If X+Y+Z =98; and the X:Y …
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Posted by Aakash Raj 6 years, 8 months ago
- 2 answers
Payal Singh 6 years, 8 months ago
Given : X+Y+Z =98 .......(1)
and the X:Y =2:3 ,Y:Z= 5:8.
Now, {tex}{X\over Y}={2\over 3}\\ X = {2Y\over 3}{/tex}
Also, {tex}{Y\over Z}={ 5\over 8}\\ Z= {8Y\over 5}{/tex}
Put values of X and Z in (1), we get
{tex}{2Y\over 3}+Y+{8Y\over 5}= 98\\ => {10Y+15Y+24Y\over 15}=98\\ => {49Y\over 15}=98{/tex}
=> Y = 30
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Anurag Singhal 6 years, 8 months ago
0Thank You