A ladder of length 6m makes …
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A ladder of length 6m makes an angle of 45 with the floor while leaning against one wall of a room if the foot of the ladder is fixed on the floor and it is made to lean against the opposite wall of the room it makes an angle 60 with the floor find the distance between these two walls of the room
Posted by Shashant Ahuja 7 years, 2 months ago
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Naveen Sharma 7 years, 2 months ago
Ans. Let AB and CD are two wals of room and Ladder is fixed at O.
In Triangle ABO : cos 60 = BO/6
=> 1/2 = BO/6
cross multiply. We get
BO = 3m
In Triangle CDO : cos 45 = DO/6
=> 1/√2 = DO/6
=> DO = 3√2 m
Distance b/w walls = BO + DO = 3 + 3√2 = 3 + 3(1.41) = 3 + 4.23 = 7.23m
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