Solve the equation: 22x+3=65(2x-2)+122.
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Naveen Sharma 7 years, 2 months ago
Ans. Equation is in the Form = 22x+3 = 65 (2x - 2 ) + 122
=> 22x . 23 = 65 ( 2x - 2 ) + 122
=> 8(2x)2 = 65 ( 2x - 2) + 122
Put 2x = y , We get
=> 8y2 = 65(y-2) + 122
=> 8y2 = 65y - 130 + 122
=> 8y2 - 65y + 8 = 0
=> 8y2 - 64y - y + 8 = 0
=> 8y ( y - 8) - 1(y-8) = 0
=> (8y-1) ( y - 8) = 0
Either 8y -1 = 0 or y - 8 = 0
So, y = 1/8 or 8
=> 2x = 1/8 or 2x = 8
=> 2x = (2)-3 or 2x = (2)3
On comparing, We get
x = -3, 3
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