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Install NowNCERT Solutions class 12 Maths Exercise 11.2 Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.
Download NCERT solutions for Three Dimensional Geometry as PDF.
NCERT Solutions class 12 Maths Three Dimensional Geometry
.Show that the three lines with direction cosines are mutually perpendicular.
Ans. Given: Direction cosines of three lines are
For first two lines,
= =
Therefore, the first two lines are perpendicular to each other.
For second and third lines,
= =
Therefore, second and third lines are also perpendicular to each other.
For First and third lines,
= =
Therefore, first and third lines are also perpendicular to each other.
Hence, given three lines are mutually perpendicular to each other.
2.Show that the line through the points is perpendicular to the line through the points (0, 3, 2) and (3, 5, 6).
Ans. We know that direction ratios of the line joining the points A and B are
Again, direction ratios of the line joining the points C (0, 3, 2) and D (3, 5, 6) are
(say)
For lines AB and CD, = = 6 + 10 – 16 = 0
Therefore, line AB is perpendicular to line CD.
3.Show that the line through points (4, 7, 8), (2, 3, 4) is parallel to the line through the points
Ans. We know that direction ratios of the line joining the points A (4, 7, 8) and B (2, 3, 4) are
= (say)
Again direction ratios of the line joining the points C and D (1, 2, 5) are
= (say)
For the lines AB and CD,
Therefore, line AB is parallel to line CD.
4.Find the equation of the line which passes through the point (1, 2, 3) and is parallel to the vector
Ans. A point on the required line is A (1, 2, 3) =
Position vector of a point on the required line is
The required line is parallel to the vector
direction ratios of the required line are coefficient of in are
Vector equation of the required line is
Where is a real number.
Cartesian equation of this equation is
5.Find the equation of the line in vector and in Cartesian form that passes through the point with position vector and is in the direction
Ans. Position vector of a point on the required line is =
The required line is in the direction of the vector is
Direction ratios of required line are coefficients of in =
Equation of the required line in vector form is
Where is a real number.
Cartesian equation of this equation is
6.Find the Cartesian equation of the line which passes through the point and parallel to the line given by
Ans. Given: A point on the line is
Equation of the given line in Cartesian form is
Direction ratios of the given line are its denominators 3, 5, 6
Equation of the required line is
=
7.The Cartesian equation of a line is Write its vector form.
Ans. Given: The Cartesian equation of the line is = (say)
General equation for the required line is
Putting the values of in this equation,
=
8.Find the vector and Cartesian equations of the line that passes through the origin and
Ans. = Position vector of a point here O (say) on the line = (0, 0, 0) =
= A vector along the line
= = Position vector of point A – Position vector of point O
=
Vector equation of the line is
NowCartesian equation of the line
Direction ratios of line OA are
And a point on the line is O (0, 0, 0) =
Cartesian equation of the line =
= =
Remark:In the solution of the above question we can also take:
= Position vector of point A = for vector form and point A as = for Cartesian form.
Then the equation of the line in vector form is
And equation of line in Cartesian form is
9.Find vector and Cartesian equations of the line that passes through the points and
Ans. Let and be the position vectors of the points A and B respectively.
and
A vector along the line = = Position vector of point B – Position vector of point A
= = =
Vector equation of the line is
And another vector equation for the same line is =
Cartesian equation
Direction ratios of line AB are
Equation of the line is =
10.Find the angle between the following pairs of lines:
(i) and
(ii) and
Ans. (i)Equation of the first line is
Comparing with ,
and
(vector is the position vector of a point on line and is a vector along the line)
Again, equation of the second line is
Comparing with ,
and
(vector is the position vector of a point on line and is a vector along the line)
Let be the angle between these two lines, then
= =
(ii)Comparing the first and second equations with and resp.
and
Let be the angle between these two lines, then
= =
NCERT Solutions class 12 Maths Exercise 11.2
11.Find the angle between the following pair of lines:
(i) and
(ii) and
Ans. (i)Given: Equation of first line is
The direction ratios of this line i.e., a vector along the line is
= =
Nowequation of second line is
The direction ratios of this line i.e., a vector along the line is
= =
Let be the angle between these two lines, then
= =
(ii)Given: Equation of first line is
The direction ratios of this line i.e., a vector along the line is
= =
Nowequation of second line is
The direction ratios of this line i.e., a vector along the line is
= =
Let be the angle between these two lines, then
= =
NCERT Solutions class 12 Maths Exercise 11.2
12.Find the values of so that the lines and are at right angles.
Ans. Given: Equation of one line
Direction ratios of this line are
Again, equation of another line
Direction ratios of this line are
Since, these two lines are perpendicular.
Therefore,
NCERT Solutions class 12 Maths Exercise 11.2
13.Show that the lines and are perpendicular to each other.
Ans. Equation of one line
Direction ratios of this line are =
Again equation of another line
Direction ratios of this line are 1, 2, 3 =
Now = =
Hence, the given two lines are perpendicular to each other.
NCERT Solutions class 12 Maths Exercise 11.2
14.Find the shortest distance between the lines and
Ans. Comparing the given equations with and , we get
and
Since, the shortest distance between the two skew lines is given by
……….(i)
Here,
Putting these values in eq. (i),
Shortest distance
NCERT Solutions class 12 Maths Exercise 11.2
15.Find the shortest distance between the lines and .
Ans. Equation of one line is
Comparing this equation with , we have
Again equation of another line is
Comparing this equation with , we have
=
Expanding by first row = =
And
= = =
Length of shortest distance =
= (numerically)
=
NCERT Solutions class 12 Maths Exercise 11.2
16.Find the shortest distance between the lines whose vector equations are
and
Ans. Equation of the first line is
Comparing this equation with ,
and
Again equation of second line
Comparing this equation with ,
and
Now shortest distance = ……….(i)
Here
Putting these values in eq. (i),
Shortest distance
NCERT Solutions class 12 Maths Exercise 11.2
17.Find the shortest distance between the lines whose vector equations are
and
Ans. Equation of first line is
= =
Comparing this equation with ,
Equation of second line is
= =
Comparing this equation with ,
Now Shortest distance = ……….(i)
Here
Putting these values in eq. (i),
Shortest distance
NCERT Solutions class 12 Maths Exercise 11.2
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