PB is a tangent to the …
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Naveen Sharma 7 years, 2 months ago
Ans. In Right Angle Triangle OMB,
OM = 5 cm [Given]
MB = AB/2 = 24/2 = 12 cm [perpendicular from the center to chord divided it into two equal part]
OB2 = OM2 + MB2 [By Pythagoras Theorem]
=> OB2 = 25 + 144 = 169
=> OB = 13 cm
Now in Right Angle Triangle OBP
OB = 13 cm [Calculated Above]
PB = 20 cm [Given]
PO2 = OB2 + PB2 [By Pythagoras Theorem]
=> PO2 = 169 + 400
=> PO = \( { \sqrt{569}}\)
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