0{/tex}

On Solving, We get

t = 5.0 or -2.5

 

Time can not be negative so the required answer is 5.0 seconds. the stone will reach the ground in 5.0 seconds.

 

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