In an experiment, 4.9g of copper …
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Shweta Gulati 7 years, 3 months ago
Case I
Mass of copper= 3.92g
Mass of copper oxide= 4.9g
% of copper in oxide = (Mass of copper/Mass of copper oxide) x 100
= 80%
So, % of oxygen = 100-80= 20%
Case II
Mass of copper= 3.64g
Mass of copper oxide= 4.55g
% of copper in oxide = (Mass of copper/Mass of copper oxide) x 100
= 80%
% of oxygen= 100-80=20%
Thus,copper oxide prepared by any of the given methods contains copper and oxygen in the same proportion by mass.Hence, it proves the law of constant proportions.
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