if the distance of the chord …
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Shweta Gulati 7 years, 1 month ago
Let AB be the chord of length 4 cm. C be its mid-point
. O be the center of the circle. Join OA [OA becomes the radius]
Given OC = 5 cm
AC = BC = 4/2 = 2 cm [The perpendicular drawn from the center to a chord bisect the chord]
OAC is a right angled triangle
OA2=OC2+AC2[byPythagorasTheorem]
OA2= 52+22
= 25+4
=29
OA= \(\sqrt29\)cm
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