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how to prove the sum of …

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how to prove the sum of first terms of ap is 42 10th term to its 30th terms is 1:3 find the first term

  • 1 answers

Naveen Sharma 7 years, 3 months ago

Ans. 

Let first term of AP is a and comman difference is d.

as we know 

an = a + (n-1) dwhere an is nth term

=> a10  = a + (10-1)d

=> a10  = a + 9d

And a30 = a + (30-1)d

=> a30 = a + 29d

According to Question

=> a+9da+29d = 13

=> 3a + 27d = a + 29d 

=> 2a = 2d

=> a = d       ............. (1)

Sum of first 6 terms = 42

We know 

Sn = n2× 2a + (n-1)d

=>S6 = 62 ×2a + (6-1)d

=> 42 = 32a + 5a

=> 42 = 21a

=> a = 2 

First term is 2. Common difference is 2.

=> a13 = 2 + (13-1)2

= > a13 = 2 + 24 

=>  a13 = 26 

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