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Show that T1 , T2 , T3 , .... …

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Show that T, T, T, .... T.... form an AP where Tis defined as: T= 9 - 5n. Also find the sum of the first 15 terms.

  • 1 answers

Rashmi Bajpayee 7 years, 1 month ago

Given:     Tn = 9 - 5n

T1 = a = 9 - 5 x 1 = 9 - 5 = 4

T2 = 9 - 5 x 2 = 9 - 10 = -1

Therefore, d = -1 - 4 = -5

S15 = n/2[2a + (n - 1)d]

      = 15/2[2 x 4 + (15 - 1) x (-5)]

      = 15/2[8 - 70]

      = 15/2 x [-62]

      = -465

Therefore, the sum of 15 terms of given AP is -465.

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