Find the sum of all 3 …
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Naveen Sharma 7 years, 3 months ago
First 3 Digit Number that leaves remainder 3 when divided by 5 is 103.
and last will be 998
A.P. = 103, 108, 113, ..................., 998
first term a = 103
Common Difference d = 5
nth term = 998
n = ?
as we know
nth term = a + ( n-1)d
998 = 103 + ( n-1)5
895/ 5 = n -1
179 = n -1
n = 180
now find sum of 180 terms of AP
S180 = 180/ 2 ( 103 + 998 )
=> S180 = 90 * 1001
=> S180 = 900090
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