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Naveen Sharma 7 years, 3 months ago
Ans. Let 2r and x be the lenth and width of the window respectivily.
Then radius of semicircular portion is r.
Given : Perimeter of window = 10cm
=>
=>
Area of window is given by :
=>
=>
=>
=>
=>
Differentiate w.r.t r, we get
To Find critical point, Put
=>
=>
=>
=>
Therefore , by second derivative test, the area is the maximum when
Now length of window =
Width of Window x =
0Thank You