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 A 25 FOOT LADDER IS PLACED …

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 A 25 FOOT LADDER IS PLACED AGAINST A VERTICAL WALL OF A BUILDING.THE FOOT OF THE LADDER IS 17 FEET FROM THE BASE OF THE BUILDING,IF THE TOP OF THE LADDER SLIPS 4 FEET,THEN THE FOOT OF THE LADDER WILL SLIP.......

  • 1 answers

Naveen Sharma 7 years, 3 months ago

I think it is not 17 feet it is 7 feet.

Fiirst we need to find at what height ladder is placed. 

Let BC is ladder and AC is Building with foot at C.

Now as given AB = 25

BC = 7 

Using Pythagorous Theroem 

(AB2) = (BC)2 + (AC)2

=> 625 = 49 + (AC)2

=> (AC)2 = 576

=> AC = 24

It slips down 4 feet it means its top is at 20 feet height

So Now

AC = 20

AB = 25 

then again Using theorem 

(BC)2 = 625 - 400 

(BC)2 = 225

BC = 15 

it mean it slips 8 feet. 

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